2. Lesson 3: Bass Tournament Overview M.7.SP.3 You will informally assess the degree of visual overlap of two numerical data distributions with similar variabilites, measuring the difference between the centers by expressing it as a multiple of a measure of variability. CCSS.Math.Content.7.SP.B.3CCSS.Math.Content.7.SP.B.3

3. Upon the completion of this lesson you will be able to Tell how the measures of central tendencies are used to compare data. Describe what the degree of visual overlap and variants of the means tell you about the two sets of data. Analyze sets of data to determine the deviation and the absolute deviation from the mean and then the variability of the data sets.

4. Telling how the measures of central tendencies are used to compare data. What are the measures of central tendencies? – For this lesson we will be working with just the mean. Mean: Is the average of a set of data Find the mean given this set of data: 23, 12, 24, 18, and 23. 23+12+24+18+23 = 100 100 / 5 (the number data points) = 20; therefore the mean is 20.

5. Describe what the degree of visual overlap and variants of the means tell you about the two sets of data. When looking at the visual overlap of the two sets of data one can tell which set has a greater spread of data and where the two sets overlap. X XXXXX 12131415161718192021 XX XXXX 12131415161718192021

6. Analyze sets data to determine the deviation and the absolute deviation from the mean and then the variability of the data sets. Students in Group 1 Number of days they attended after school tutoring in Feb. and March Deviation from the mean (number – mean ) Absolute Deviation from the Mean |number – mean| 113-33 214-22 3151 41711 5 11 62044 The sum for this set is 13+14+15+17+17+20 = 96. The mean is 96 / 6 = 16. The sum of the absolute deviations is 3+2+1+1+1+4= 12 The mean of the absolute deviation (MAD) is 12 / 6 = 2.

7. Analyze sets data to determine the deviation and the absolute deviation from the mean and then the variability of the data sets. Students in Group 2 Number of days they attended after school tutoring in Feb. and March Deviation from the mean (number – mean) Absolute Deviation from the Mean |number – mean| 112-3.53.5 215-0.50.5 3160.5 4160.5 5171.5 6171.5 The sum for this set is 12+15+16+16+17+17 = 93. The mean is 93 / 6 = 15.5. The mean of the absolute deviation is 3.5+0.5+0.5+0.5+1.5+1.5 = 8. The mean of the absolute deviation (MAD) is 1 and 1/3.

8. Analyze sets data to determine the deviation and the absolute deviation from the mean and then the variability of the data sets. Student s in Group 1 Number of days they attended after school tutoring in Feb. and March Deviation from the mean (number – mean) Absolute Deviation from the Mean |number – mean| 113-33 214-22 3151 41711 5 11 62044 Student s in Group 2 Number of days they attended after school tutoring in Feb. and March Deviation from the mean (number – mean) Absolute Deviation from the Mean |number – mean| 112-3.53.5 215-0.50.5 3160.5 4160.5 5171.5 6171.5 Mean = 16 and MAD = 2Mean = 15.5 and MAD = 1 and 1/3 ___________[________|_______]__________________ 12 13 14 15 16 17 18 19 20 21 One standard deviation Mean __________[___ _|___ ]_______________________ 12 13 14 15 16 17 18 19 20 21 One standard deviation Mean

9. Activities in this Lesson A fishing tournament simulation where you will be collecting and analyzing the data. (Recording results to then save and/or print.) Activity called Celebrating Differences where you will be collecting and analyzing the data. Homework worksheet where you will be reviewing measures of central tendencies and analyzing the sets of data.