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Published byEmil Miller Modified over 9 years ago
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Putting redox reactions to work
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Electrons are transferred Lose Electrons Oxidation Gain Electrons Reduction
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Made of two half-cells Based upon two half-reactions Electrons travel between the two half-cells
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Also called voltaic cells Convert chemical energy into electrical energy Spontaneous
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Convert electrical energy into chemical energy Non-spontaneous
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Write the reaction for solid magnesium placed in a copper (II) sulfate solution. Mg (s) + CuSO 4 (aq) MgSO 4 (aq) + Cu (s)
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Balance the reaction using the half-reaction method Mg (s) + CuSO 4 (aq) MgSO 4 (aq) + Cu (s) 0+2 +6 -2 +2 +6 -2 0
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Balance the reaction using the half-reaction method Mg (s) + CuSO 4 (aq) MgSO 4 (aq) + Cu (s) 0+2 +6 -2 +2 +6 -2 0 Mg (s) Mg 2+ (aq) + 2e - Cu 2+ (aq) + 2e - Cu (s)
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Balance the reaction using the half-reaction method Mg (s) + CuSO 4 (aq) MgSO 4 (aq) + Cu (s) 0+2 +6 -2 +2 +6 -2 0 1(Mg (s) Mg 2+ (aq) + 2e - ) 1(Cu 2+ (aq) + 2e - Cu (s)) Mg (s)+CuSO 4 (aq)+2e - MgSO 4 (aq)+Cu (s)+2e -
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Anode Cathode Salt Bridge Flow of electrons
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Potential (either half-cell or cell) ◦ Pull on the electrons ◦ Electromotive force (emf) ◦ Volt (V) ◦ Joule/Coulomb (J/C) Voltmeter ◦ Analog ◦ Digital Potentiometer Positive potential…spontaneous Negative potential…nonspontaneous
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Standard Reduction Potentials Chart ◦ Only reduction reactions ◦ Must look up the reverse of the oxidation and flip the sign of the potential Add standard half-cell potentials to get standard cell potential
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1(Mg (s) Mg 2+ (aq) + 2e - ) E˚ ox = +2.37 V 1(Cu 2+ (aq) + 2e - Cu (s)) E˚ red = +0.342 V Mg (s)+CuSO 4 (aq)+2e - MgSO 4 (aq)+Cu (s)+2e - E˚ cell = +2.71 V
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Oxidation||Reduction X(s)|X + (aq)||Y + (aq)|Y(s) Mg(s)|Mg 2+ (aq)||Cu 2+ (aq)|Cu(s) 1(Mg (s) Mg 2+ (aq) + 2e - ) 1(Cu 2+ (aq) + 2e - Cu (s)) Mg (s)+CuSO 4 (aq)+2e - MgSO 4 (aq)+Cu (s)+2e -
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Cu(s)|Cu 2+ (aq)||Ag 1+ (aq)|Ag(s) 1(Cu (s) Cu 2+ (aq) + 2e - ) E˚ ox = -0.342V 2(Ag 1+ (aq) + 1e - Ag (s)) E˚ red = +0.800V Cu(s)+2Ag 1+ (aq)+2e - Cu 2+ (aq)+2Ag (s)+2e - E˚ cell = +0.458V
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Series of electrochemical cells connected to each other Completes the circuit Dry cell ◦ Flashlight battery ◦ Watch battery Wet Cell ◦ Car battery
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Carbon-Zinc Battery ◦ Zinc casing…anode ◦ Carbon rod…cathode ◦ MnO 2 is actually reduced ◦ Alkaline battery…has KOH rather than NH 4 Cl
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Carbon-Zinc Battery ◦ Zn(s) Zn 2+ (aq) + 2e - ◦ 2NH 4 1+ (aq) + 2MnO 2 (s) + 2e - Mn 2 O 3 (s) + 2NH 3 (g) + H 2 O(l)
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Lead-Acid Storage Battery Pb(s) + PbO 2 (s) + H 2 SO 4 (aq) PbSO 4 (s) + H2O(l) Spontaneous & nonspontaneous
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Not 1M Require additional calculations Can manipulate potential to a particular V
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Nernst Equation ◦ E cell = E˚ cell – {(0.0592/n)(logQ)} n Q
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A 0.500M solution of copper (II) sulfate is reacted with magnesium metal. A 0.750M solution of magnesium sulfate is one of the products. What is the cell potential? ◦ Write two half reactions ◦ Write balanced equation ◦ Determine n ◦ Determine E˚ cell ◦ Use Nernst to solve for E cell Mg(s)|Mg 2+ (aq)||Cu 2+ (aq)|Cu(s)
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1(Mg (s) Mg 2+ (aq) + 2e - ) E˚ ox = +2.37 V 1(Cu 2+ (aq) + 2e - Cu (s)) E˚ red = +0.342 V Mg (s)+CuSO 4 (aq)+2e - MgSO 4 (aq)+Cu (s)+2e - E˚ cell = +2.71 V
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E cell = 2.71 V – {(0.0592/2)(log([0.75]/[0.5]))} E cell = 2.71 V – {(0.0296)(0.176)} E cell = 2.71 V – 0.00521 E cell = 2.70 V
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Cu(s)|Cu 2+ (0.0100M)||Ag 1+ (0.0250M)|Ag(s)
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