1. Centripetal Force and Acceleration
Circular Motion
Centripetal Force and Acceleration

2. Tangential Velocity Tangential Velocity (Vt)- object’s speed along
an imaginary line that is drawn tangent to the circular path
Depends on distance from the object to the center of the circular path
When the tangential speed is constant then the motion is described as uniform circular motion

4. Tangential Velocity r=radius of the circle
Vt=2πr/T
r=radius of the circle
T=Period (amount of time to complete one circle)

5. Example
A plane makes a complete circle with a radius of 3622 m in 2.10 min. What is the speed of the plane?
180 m/s

6. Centripetal Acceleration
When an object is moving in a circular path, the direction changes
If the object has a constant SPEED, Acceleration is due to the direction changing
This is called centripetal acceleration

7. Centripetal Acceleration
Centripetal acceleration is always directed towards the center of the circle
Centripetal=center seeking

8. Centripetal Acceleration

9. Tangential Accleration
Centripetal acceleration results from change in direction
When the speed changes in a circle it is called tangential acceleration
Consider a car moving in a circle

10. Centripetal Force Remember!
When an object is accelerating there is a net force
If there is centripetal acceleration, there is a net force- Centripetal Force
This is not a new force
Net force that accelerates an object towards the center of a circle

11. Examples
If a mass is twirled in a circle, at the end of a string, the centripetal force is provided by the tension
When a car rounds a corner on a highway, the centripetal force is provided by friction
When the moon orbits the Earth, the centripetal force is provided by gravity

12. Centripetal Force Centripetal Force =mass x centripetal acceleration
Fc=mac
Substitute ac
Fc=m V2/r
Substitute Vt
Fc=m 4π2r/T2

13. Example- Standard
A 0.50 kg mass is whirled in a circle of radius m at 2.3 m/s. Calculate the centripetal force acting on the mass
13.2 N

14. Example-Honors
A 0.50 kg mass sits on a frictionless table and is attached to hanging weight. The 0.50 kg mass is whirled in a circle of radius 0.20 m at 2.3 m/s. Calculate the centripetal force acting on the mass .
Calculate the mass of the hanging weight
13.2 N
Fg=T=Fc=mg =m9.8
1.35 kg

15. Example
A car traveling at 14 m/s goes around an unbanked curve in the road that has a radius of 96 m. What is its centripetal acceleration?
What is the minimum coefficient of friction between the road and the car’s tires?
2.04 m/s2
Ff=Fc=mac μmg=mac μg=ac μ9.8= coefficient=.21

16. Clicker Question
Calculate the centripetal force acting on a 925 kg car as it rounds an unbanked curve with a radius of 75 m at a speed of 22 m/s.

17. Clicker Question
An amusement park ride has a radius of 2.8 m. If the time of one revolution of a rider is s, what is the speed of the rider?

18. Clicker Question
A 2.7x103 kg satellite orbits the Earth at a distance of 1.8x107 m from the Earth’s centre at a speed of 4.7x103 m/s. What force does the Earth exert on the satellite?

19. Clicker Question
. An object moves in a circle at a constant speed. Which of the following is not true of the object?
A. Its centripetal acceleration is constant.
B. Its tangential speed is constant.
C. Its velocity is constant.
D. A centripetal force acts on the object.

20. Clicker Question
A car traveling at 15 m/s on a flat surface turns in a circle with a radius of 25 m.
2. What is the centripetal acceleration of the car?
A. 2.4  10-2 m/s2
B m/s2
C. 9.0 m/s2
D. zero

21. Centrifugal Force
When a driver takes a sharp left turn, the passenger slides to the right of the car and into the door, Why?
Centrifugal=center-fleeing
Apparent force that causes a revolving or rotating object to move in a straight line
However-Newton’s first law states- an object in motion will stay in motion until a force acts on it
Centrifugal force does not really exist!

22. Describing Motion
What happens when centripetal force disappears? Where does the object go?
A ball that is on the end of a string is whirled in a vertical circular path.
If the string breaks at the position shown in (a), the ball will move vertically upward in free fall.
If the string breaks at the top of the ball’s path, as in (b), the ball will move along a parabolic path.

