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Chapter 1 - Title Demo Week II. “Whoosh Bottle” Bottle, alcohol, match 2 effects –Detonation “whoosh’ thrust (methanol) –Burning Cone/ring of fire (propanol)

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Presentation on theme: "Chapter 1 - Title Demo Week II. “Whoosh Bottle” Bottle, alcohol, match 2 effects –Detonation “whoosh’ thrust (methanol) –Burning Cone/ring of fire (propanol)"— Presentation transcript:

1 Chapter 1 - Title Demo Week II

2 “Whoosh Bottle” Bottle, alcohol, match 2 effects –Detonation “whoosh’ thrust (methanol) –Burning Cone/ring of fire (propanol) Depends on v.p., –All burn if diluted Fortman et al, 1999; Campbel et al., 2001 methanol > ethanol > 2-propanol > propanol

3 Safety No glass –Shatters Use air, NOT oxygen Do not heat Pressurized –Avoid spray Excess liquid melts the bottle –Extinguish with cap Goggles and safety shield

4 Procedure Add wheels Jug MUST be dry Add 0.75 mL methanol Cap and slosh Wait 20 mins

5 Rockets (Making Water) Fuel HCl(aq) + Zn(s)  ZnCl 2 (aq) + H 2 (g) Ignition 2H 2 (g) + O 2 (g)  2H 2 O(l)

6 Calculation Atmosphere provides 1 O 2 molecule out of 5 we let in the bottle, Determine what ratio of H 2 to air in a 2L bottle will provide a 2:1 ratio of H 2 :O 2. Ratio O 2 : N 2 in air __ : __ Ratio of Hydrogen : Oxygen in our rocket required for complete combustion __ : __ Ratio of Hydrogen : Air in our rocket required for complete combustion __ : __ (a : b) __/__ : __/__ (divide by the total a+b) __% : __%

7 ff

8 Solution 2H 2 + O 2  2H 2 O 2 : 1 2 Need 2 hydrogen molecules for every oxygen molecule From air: 1 O 2 for every 5 molecules of air we let in Ratio of Hydrogen : Oxygen in our rocket required for complete combustion 2 : 1 Ratio of Hydrogen : Air in our rocket 2 : 5 2/7 : 5/7 30% : 70% [1] ~ 570 mL of H 2 and 1430 mL of air.


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