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U4 S1 L3 Balancing by redox Textbook Readings MHR page 730: The Half-Reaction Method for Balancing Equations page 731: Balancing Half-Reactions page 732: Balancing Half-Reactions for Acidic Solutions page 733: Balancing Half-Reactions for Basic Solutions pages 734-736: Half-Reaction Method for Balancing Redox Reactions pages 736-738: Balancing Redox Reactions for Acidic and Basic Solutions pages 742-744: Stoichiometry and Redox Titrations Textbook Practice Items MHR page 732: items 17, 18, 19 and 20 page 734: items 21, 22, 23 and 24 pages 738-739: items 27 and 28 page 744: items 29, 30, 31 and 32 pages 745-746: items 1-9
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Upon completion of this lesson, you should be able to: write and balance equations for complex oxidation-reduction reactions occurring in acidic or basic solutions solve redox stoichiometry problems for spontaneous redox reactions
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The first thing we have to do when balancing redox equations is to make sure the reaction is indeed a redox reaction. Therefore, we must check to make sure that a species is being reduced and one is being oxidized. Once the redox species have been identified we can proceed to balance the equation. Balancing by half reactions: (balancing by electrons!) Potassium reacts with Chlorine to produce potassium chloride.
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Balancing Redox Reactions in Acidic Conditions: ~~The No Fail 6 Step Method~~ p 732 1.Write the half reaction for the species being oxidized and reduced. 2.Balance: –Atoms other than O and H –Balance O using H 2 O –Balance H using H + (hence acidic conditions!) 3.Balance each half reaction electrically using electrons (e - ). Net charge must be zero. 4.Balance each half reaction so that the number of electrons in each is the same. 5.Simplify. Combine both equations (cross out/add/subtract - just like in math). 6.Check the numbers, kinds of atoms and net charge.
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Write a balanced half reaction for that shows the reduction of permanganate ions to manganese (II) under acidic conditions.
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Balance the following chemical equation under acidic conditions
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Balancing Redox Reactions in Basic Conditions: ~~The No Fail 7 Step Method~~ p 733 1.Write the half reaction for the species being oxidized and reduced. 2.Balance: –Atoms other than O and H –Balance O using H 2 O –Balance H using H + (hence acidic conditions!) 3.Balance each half reaction electrically using electrons (e - ). Net charge must be zero. 4.Change from acidic to basic – look at the H +, add the same number of OH - to both sides. On the side H + is on form water (H + + OH - H 2 O). 5.Balance each half reaction so that the number of electrons in each is the same. 6.Simplify. Combine both equations (cross out/add/subtract - just like in math). 7.Check the numbers, kinds of atoms and net charge.
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Write a balanced half reaction for the oxidation of thiosulphate ions to sulfite ions in basic conditions
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Balance the following under basic conditions:
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Balancing redox by Ox # method – p 747 : The short cut! 1.Write equation 2.Assign Ox #’s 3.Identify atoms involved in redox 4.Find numerical value of change 5.Determine ratio of atoms 6.Balance 7.Balance O with H 2 O and H with H +
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Balance under acidic conditions
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Using the Standard reduction potential Table. Write the redox reaction equation for the reaction between zinc metal and aqueous chromium(III) sulphate –List the reactant species present
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