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1 EENG 2710 Chapter 1 Number Systems and Codes
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2 Chapter 1 Homework 1.1c, 1.2c, 1.3c, 1.4e, 1.5e, 1.6c, 1.7e, 1.8a, 1.9a, 1.10b, 1.13a, 1.19
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3 Number Systems
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4 Binary Number System Uses two digits, 0 and 1. Represents any number using the positional notation.
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5 Positional Notation The value of a digit depends on its placement within a number. In base 10, the positional values are (starting to the left of the decimal) – 1 (10 0 ), 10 (10 1 ), 100 (10 2 ), 1000 (10 3 ), etc. In base 2, the positional values are 1 (2 0 ), 2 (2 1 ), 4 (2 2 ), 8 (2 3 ), etc.
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6 Binary Weights 2727 2626 2525 2424 23232 2121 2020 1286432168421
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7 Fractional Binary Weights 2 -1 2 -2 2 -3 2 -4 ½¼1/81/16 0.50.250.1250.0625
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8 Bit Shorthand for binary digit, a logic 0 or 1. The most significant bit (MSB) is the leftmost bit of a binary number. The least significant bit (LSB) is the rightmost bit of a binary number.
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9 Binary Inputs Digital circuits operate by accepting logic levels (0,1) at their input(s). The corresponding output(s) logic level will change (0,1).
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10 Binary Inputs
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11 4-Input Digital Circuit
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12 Base Conversions Methods Series substitution method Sum powers of 2 Radix method –Repeated Division –Repeated Multiplication
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13 Series Substitution Method (Binary to Decimal)
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14 Sum Powers of 2 (Decimal to Binary) Step 1: –Determine the largest power of 2 less than or equal to the number to be converted. – Place a 1 in that positional location. Convert 57 10 to binary 64 10 57 10 32 10
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15 Sum Powers of 2 Step 2: –Subtract the number found in Step 1 from the number to be converted. 57 – 32 = 25 –For the new number, determine if the next lowest power of 2 is less than or equal to that number. 25 – 16 = 9
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16 Sum Powers of 2 Step 3: –If the new power of two from Step 2 is larger, place a 0 in that positional location. –If the new value is less than or equal, place a 1 in that positional location.
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17 Sum Powers of 2 Step 4: –Repeat Steps 2 and 3 until there is nothing left to subtract. –All remaining bits are set to 0. 57 10 = 111001 2
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18 Radix Method (Repeated Division by 2) 46 10 = 101110 2
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19 Fractional Binary Numbers Radix point: –The generalized decimal point. The dividing line between positive and negative powers for positional multipliers. Binary point: –The radix point for binary numbers.
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20 Fractional Binary Values The value immediately to the right of the binary point is 2 –1 = 0.5. The next value to the right is 2 –2 = 0.25. The next value to the right is 2 –4 = 0.125, and so on.
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21 Series Substitution Method (Binary Fraction to Decimal Fraction)
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22 Radix Method for 0.2 10 to Binary (Repeated Multiplication by 2) Step 1:Multiply the decimal fraction by 2. Step 2: Integer part is 0 or 1 left of decimal point. 0.2 x 2 = 0.4 Integer part = 0 0.4 x 2 = 0.8 Integer part = 0 0.8 x 2 = 1.6 Integer part = 1 0.6 x 2 = 1.2 Integer part = 1 0.2 x 2 = 0.4 Integer part = 0 (stop 0011repeats) Read integer parts from top to bottom Therefore, 0.2 10 = 0.0011 0011 0011
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23 Hexadecimal Numbers Base 16 number system. Primarily used as a shorthand form of binary numbers.
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24 Counting in Hexadecimal Values range from 0 to F with the letters A to F used to represent the values 10 to 15 respectively. Positional multipliers are powers of 16: 16 0 = 1, 16 1 = 16, 16 2 = 256, etc.
