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500 400 300 200 100 Equilibrium Rate Constant Integrated Rate Law Activation Energy Reaction Mechanisms Rate Laws
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A reaction has the rate law, Rate = k[A][B] 2. What is the overall order for the reaction? Third Order Overall Return
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A reaction has the rate law, rate = k[A][B] 2. If the concentration of both A and B are doubled, what happens to the rate? Increases by a factor of 8. Return Return
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The equation, 2A + 2B C + D, describes an elementary reaction which takes place in a single step. What is the rate law? Rate = k[A] 2 [B] 2 Return
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Based on the following equation, which of the following compounds would you expect to undergo the most change in concentration in a given amount of time? 2NH 3 N 2 + 3H 2 H2H2 Return
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For the reaction, 2XO + O 2 2XO 2, the following data was obtained. What is the rate law for the reaction? Trial [XO] [O2] rate 1 0.010 0.010 2.5 2 0.010 0.020 5.0 3 0.030 0.020 45.0 Rate = k [XO] 2 [O 2 ] Return
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The reaction: A + 3B D + F was studied and the following mechanism was determined A + B ↔ C (fast) C + B D + E (slow) E + B F (very fast) Which step is the rate determining step? The second step (slow step) Return Return
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Suppose the reaction: A + B D followed the mechanism A + B ↔ C (fast) C D (slow) What is the rate law for the reaction? Rate = k[A][B] Return
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The reaction A + 3B D + F was followed and the following mechanism was determined: A + B ↔ C (fast) C + B D + E (slow) E + B F (very fast) Identify the intermediates. C and E Return
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The reaction A +3B D + F was studied and the mechanism was determined to be: A + B ↔ C (fast) C + B D + E (slow) E + B F (very fast) What is the rate law? Rate = k[A][B] 2 Return Return
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The decomposition of H 2 O 2 is determined to occur by the following mechanism: H 2 O 2 + I - H 2 O + IO - (slow) H 2 O 2 + IO - H 2 O + O 2 + I - (fast) What is the overall reaction? 2H 2 O 2 H 2 O + O 2 Return Return
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How does a catalyst alter the rate of a chemical reaction? Lowers the activation energy (provides an alternative pathway) Return
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For a one step reaction, the activation energy for the forward reaction is 40 kJ/mol and the enthalpy of reaction is -20 kJ/mole. Which reaction is slower; the forward or the reverse? The reverse reaction is slower Return Return
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According to the collision theory, what two conditions must be met in order for a reaction to occur? Reactants must possess a minimum amount of energy and the collisions must occur with the correct orientation Return
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How can the slope of a plot of ln(k) vs 1/T for a reaction be used to determine the activation energy? By multiplying by –R (-8.314) Return Return
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For a one step reaction the activation energy is 40 kJ/mol and the enthalpy of reaction is 20 kJ/mol. What is the activation energy of the reverse reaction? 20 kJ/mol Return
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The following reaction was studied: A B + C. The graph of 1/[A] vs time gave a straight line. What is the order of the reaction with respect to A? 2 nd order Return Return
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Given a reaction, 2A + B P, for which the observed rate law is rate = k [A], what is the integrated rate law? ln[A] = -kt + ln[A] o Return Return
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In a first order reaction, what fraction of the material will remain after 4 half lives? 1/16 Return
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A first order reaction has a rate constant of 0.00318 min -1. What is the half life of the reaction? 21.8 minutes Return Return
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A graph of [A] vs time gave a straight line. How does doubling the concentration of A affect the rate of the reaction? It has no affect Return
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How does changing the concentration affect the rate constant? It has no affect Return Return
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How does increasing the temperature affect the rate and the rate constant? It increases both the rate constant and the rate Return
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What is the unit for the rate constant in a reaction that is 2 nd order overall? L/mol s Return Return
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In a zero order rate law, what units must the rate concept possess? Mol/L time Return Return
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A rate constant has the units s -1. Doubling the concentration would have what affect on the overall rate of reaction? It would double the rate Return
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What factors affect the value of Keq? Temperature and nature of reactants Return Return
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How does a catalyst affect the value of Keq? It has no effect Return
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If K>1, what does that indicate about the equilibrium position? The concentration of products is greater than the concentration of reactants at equilibrium Return Return
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Increasing the temperature increases the value of Keq. Is the reaction endothermic or endothermic? endothermic Return
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According to the equation: 3H 2 (g) + N 2 (g) 2NH 3 (g), if the volume of the reaction chamber increases, will the forward or reverse reaction be favored? Reverse reaction Return
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