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Bellwork: Graph each line: 1. 3x – y = 6 2. Y = -1/2 x + 3 Y = -2
If f(x) = 3x2 – 9, find each. 4. f(-2) f(3) f(4a) Algebra II
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Evaluating, Graphing, and Writing Piecewise Functions
Algebra II
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Piecewise Functions A combination of equations each corresponding to a given domain. Algebra II
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Example 1 f(x)= { 2x2 – 2 if x < 1 x + 4 if x ≥ 1 Evaluate each.
= (3) + 4 = 7 = 2(-4)2 – 2 = 2(16) – 2 = 30 = (1) + 4 = 5 Algebra II
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Example 2 x − 1 if x ≤ -1 f(x)= { (x − 3)2 if x > -1 Evaluate each.
= (-3) − 1 = -4 = (-1) − 1 = -2 = ((2) – 3)2 = (-1)2 = 1 Algebra II
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Example 3 g(x)= { 3x – 2 if x < -3 4 if -3 ≤ x < 5
Evaluate each. 1. g(5) 2. g(-2) 3. g(-8) = 2(5)2 – 3 = 2(25) – 3 = 47 = 4 = 3(-8) – 2 = -24 – 2 = -26 Algebra II
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Find each. f(½) f(2) f(-5) -3/2 9 -10 4. g(½) 5. g(0) 6. g(-1) 3 2
2x if x < -2 x – if -2 ≤ x < 2 2x if x ≥ 2 f(x)= { x + 3 if x < ½ 2x – 1 if x ≥ ½ g(x)= { Evaluate each piecewise function for the given values. f(½) f(2) f(-5) -3/2 9 -10 4. g(½) 5. g(0) 6. g(-1) 3 2 Algebra II
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Graphing: Example 1 f(x)= { x – 3 if x < 2 -½x + 1 if x ≥ 2
Graph the piecewise function: f(x)= { x – 3 if x < 2 -½x + 1 if x ≥ 2 x – 3 if x < 2 -½x + 1 if x ≥ 2 Algebra II
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Graphing: Example 2 f(x)= { 3x + 1 if x ≤ -1 x + 2 if x > -1
Graph the piecewise function: f(x)= { 3x + 1 if x ≤ -1 x + 2 if x > -1 3x + 1 if x ≤ -1 x + 2 if x > -1 Algebra II
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Graphing: Example 3 f(x)= { -2x if x < -2 ⅔x – 1 if x ≥ -2
Graph the piecewise function: f(x)= { -2x if x < -2 ⅔x – 1 if x ≥ -2 -2x if x < -2 ⅔x – 1 if x ≥ -2 Algebra II
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Graphing: Example 4 f(x)= { -3 if x < 0 -x – 1 if x ≥ 0
Graph the piecewise function: f(x)= { if x < 0 -x – 1 if x ≥ 0 if x < 0 -x – 1 if x ≥ 0 Algebra II
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Graphing: Example 5 f(x)= { Graph the piecewise function:
2x – 1 if x < -2 if -2 ≤ x ≤ 2 -¼x if x > 2 2x – 1 if x < -2 if -2 ≤ x ≤ 2 -¼x if x > 2 Algebra II
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Find each. Graph: Evaluate each given the piece-wise function: f(x)={
1/3x + 1 if x < -3 3x if -3 ≤ x < 2 if x > 2 4x if x < -3 3x – 2 if -3 ≤ x < 5 – if x ≥ 5 f(x)= { Algebra II
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Writing a Piecewise Function
Write the equation for each piece of the function Write the domain for each piece of the function use inequality notation to represent the domain in each piece Algebra II
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function that is graphed.
Example 1 Write the piecewise function that is graphed. (3 – 1) = -2 = -2 (-3 + 2) y – 1 = -2(x + 2) y = 2x – 3 (-5 + 4) = -1 (2 + 1) y + 4 = -⅓(x + 1) y = -⅓x – 13/3 f(x) = { 2x – 3 if x ≤ -1 -⅓x – 13/3 if x > -1 Algebra II
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function that is graphed.
Example 2 Write the piecewise function that is graphed. (6 – 5) = 1 (1 + 4) y – 6 = ⅕(x – 1) y = ⅕x + 29/5 (0 + 1) = 1 = 1 (3 – 2) y – 0 = 1(x + 3) y = x – 3 f(x) = { ⅕x + 29/5 if x < 1 x – 3 if x ≥ 1 Algebra II
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function that is graphed.
Example 3 Write the piecewise function that is graphed. (2 + 1) = 3 = -1 (-3 - 0) y + 1 = -1(x + 0) y = -x – 1 (2 – 0) = 2 = 2 (1 – 0) y – 0 = 2(x + 0) y = 2x f(x) = { -x – 1 if x ≤ 0 2x if x > 0 Algebra II
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function that is graphed.
Example 4 Write the piecewise function that is graphed. (5 – 3) = 2 = 1 (-3 + 5) y – 5 = 1(x + 3) y = x + 8 Slope is 0 horizontal line (1 – 0) = 1 = -½ (1 – 3) y = 3 y – 0 = -½(x – 3) y = -½x + 3/2 f(x) = { x + 8 if x < -3 if -3 ≤ x < 1 -½x + 3/2 if x ≥ 1 Algebra II
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Closure: Graph the piece-wise function:
Write a piece-wise function for this graph: f(x) = { x + 8 if x < -3 if -3 ≤ x < 1 -½x + 3/2 if x ≥ 1 Algebra II
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