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25 Hexadecimal vs. Decimal Numbers Decimal 0123456789101112131415 Hexadecimal 0123456789ABCDEF
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26 Counting In Hexadecimal 0,1,2,3,4,5,6,7,8,9,A,B,C,D,E,F 10,11,12,13,14,15,16,17,18,19,1A,1B,1C,1D,1E,1F 20,21,22,23,24,25,26,27,28,29,2A,2B,2C,2D,2E,2F 30,31,32,33,34,35,36,37,38,39,3A,3B,3C,3D,3E,3F
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27 Decimal-to-Hexadecimal Conversion ( Repeated division by 16) 31581 10 = 7B5DH
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28 Hex-Decimal-Binary Table HexDecimalBinaryHex (Cont) DecimalBinary 000000881000 110001991001 220010A101010 330011B111011 440100C121100 550101D131101 660110E141110 770111F151111
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29 Conversion Between Hexadecimal and Binary Each hexadecimal digit represents 4 binary bits. F D 6 9 1111 1101 0110 1001 FD69H = 1111110101101001 2
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30 Signed/Unsigned Binary Numbers Signed Binary Number: –A binary number of fixed length whose sign (+/–) is represented by one bit (usually MSB) and its magnitude by the remaining bits. Unsigned Binary Number: –A binary number of fixed length whose sign is not specified by a bit. All bits are magnitude and the sign is assumed +.
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31 Unsigned Binary Arithmetic Sum: –Result of an Addition Operation of two (or more) binary numbers (operands). Carry: –A digit (or bit) that is carried over to the next most significant bit during an n-Bit addition operation. The carry bit is a 1 if the result was too large to be expressed in n bits.
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32 Basic Rules (Unsigned)
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33 Basic Subtraction Basic Subtraction of x = a – b, with a = minuend, b = subtrahend, and x = difference or result. Requires a Borrow Bit if a < b. There are other forms of subtraction such as 2’s Complement Addition used by microprocessors (such as in a PC).
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34 Binary Subtraction with Borrow Examples
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35 Signed Binary Numbers Sign Bit: –A bit (usually the MSB) that indicates whether a number is positive (= 0) or negative (= 1). Magnitude Bits: –The bits of a signed binary number that tell how large it is in value.
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36 Signed Binary Numbers True-Magnitude Form: –A form of signed binary whose magnitude bits are the TRUE binary form (not complements). 1’s Complement: –A form of signed binary in which negative numbers are created by complementing all bits. 2’s Complement: –A form of signed binary in which the negative numbers are created by complementing all the bits and adding a 1 (1’s Complement + 1).
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37 True-Magnitude Form 5-Bit Numbers Negative Sign (S = 1) +25 = 011001 (Note sign bit (MSB) Sign = 0) –25 = 111001 (Same as +25 with sign = 1) +12 = 001100 –12 = 101100
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38 1’s Complement Form 8-Bit 1’s Complement Negative (S = 1) +57 = 00111001 –57 = 11000110 (All Bits Inverted) +72 = 01001000 –72 = 10110111
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39 2’s Complement Form 57 = 0011 1001 -57 = 1100 0110 + 1 1100 0111
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40 Signed Binary Addition (8-Bit) Signed Addition Positive (S = 0) +30 = 00011110 +75 = 01001011 105 01101001
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41 Subtraction with 1’s Complement Add the 1’s Complement and then Carry. Uses an End around carry addition method. (80 – 65)
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42 2’s Complement Subtraction Add 2’s Complement to Minuend. Discord Carry Bit From Results (80 – 65)
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43 2’s Complement Subtraction 200 10 – 5 10 = 195 10 (Use 16 bit word) 200 10 = 0000000011001000 2 5 10 = 0000000000000101 2 -5 10 = 1111111111111010 2 = 1’s complement + 1 1111111111111011 2 0000000011001000 2 + 1111111111111011 2 10000000011000011 2 = 0000000011000011 2 = 195 10
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44 Negative Results If the True-Magnitude Form is used for subtraction, the results are incorrect. If the result is from 1’s or 2’s Complement and the result is negative (S = 1), the magnitude is found by taking the complement of the result.
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45 Negative Result Example Thus, = -15 10
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46 More Binary Addition
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47 More Binary Subtraction
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48 Binary Multiplication
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49 Binary Division
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50 Range of Signed Numbers Range of Positive Numbers is 0 to 2 n – 1 for a number with n magnitude bits. Range of Negative Numbers is –1 to –2 n for a number with n magnitude bits. 8-Bit Example: 8-Bit Number Range is –2 n x +2 n – 1 or –128 to +127
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51 Sign Bit Overflow Overflow: –An erroneous carry into the sign bit of a signed binary number –Results from a sum or difference that is larger than can be represented by the magnitude bits. Results in a False Positive or False Negative Number.
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52 False Negative Overflow Addition of two 8-Bit Positive Numbers: Two positive numbers added with a result greater than the range of +127 for 8-bit numbers causes an overflow.
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53 False Positive Overflow Addition of two 8-Bit Negative Numbers: Two Negative numbers were added to produce a False Positive Result due to overflowing the negative range of 8-bit numbers (0 to –128).
