1. Two-Sample Inference Procedures with Means

2. Suppose we have a population of adult men with a mean height of 71 inches and standard deviation of 2.6 inches. We also have a population of adult women with a mean height of 65 inches and standard deviation of 2.3 inches. Assume heights are normally distributed. Describe the distribution of the difference in heights between males and females (male- female). Normal distribution with  x-y =6 inches &  x-y =3.471 inches

3. 7165 Female Male 6 Difference = male - female

4. Remember: We will be interested in the difference of means, so we will use this to find standard error.

5. Do calculator simulation! a) What is the probability that the mean height of 30 men is at most 5 inches taller than the mean height of 30 women? b) What is the 70th percentile for the difference (male-female) in mean heights of 30 men and 30 women? 6.332 inches P((x m – x w )< 5) =.0573

6. Two-Sample Procedures with means two treatments two populationsThe goal of these inference procedures is to compare the responses to two treatments or to compare the characteristics of two populations. We have INDEPENDENT samples from each treatment or population

7. Assumptions: two SRS’s two randomly assignedHave two SRS’s from the populations or two randomly assigned treatment groups Samples are independent Both populations are normally distributed –Have large sample sizes –Graph BOTH sets of data  ’s  ’s known/unknown

8. Formulas NOT Since in real-life, we will NOT know both  ’s, we will do t-procedures.

9. Degrees of Freedom Option 1: use the smaller of the two values n 1 – 1 and n 2 – 1 This will produce conservative results – higher p-values & lower confidence. Option 2: approximation used by technology Calculator does this automatically!

10. Confidence intervals: Called standard error

11. Pooled procedures: Used for two populations with the same variance When you pool, you average the two-sample variances to estimate the common population variance. DO NOT use on AP Exam!!!!! We do NOT know the variances of the population, so ALWAYS tell the calculator NO for pooling!

12. Two competing headache remedies claim to give fast- acting relief. An experiment was performed to compare the mean lengths of time required for bodily absorption of brand A and brand B. Assume the absorption time is normally distributed. Twelve people were randomly selected and given an oral dosage of brand A. Another 12 were randomly selected and given an equal dosage of brand B. The length of time in minutes for the drugs to reach a specified level in the blood was recorded. The results follow: meanSDn Brand A20.18.712 Brand B18.97.512 Describe the shape & standard error for sampling distribution of the differences in the mean speed of absorption. (answer on next screen)

13. Describe the sampling distribution of the differences in the mean speed of absorption. Find a 95% confidence interval difference in mean lengths of time required for bodily absorption of each brand. (answer on next screen) Normal distribution with S.E. = 3.316

14. Assumptions: Have 2 independent SRS from volunteers Given the absorption rate is normally distributed  ’s unknown We are 95% confident that the true difference in mean lengths of time required for bodily absorption of each brand is between –5.685 minutes and 8.085 minutes. State assumptions! Formula & calculations Conclusion in context From calculator df = 21.53, use t* for df = 21 & 95% confidence level Think “Price is Right”! Closest without going over

15. Note: confidence interval statements “mean difference”Matched pairs – refer to “mean difference” “difference of means”Two-Sample – refer to “difference of means”

16. In a recent study on biofeedback, it was reported that meditation could alter the alpha & beta waves in the brain thus changing the rate at which the heart beats. This is important for relieving the effects of stress. Let’s test this!

17. Hypothesis Statements: H 0 :  1 -  2 = 0 H a :  1 -  2 < 0 H a :  1 -  2 > 0 H a :  1 -  2 ≠ 0 H 0 :  1 =  2 H a :  1 <  2 H a :  1 >  2 H a :  1 ≠  2 BOTH Be sure to define BOTH  1 and  2 !

18. Hypothesis Test: Since we usually assume H 0 is true, then this equals 0 – so we can usually leave it out

19. The length of time in minutes for the drugs to reach a specified level in the blood was recorded. The results follow: meanSDn Brand A20.18.712 Brand B18.97.512 Is there sufficient evidence that these drugs differ in the speed at which they enter the blood stream?

20. Assump.: Have 2 independent SRS from volunteers Given the absorption rate is normally distributed  ’s unknown Since p-value > a, I fail to reject H 0. There is not sufficient evidence to suggest that these drugs differ in the speed at which they enter the blood stream. State assumptions! Formula & calculations Conclusion in context H 0 :  A =  B H a :  A =  B Where  A is the true mean absorption time for Brand A &  B is the true mean absorption time for Brand B Hypotheses & define variables!

21. Suppose that the sample mean of Brand B is 16.5, then is Brand B faster? No, I would still fail to reject the null hypothesis.

22. Robustness: more robustTwo-sample procedures are more robust than one-sample procedures BESTBEST to have equal sample sizes! (but not necessary)

23. A modification has been made to the process for producing a certain type of time-zero film (film that begins to develop as soon as the picture is taken). Because the modification involves extra cost, it will be incorporated only if sample data indicate that the modification decreases true average development time by more than 1 second. Should the company incorporate the modification? Original8.65.14.55.46.36.65.78.5 Modified5.54.03.86.05.84.97.05.7