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A-9 18 D-9 6 F-9 10 D-7 9 A-7 20 A-5 15 C-5 6 E-5 28 E-3 10 F-7 7 F-5 14 F-3 20 B-3 8 A-1 4 C-1 5 A-6 15 The Problem…

Published byShanon Cox Modified over 9 years ago

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Presentation on theme: "A-9 18 D-9 6 F-9 10 D-7 9 A-7 20 A-5 15 C-5 6 E-5 28 E-3 10 F-7 7 F-5 14 F-3 20 B-3 8 A-1 4 C-1 5 A-6 15 The Problem…"— Presentation transcript:

1 A-9 18 D-9 6 F-9 10 D-7 9 A-7 20 A-5 15 C-5 6 E-5 28 E-3 10 F-7 7 F-5 14 F-3 20 B-3 8 A-1 4 C-1 5 A-6 15 The Problem…

2 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 C-5 6 A-6 15 F-5 14 F-3 20 E-5 28 E-5 28 A-5 15 E-3 10 B-3 8 A-1 4 C-1 5 Scheduling Activities #1 (Begin Gant Chart with late starts) 20 10 40503070 60 9010080

3 Move tasks for precedence and resource relationships. 20 10 40503070 60 9010080 Scheduling Activities #2 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 C-5 6 A-6 15 F-5 14 F-3 20 E-5 28 A-5 15 E-3 10 B-3 8 A-1 4 C-1 5 110

4 20 10 40503070 60 9010080 Choose a Critical Chain… CC = A1, C1, B3, C5, E5, F5, F7, A7, A9 (110 days) A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 A-6 15 F-5 14 F-3 20 E-5 28 A-5 15 E-3 10 B-3 8 110 C-5 6 C-1 5 A-1 4

5 Add a Project Buffer… PB = √ 2 2 + 2.5 2 + 4 2 + 3 2 + 14 2 + 7 2 + 3.5 2 + 10 2 + 9 2 = Critical Chain √ 4 + 6.25 + 16 + 9 + 196 + 49 + 12.25 + 100 + 81 = 21.76 X (Z=90%) 1.28 = 28 days 20 10 40503070 60 9010080 120 110 140150130 PB 28 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 C-5 6 A-6 15 F-5 14 F-3 20 E-5 28 A-5 15 E-3 10 B-3 8 A-1 4 C-1 5

6 Add Feeding and Resource Buffers… FB1 = √ 5 2 x 1.28 = 7 FB2 = √ 10 2 x 1.28 = 11 FB3 = √ 7.5 2 + 7.5 2 x 1.28 = 14 CP + PB = 110 + 28 = 138 FP4 and FP5 are redundant 20 10 40503070 60 9010080 FB2 11 FB1 7 120 110 140150130 PB 28 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 C-5 6 A-6 15 F-5 14 F-3 20 E-5 28 A-5 15 E-3 10 B-3 8 A-1 4 C-1 5 FB3 14 FB4 FB5 133 (5 day leeway) 125 (5 day leeway) 41 (5 day leeway) 78 (5 day leeway) 143 (5 day leeway)

7 20 10 40503070 60 9010080 FB2 11 FB1 7 120 110 140150130 PB 28 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 C-5 6 A-6 15 F-5 14 F-3 20 E-5 28 A-5 15 E-3 10 B-3 8 A-1 4 C-1 5 FB3 14 FB4 FB5 133 (5 day leeway) 125 (5 day leeway) 41 (5 day leeway) 78 (5 day leeway) Is this feasible, repeatable and aggressive? 1.Feasible: Yes 2.Repeatable: 1.How many changes? 1.4 changes. Seems a lot… (Perhaps could be better if less changes) 3.Aggressive? 1.138. Might be a few days shorter… 143 (5 day leeway)

8 Move tasks for precedence and resource relationships. 20 10 40503070 60 9010080 Scheduling Activities #2a A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 A-6 15 F-5 14 F-3 20 E-5 28 E-3 10 110 C-5 6 A-5 15 B-3 8 A-1 4 C-1 5 97 days

9 E3, E5, F5, F7, A7, A9 (97 days) 20 10 40503070 60 9010080 Find a Critical Path A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 A-6 15 F-5 14 F-3 20 E-5 28 E-3 10 110 C-5 6 A-5 15 B-3 8 A-1 4 C-1 5 97

10 20 10 40503070 60 9010080 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 A-6 15 F-5 14 F-3 20 E-5 28 E-3 10 110 C-5 6 A-5 15 B-3 8 A-1 4 C-1 5 125 Add a Project Buffer PB = Z 90% x (5 2 + 14 2 + 7 2 + 3.5 2 + 10 2 + 9 2 ) 1/2 = 1.28 x 21.5 = 28 days PB 28 120 130 140

11 20 10 40503070 60 9010080 A-9 18 F-9 10 D-9 6 F-7 7 D-7 9 A-7 20 A-6 15 F-5 14 F-3 20 E-5 28 E-3 10 110 C-5 6 A-5 15 B-3 8 A-1 4 C-1 5 130 Add Feeding Buffers FB1 = Z 90% x 10 = 13 FB2 = Z 90% x (2.5 2 + 4 2 + 7.5 2 + 7.5 2 ) 1/2 = 1.28 x 11.6 = 15 FB3 = Z 90% x (2.5 2 + 4 2 + 3 2 + 4.5 2 + 3 2 ) 1/2 = 1.28 x 7.8 = 10 - REDUNDANT FB4 = Z 90% x 5 = 7 - REDUNDANT PB 28 120 130 140 FB1 13 FB3 10 FB2 15 FB4 7

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