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54 Hexadecimal Addition Similar to decimal addition with a range of digits of 0 to 9 and A to F. Examples: F + 1 = 10 F + F = 1E F + F + 1 = 1F
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55 Hexadecimal Addition For sums greater than 15, subtract 16 and carry 1 to the next position.
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56 Hexadecimal Subtraction
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57 Hexadecimal Subtraction 2F00H – 4000H Convert 4000H to hexadecimal equivalent of 2’s complement: FFFF 4000 BFFF + 1 C000 Add numbers: 2F00 + C000 EF00H
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58 Hexadecimal Subtraction 2F00H – 4000H a.Converting 4000 to binary = 0100 0000 0000 0000 b.Take 1’s complement = 1011 1111 1111 1111 c.Take 2’s complement = +1 +1 +1 +1 1100 0000 0000 0000 d.Change to Hexadecimal = C000H e.Add numbers: 2F00 + C000 EF00H
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59 More Hexadecimal Addition
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60 More Hexadecimal Subtraction
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61 Hexadecimal Multiplication
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62 Hexadecimal Division
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63 Octal Addition
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64 Octal Subtraction
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65 Octal Multiplication
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66 Octal Division
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67 Excess 8 code
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68 Floating-point Number Formats
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69 Developing a Floating Point number If n = 1101.0101, convert n to a floating point number. n = (0.11010101) x 2 4 The mantissa M = 0.11010101 2sm The exponent E = 011 + 10000 = 10011 2 E = (1, 0011) exess 16 Combining M & E: N = 0, 1, 0011, 11010101) fp
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70 BCD Codes BCD Code (Binary-Coded Decimal): A code used to represent each decimal digit of a number by a 4-Bit Binary Value. Valid Digits for 0 to 9 are 0000 to 1001. –The binary codes 1010 to 1111 are invalid Called an 8421 Code due to the decimal weight of each bit position.
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71 BCD Examples Each digit is a 4-Bit Binary group: (84) 10 = 1000 0100 (4987) 10 = 0100 1001 1000 0111 BCD
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72 Gray Code A binary code that progresses so that only one bit changes between two successive codes. 000 001 011 010 110 111 101 100
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73 How to build a 4-bit Gray Code Table ( A binary code that progresses so that only one bit changes between two successive codes.)
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74 4-bit Gray Code Table
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75 A Gray Code Disk
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76 ASCII Code American Standard Code for Information Interchange. A seven-bit alphanumeric code used to represent text letters, numerals, punctuation, and special controls. An expanded 8-bit form is becoming more widespread.
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77 ASCII Code
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78 Error Detection and Correction Codes
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79 Error Detection and Correction Codes Definitions Parity Codes –Odd parity –Even parity Hamming Codes –Code 1 –Code 2
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80 Error Detection and Correction Codes Definitions Error – an incorrect value of one or more binary bits. Single Error - an incorrect value of one binary bits. Multiple Error - incorrect values of many binary bits. Distance between code words – d –Code word I = 01101100 –Code word J = 11000100 – d (I,J) =3
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81 Definitions Continued d min – minimum distance between two code word –If code provides t error correction plus detection of s additional errors, then 2t + s + 1 d min –At least d min errors are needed to transform one code word to another –Less than d min errors, then a detectable non-code word results. Thus, if the non-code word is closer to a valid code word, then the original code word can be deduced and the error can be corrected.
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82 Parity Basics Parity: A digital system that checks for errors in a n-Bit Binary Number or Code. Even Parity: A parity system that requires the binary number and the parity bit to have an even # of 1s. Odd Parity: A parity system that requires the binary number and the parity bit to have an Odd # of 1s.
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83 Parity Basics Parity Bit: A bit appended on the end of a binary number or code to make the # of 1s odd or even depending on the type of parity in the system. Parity is used in transmitting and receiving data by devices in a PC called UARTs, that are on the COM Port. UART = Universal asynchronous Receiver/Transmitter
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84 Parity Basics
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85 Parity Calculation N 1 = 0110110: –It has four 1s (an even number). –If Parity is ODD, the Parity Bit = 1 to make it an odd number (5). N = 1110110 –If Parity is EVEN, the Parity Bit = 0 to keep it an even number (4). N = 0110110
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86 Hamming Code Table
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87 Hamming Code Problem Error Word = 1100110, Use Hamming Code 1 to determine the code word. Code word
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