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In your own words: What is a limit?
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Evaluating Limits Analytically
Evaluate a limit using properties of limits Develop and use a strategy or finding limits Evaluate a limit using dividing out and rationalizing techniques Evaluate a limit using the Squeeze Theorem
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Some Basic Limits Let π and π be real numbers and let π be a positive integer. lim π₯βπ π =π lim π₯βπ π₯ =π lim π₯βπ π₯ π = π π
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Properties of Limits Let π and π be real numbers, let π be a positive integer, and let π and π be functions with the following limits lim π₯βπ π π₯ =πΏ and lim π₯βπ π π₯ =πΎ. Scalar Multiple lim π₯βπ ππ π₯ =ππΏ Sum or Difference lim π₯βπ π π₯ Β±π π₯ =πΏΒ±πΎ Product lim π₯βπ π π₯ π π₯ =πΏπΎ Quotient lim π₯βπ π π₯ π π₯ = πΏ πΎ πΎβ 0 Power lim π₯βπ π π₯ π = πΏ π
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lim π₯β3 (2 π₯ 3 +3π₯β4)
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Limits of Polynomial and Rational functions
If π is a polynomial function and π is a real number, then lim π₯βπ π π₯ =π π . If π is a rational function given by π π₯ = π π₯ π π₯ and π is a real number such that π(π)β 0, then lim π₯βπ π π₯ =π π = π π π π .
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The Limit of a Function Involving a Radical
Let π be a positive integer. The following limit is valid for all π if π is odd, and is valid for π>0 if π is even. lim π₯βπ π π₯ = π π
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The Limit of a Composite Function
If π and π are functions such that lim π₯βπ π π₯ =πΏ and lim π₯βπΏ π π₯ =π πΏ , then lim π₯βπ π π π₯ =π lim π₯βπ π π₯ =π πΏ .
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Soβ¦ Hopefully youβve figured out by now, to find the limit, just put the π value into the equationβ¦ Thatβs it. It works for all trig functions too. So, like, lim π₯βπ sin π₯ = sin π . Iβm not going to make you copy all of them down, unless you want to.
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Functions That Agree at All But One Point
Let π be a real number and let π π₯ =π π₯ for all π₯β π in an open interval containing π. If the limit of π π₯ as π₯ approaches π exists, then the limit of π π₯ also exists and lim π₯βπ π π₯ = lim π₯βπ π π₯ .
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Functions That Agree at All But One Point - Simplified
This is a fancy way of saying that you can manipulate a function, without changing it, to find a value that, otherwise, wouldnβt exist.
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lim π₯β4 π₯ 2 βπ₯β12 π₯β4
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lim π₯β0 π₯β2 +2 π₯
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The Squeeze Theorem If β π₯ β€π π₯ β€π π₯ for all π₯ in an open interval containing π, except possibly at π itself, and if lim π₯βπ β π₯ = lim π₯βπ π π₯ =πΏ then lim π₯βπ π π₯ =πΏ.
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lim π₯β0 sin π₯ π₯
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lim π₯β0 1β cos π₯ π₯
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