1. Modular 11 Ch 7.1 to 7.2 Part I

2. Ch 7.1 Uniform and Normal Distribution Recall: Discrete random variable probability distribution For a continued random variable the probability of observing one particular value is zero. Special case: Binomial distribution i.e. Finding the probability of obtaining success in independent trials of a binomial experiment is calculated by plugging the value of into the binomial formula as shown below : Objective A : Uniform Distribution Continuous Random variable A1. Introduction

3. We can only compute probability over an interval of values. Continuous Probability Distribution Since and for a continuous random variable, To find probabilities for continuous random variables, we use probability density functions.

4. Two common types of continuous random variable probability distribution : Uniform distribution Normal distribution.

5. Objective A : Uniform Distribution Note : The area under a probability density function is 1. Area of rectangle = Height x Width 1 = Height x Height = for a uniform distribution Ch 7.1 Uniform and Normal Distribution A2. Uniform Distribution

6. Example 1 : A continuous random variable is uniformly distributed with. (a) Draw a graph of the uniform density function. Area of rectangle = Height x Width 1 = Height x Height = =

7. (b) What is ? Area of rectangle = Height x Width (c) What is ? Area of rectangle = Height x Width

8. Ch 7.1 Uniform and Normal Distribution Objective A : Uniform Distribution Objective B : Normal distribution Ch 7.2 Applications of the Normal Distribution Objective A : Area under the Standard Normal Distribution

9. Objective B : Normal distribution – Bell-shaped Curve Ch 7.1 Uniform and Normal Distribution

11. Example 1: Graph of a normal curve is given. Use the graph to identify the value of and.

12. (b) Shade the region that represents the proportion of refrigerator that lasts for more than 17 years. (a) Draw a normal curve and the parameters labeled. Example 2: The lives of refrigerator are normally distributed with mean years and standard deviation years.

13. (c) Suppose the area under the normal curve to the right = 17 is 0.1151. Provide two interpretations of this result. 11.51% of all refrigerators are kept for at least 17 years. – the probability that a randomly selected individual from the population will have the characteristic described by the interval of values. The probability that a randomly selected refrigerator will be kept for at least 17 years is 11.51%. Notation: The area under the normal curve for any interval of values of the random variable represent either: – the proportions of the population with the characteristic described by the interval of values.

14. Ch 7.1 Uniform and Normal Distribution Objective A : Uniform Distribution Objective B : Normal distribution Ch 7.2 Applications of the Normal Distribution Objective A : Area under the Standard Normal Distribution

15. Ch 7.2 Applications of the Normal Distribution The standard normal distribution – Bell shaped curve – and. The random variable for the standard normal distribution is. Use the table (Table V) to find the area under the standard normal distribution. Each value in the body of the table is a cumulative area from the left up to a specific score. Objective A : Area under the Standard Normal Distribution

16. (a) what is the area to the right of ? (b) what is the area to the left of ? Probability is the area under the curve over an interval. The total area under the normal curve is 1. Under the standard normal distribution,

17. From Table V Example 1 : Determine the area under the standard normal curve. (a) that lies to the left of -1.38. (b) that lies to the right of 0.56. From Table V Area under the whole standard normal distribution is 1. Table V only provides area to the left of = 0.56.

18. (c) that lies in between 1.85 and 2.47. From Table V