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Planck’s hypothesis, and Einstein’s photon theory. Contents: Hubris at the turn of the century Black Body radiation The problem with black body radiation.

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Presentation on theme: "Planck’s hypothesis, and Einstein’s photon theory. Contents: Hubris at the turn of the century Black Body radiation The problem with black body radiation."— Presentation transcript:

1 Planck’s hypothesis, and Einstein’s photon theory. Contents: Hubris at the turn of the century Black Body radiation The problem with black body radiation Planck’s hypothesis Einstein’s corpuscular light theory Photons : Example 1 | Example 2Example Example 2 Whiteboards

2 Hubris TOC 1900 +/- 10. The end of physics Tricky bits Motion of the earth with respect to “ether” (Einsteinian relativity) Black body radiation (Quantum mechanics)

3 Black Body radiation TOC Radiation given off by hot stuff

4 Black Body radiation TOC The problem fig 27-5

5 Black Body radiation TOC Planck’s solution Planck proposes a quantum hypothesis E min = hf h = Planck’s constant = 6.626 x 10 -34 Js f = frequency of oscillations (Hz, s -1 ) E = nhf, n = 1,2,3,... Hypothesis fits data exactly. Planck thinks it’s just math, not reality

6 Einstein’s photon theory TOC Einstein: Reality is quantum Radiation is also quantized Photons = corpuscular theory E = hf v = f E = Photon energy (Joules) v = c = speed of light = 3.00 x 10 8 m/s f = frequency (Hz) = wavelength (m)

7 TOC E = hf v = f E = Photon energy (Joules) v = c = speed of light = 3.00 x 10 8 m/s f = frequency (Hz) = wavelength (m) Example 1: What is the energy of a 460 nm photon? v = f, c = f, f = c/ E = hf = hc/

8 TOC E = hf v = f E = Photon energy (Joules) v = c = speed of light = 3.00 x 10 8 m/s f = frequency (Hz) = wavelength (m) Example 2: A photon has an energy of 13 eV. What is its wavelength? (Remember V = W/q, and 1 eV is one electron moved through 1 volt) E (in Joules) = (13 eV)(1.602 x 10 -19 J/eV) c = f, = c/f E = hf, f = E/h = c/f = hc/E

9 Whiteboards: Photons 11 | 2 | 3 | 4234 TOC

10 4.36 x 10 -19 J W E = hf = (6.626 x 10 -34 Js)(6.58 x 10 14 s -1 ) = 4.36 x 10 -19 J What is the energy of a photon with a frequency of 6.58 x 10 14 Hz?

11 8.23 x 10 15 Hz, 36.5 nm W E = hf f = E/h = (5.45 x 10 -18 J)/(6.626 x 10 -34 Js) = 8.23 x 10 15 Hz v = f, = v/f = (3.00 x 10 8 m/s)/(8.23 x 10 15 Hz) = 36.5 nm What is the frequency of a photon with an energy of 5.45 x 10 -18 J? What is its wavelength?

12 6.33 x 10 -19 J, 3.95 eV W E = hf = hc/ 1eV = 1.602 x 10 -19 J E = hc/ = (6.626 x 10 -34 Js)(3.00 x 10 8 m/s)/(3.14 x 10 -9 m) = 6.33 x 10 -19 J E = (6.33 x 10 -19 J)/(1.602 x 10 -19 J/eV) = 3.95 eV What is the energy in Joules of a 314 nm photon? What is that energy in eV? (2)

13 206 nm W E = hf = hc/ 1eV = 1.602 x 10 -19 J E = (6.02 eV)(1.602 x 10 -19 J/eV) = 9.64 x 10 -19 J E = hc/, = hc/E = (6.626 x 10 -34 Js)(3.00 x 10 8 m/s)/(9.64 x 10 -19 J) = 2.06 x 10 -7 m = 206 nm (nm = 1 x 10 -9 m) A photon has an energy of 6.02 eV. What is its wavelength? (answer in nm) (2)

14 9.36 x 10 17 photons/sec W E = hf = hc/ In one second, a 300 mW laser emits photons with a total energy of.300 J E = hc/, = (6.626 x 10 -34 Js)(3.00 x 10 8 m/s)/(620. x 10 -9 m) = 3.20613 x 10 -19 J (per photon) # photons = (.300 J/s)/(3.20613 x 10 -19 J/photon) = 9.36 x 10 17 photons/sec Hey, that’s a lot! How many photons per second stream from a 620. nm, 300. mW laser? (2)

15 Waves Photons Color Brightness Energy per photon changes E = hf X-Rays, UV, Gamma Wavelength Changes Amplitude Changes # of photons changes many = bright few = dim CCD Devices, High speed film big = red small = blue small = dim big = bright Light


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