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Expected Value and Standard Error for a Sum of Draws (Dr. Monticino)
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Assignment Sheet Read Chapter 17 Assignment #10 (Due Monday April 11 th ) Chapter 17 Exercise Set A: 1,2,4,6 Exercise Set B: 1,2,4 Exercise Set C: 1,2,3,5,7 Exercise Set D: 1-3 Exercise Set E: 1,3,6 Review Exercises: 1-4,7,9,12 Quiz 9 will be over Chapter 16 and possibly part of Ch 17 Test 2 over Chapters 13 - 18 is scheduled for April 13 th
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Overview Expected value For a single draw For a sum of draws Standard deviation Short cut For a single draw For a sum of draws: Standard Error Relation to the normal distribution
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Expected Value For a single draw or a single repetition of a random process Suppose that a random process produces values x 1,x 2,...x n with probabilities p 1,p 2,...,p n. The expected value of the process is the weighted average p 1 *x 1 + p 2 *x 2 +...+ p n *x n If a box model of the process is constructed, then expected value is just the average of the box Examples Suppose a box model contains three –5 tickets and two +10 tickets Flip a fair coin, win $1 if heads comes up, lose $1 if tails comes up Bet $1 on “17” in roulette, win $35 if the number comes up
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Expected Value If the process is repeated N times, then expected sum = expected value for the sum = (expected value for one repetition) N Examples Draw 20 times from a box model that contains three –5 tickets and two +10 tickets Flip a fair coin 5 times, win $1 if heads comes up, lose $1 if tails comes up Bet $1 on “17” in roulette 10 times, win $35 if the number comes up
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Standard Deviation For a single draw or a single repetition of a random process Suppose that a random process produces values x 1,x 2,...x n with probabilities p 1,p 2,...,p n. Let denote the expected value The standard deviation of the process is If a box model of the process is constructed, then the standard deviation is just the standard deviation of the box Just calculate the SD of the list of numbers
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Standard Deviation Short cut method for finding standard deviation of a single draw or a single repetition See page 298 You may use this method freely It can be shown that this method is equivalent to using:
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Standard Deviation Examples Suppose a box model contains three –5 tickets and two +10 tickets Flip a fair coin, win $1 if heads comes up, lose $1 if tails comes up Bet $1 on “17” in roulette, win $35 if the number comes up
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Standard Error If the process is repeated N times, then the standard error (standard deviation for the sum) is equal to If the process is repeated N times, then the sum is likely to be around expected sum standard error
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Standard Error Examples Draw 20 times from a box model that contains three –5 tickets and two +10 tickets Flip a fair coin 5 times, win $1 if heads comes up, lose $1 if tails comes up Bet $1 on “17” in roulette 10 times, win $35 if the number comes up
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Normal Approximation Observed sums are usually within 2 to 3 SE’s away from the expected sum When the number of draws is large, the distribution of the sum is approximately normal with mean equal to the expected sum and standard deviation equal to the standard error
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Binomial to Normal Suppose that you play “red-black” in a Nevada casino You always bet on red; bet $1 each time; play two times What is your probability of at least breaking even? Using binomial probabilities: At least breaking even means winning at least once
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Binomial to Normal Play red-black again, always bet on red; bet $1 each time; now play ten times Probability of at least breaking even is the probability of winning at least five times
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Binomial to Normal Again play red-black again, always bet on red; bet $1 each time; now play fifty times Probability of at least breaking even is the probability of winning at least twenty-five times
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Binomial to Normal Binomial probabilities for 2 plays, 10 plays, 50 plays, 100 plays
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Normal Approximation Suppose that you play “red-black” in a Nevada casino You always bet on red Bet $1 each time Play 500 times What is your probability of At least breaking even Winning more than $50 (Dr. Monticino)
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