23. Vertical Versus Horizontal
Draw a free body diagram of a mass moving in a vertical circle, when the object is at the top of the path and the bottom of the path
As with any object moving in a circle there is a net force acting on it towards the center of the circle
The net force is the centripetal force
At the top Fnet (Fc)=Ft +Fg
At the bottom Fnet (Fc)=Ft-Fg

24. Example
A 1.7 kg object is swung from the end of a 0.60 m string in a vertical circle. If the time of one revolution is 1.1 s, what is the tension in the string
A) at the top?
B) at the bottom?
Top- 17N
Bottom- 50 N

25. Constant Velocity
When you are trying to find the minimum speed of an object at the top of its circular arc we can use the equation
Fc=Fg so
The centripetal acceleration equals the acceleration due to gravity (ac=9.8 m/s/s) So
g=Vt2/r
V=√(gr)

26. Example
An object is swung in a vertical circle with a radius of 0.75 m. What is the minimum speed of the object at the top of the motion for the object to remain in circular motion?
2.7 m/s

27. Circular Motion
Gravitation

28. What is Gravity? The force that pulls us to the earth
It is much more than that
Gravity is the force that attracts two bodies that have mass and energy to each other
Newton discovered that gravity attracts any two objects depending on their masses and their distance apart

29. Gravity
The gravitational forces that two masses exert on each other are always equal in magnitude and are opposite in directions.
Newton’s Third Law

30. Gravity Is Proportional to the two masses
Is inversely proportional to the square of the distance between their center of mass
So if two objects are twice as far away from each what happens to the gravitational force by?
Fg=Gm1m2 r2
G=6.67 x N m2/kg2
M1= mass of the first object
M2= mass of the second object
r= distance between the two centers of mass
It gets reduced by 1/4

31. Example
Calculate the force of gravity between two 75 kg students if their centers of mass are 0.95 m apart
4.2 x N

32. Example 2
A satellite weighs 9000 N on Earth’s surface. How much does it weigh if its mass is tripled and its orbital radius is doubled?
Fg is the same thing as weight
Fg= 9000 N
Mass is on the top of the equation and the mass is proportional to the Fg, so the Fg goes up by a factor of 3
The radius is inversely proportional to the square of the distance, so if the radius is doubled then the Fg is reduced by a factor of ¼
So Fg X ¾ = 6750 N

33. Clicker Question
. Earth (m = 5.97  1024 kg) orbits the sun (m =  1030 kg) at a mean distance of 1.50  1011 m. What is the gravitational force of the sun on Earth? (G =  N•m2/kg2)
A  1032 N
B  1022 N
C  10–2 N
D  10–8 N

34. Clicker Question
Gravitational force F exists between point objects A and B separated by distance R. If the mass of A is doubled and distance R is tripled, what is the new gravitational force between A and B?
A) 9/2 F
B) 2/3 F
C) 2/9 F
D) 3/2 F

35. Common Misconception: Mass Versus Weight
Amount of matter
Constant everywhere
Gravitational attraction (Fg)
Changes depending on location

36. Clicker Question Which of the following statements is correct?
A. Mass and weight both vary with location.
B. Mass varies with location, but weight does not.
C. Weight varies with location, but mass does
not.
D. Neither mass nor weight varies with location.

37. Satellites
Are constantly “falling” when in orbit
They are in freefall

38. Gravitational Field
Gravity is an example of a field force (ie not a contact force)
A force that is exerted which has no direct contact
A field- an area of influence
Think about a campfire
As you approach it
As you increase the size

39. Gravitational Fields
Fields can be described as vectors or scalars, depends on what kind
Gravitational fields are field forces so..
They are vectors
Gravitational fields are represented by arrows, magnitude is represented by how many arrows are present

40. Gravitational Field Strength
Gravitational field strength=acceleration due to gravity
Recall Fg=mg
So…
g=Fg/m
g=acceleration due to gravity, gravitational field strength,
9.80m/s2 near the Earth’s surface
g varies with distance
g=Gm1 r2
Measured in N/kg, same as m/s2

41. Example
What is the gravitational field strength on the Earth’s surface of the moon? The mass of the moon is 7.35 x 1022 kg and the radius of the moon is 1.74 x 106 m
1.62 m/s2 or N/kg

42. Clicker Question
. Which of the following is a correct interpretation of the expression? A. Gravitational field strength changes with an object’s distance from Earth. B. Free-fall acceleration changes with an object’s distance from Earth. C. Free-fall acceleration is independent of the falling object’s mass. D. All of the above are correct interpretation

43. The Period of a Satellite
T=√(4π2r3) Gm
m refers to the mass of the center of the orbit

44. Example
A satellite orbits the Earth at a radius of 2.2 x 107 m. What is its orbital period, when the mass of the earth is 5.98 x 1024 kg. What is the speed of the satellite?
32500 s
4251 m/s