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Physics 223 28. Direct Current (DC) Circuits 28.1 EMF and Voltage 28.2 Resistors in Series and Parallel 28.3 Kirchhoff’s Rules 28.4 RC Circuit 28.5 Ammeters.

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Presentation on theme: "Physics 223 28. Direct Current (DC) Circuits 28.1 EMF and Voltage 28.2 Resistors in Series and Parallel 28.3 Kirchhoff’s Rules 28.4 RC Circuit 28.5 Ammeters."— Presentation transcript:

1

2 Physics 223

3 28. Direct Current (DC) Circuits 28.1 EMF and Voltage 28.2 Resistors in Series and Parallel 28.3 Kirchhoff’s Rules 28.4 RC Circuit 28.5 Ammeters and Voltmeters 28.6 Household Wiring

4 Electric Battery + - The battery converts chemical energy to electrical energy. It is a source of potential difference or voltage. This is used to drive electrons “downhill” through a conductor (resistor)

5 Electric Current and Ohm’s Law I = Q / t current = charge / time V = I R voltage = current x resistance

6 28.1 EMF and Voltage V = ɛ - I r r is the “hidden” internal resistance of the battery.

7 28.2 Bulbs in Series and Parallel A.L1 and L2 are in series B.L1 and L2 are in parallel C.L3 and L4 are in series D.None of the above L3 L4 L1L2

8 Bulbs in Series and Parallel L1 and L2 are in series and L3 and L4 are in parallel L3 L4 L1L2

9 Bulbs in Series and Parallel A.I 1 = I 2 B.V 1 = V 2 C. I 3 = I 4 D. None of the above L3 L4 L1L2

10 Bulbs in Series and Parallel Series Parallel I 1 = I 2 V 3 = V 4 L3 L4 L1L2

11 Example 28.1... Series Circuit Calculate the current flowing through the resistors voltage across the resistors power dissipation in the resistors R1 = 3ΩR2 = 6Ω V = 12V

12 Solution 28.1... Series Circuit R eq = R 1 + R 2 R1 = 3ΩR2 = 6Ω V = 12V R eq = 9Ω V = 12V I = 12/9 =4/3 A V1 = 4/3 x 3 = 4 V V2 = 4/3 x 6 = 8 V

13 Example 28.2... Parallel Circuit 12V R1 =6 Ω R2 = 3 Ω Calculate the current flowing through the resistors voltage across the resistors power dissipation in the resistors

14 Solution 28.2... Parallel Circuit 12V R1 =6 Ω R2 = 3 Ω 1/ R eq = 1/R 1 + 1/R 2 R eq =2Ω V = 12V I 1 = 12/6 =2 A I 2 = 12/3 =4 A

15 Example 28.3... Series /Parallel Combo Special! R1 =3Ω R2 =6Ω R3 =4Ω V =12V Calculate the current flowing through the resistors voltage across the resistors power dissipation in the resistors

16 Solution 28.3... Series /Parallel Combo Special! R1 =3Ω R2 =6Ω R3 =4Ω V =12V Req =2Ω R3 =4Ω V =12V I eq = 12/6 =2A V eq = 2 x2 = 4V V 1 = V 2 = 4V I 1 = 4/3 A and I 2 = 2/3 A

17 28.3 Kirchhoff’s Rules  I = 0 (Junction)  V = 0 (Loop)

18 RC Charging Circuit V C = V 0 (1 - e -t /RC ) V R = V 0 e -t /RC V0V0 VRVR t VCVC

19 RC Discharging Circuit V C = V 0 e -t /RC V R = V 0 e -t /RC VRVR t =VC=VC

20 28.5 Ammeters and Voltmeters A V Ammeter measures current Ammeter is connected in series Ammeter has a LOW resistance Ammeter is tricky to hook up Voltmeter measures voltage Voltmeter is connected in parallel Voltmeter has a HIGH resistance Voltmeter is easy to hook up

21 That’s all folks!


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