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Algjebra Relacionale & SQL
Ligjerata 2 Algjebra Relacionale & SQL
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Algjebra Relacionale Algjebra Relacionale perdoret per te definuar menyren se si relacionet (tabelat) mund te operojne dhe dhe manipulojne me te dhena. Ajo perdor bazat e SQL me bazen e te dhenave relacionale, dhe ilustron operacionet bazike duke perdore DML. Kjo algjeber i paraqet operacionet themelore (duke involvuar tabelat) dhe operatcionet binare (duke perdore disa tabela).
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SQL Structured Query Language (SQL)
Eshte e Standardizuar nga ANSI Perkrahet nga RDBMS-te moderne Kommandat jane te perfshira ne tri grupe Data Definition Language (DLL) Krijojne tabelat , etj Data Manipulation Language (DML) Modifikoojne te dhenat Data Control Language Kontrollojne se qka duan te perdorin – pranimet dhe nderprerjen e privilegjet
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Operacionet Selekcionimi Projektimi
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Selection Seleksionimi ose operacioni selekton rreshtat prej tabeles qe paraqitet me kushtin: < kusht > < emri i tabeles> Shembull: course = ‘CM’ Students Students stud# name course 100 Faton PH stud# name course 200 Agim CM Agim CM 300 Bujar CM Bujar CM
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Projeksioni Projekcioni ose eshte operacion i cili selekton listen e kolonave nga tabela. < lista e kolones > < emriitabeles > shembulli: stud#, name Students Students stud# name course stud# name 100 Faton PH Faton Agim CM Agim Bujar CM Bujar
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Selekcionimi / Projektimi
Selekcionimi dhe projektimi zakonisht kombinohen: stud#, name ( course = ‘CM’ Students) Students stud# name course 100 Faton PH stud# name 200 Agim CM Agim 300 Bujar CM Bujar
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Operacionet Binare Cartesian Product Theta Join Inner Join Natural Join Outer Joins Semi Joins
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Produkti Cartesian Çdo rresht në relacionin e parë (R) me çdo rresht në lidhje të dytë (S): R X S
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Produkti Cartesian - Shembull
Students Courses stud# name course course# name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing 300 Bujar CM Students X Courses = stud# Students.name course course# Courses.name 100 Faton PH PH Pharmacy 100 Faton PH CM Computing 200 Agim CM PH Pharmacy 200 Agim CM CM Computing 300 Bujar CM PH Pharmacy 300 Bujar CM CM Computing
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Theta Join Produkti Kartezian me kusht aplikohet: R ⋈ <kushti> S
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Theta Join - Shembull Students Courses stud# name course course# name
100 Faton PH PH Pharmacy 200 Agim CM CM Computing 300 Bujar CM Students ⋈ stud# = 200 Courses stud# Students.name course course# Courses.name 200 Agim CM PH Pharmacy 200 Agim CM CM Computing
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Inner Join (Equijoin) brendshem
Theta join ku <kushti> eshte (=) per qelesin primar dhe qelesin e jashtem R ⋈ <R.primary_key = S.foreign_key> S
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Inner Join - Shembull Students Courses stud# name course course# name
100 Faton PH PH Pharmacy 200 Agim CM CM Computing 300 Bujar CM Students ⋈ course = course# Courses stud# Students.name course course# Courses.name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing 300 Bujar CM CM Computing
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Natural Join Inner join jep te dhena te teperta (ne shembullin e meparshem: course and course#). Për të hequr këtë dyfishim: < stud#, Students.name, course, Courses.name > (Students ⋈ <course = course#> Courses) Ose R1= Students ⋈ <course = course#> Courses R2= < stud#, Students.name, course, Courses.name > R1 Rezultati quhet natural join i Students dhe Courses
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Natural Join - Shembull
Students Courses stud# name course course# name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing Bujar CM R1= Students ⋈ <course = course#> Courses R2= < stud#, Students.name, course, Courses.name > R1 stud# Students.name course Courses.name 100 Faton PH Pharmacy 200 Agim CM Computing 300 Bujar CM Computing
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Outer Joins Inner join + rreshat e tabeles qe nuk e plotesojne <kushtin> Left Outer Join: R <R.primary_key = S.foreign_key> S Të gjitha rreshtave nga R ruhen dhe rreshtat tjere e S janë te mbushur me NULL Right Outer Join: R <R.primary_key = S.foreign_key> S Të gjitha rreshtave nga S ruhen dhe rreshtave qe nuk e plotesojne kushtin në R janë te mbushura me NULL
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Left Outer Join - Shembull
Students Courses stud# name course course# name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing Petrit EN CH Chemistry Students <course = course#> Courses stud# Students.name course course# Courses.name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing Petrit EN NULL NULL
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Right Outer Join - Shembull
Students Courses stud# name course course# name 100 Faton PH PH Pharmacy 200 Agim CM CM Computing Petrit EN CH Chemistry Students <course = course#> Courses stud# Students.name course course# Courses.name Faton PH PH Pharmacy Agim CM CM Computing NULL NULL NULL CH Chemistry
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Kombinimi i operacioneve dhe JOIN
Students Courses stud# name address course course# name 100 Faton Aberdeen PH PH Pharmacy 200 Agim Dundee CM CM Computing 300 Bujar Aberdeen CM Si te paraqiten emrat e studenteve (nga Aberdeen) dhe emrat e kursev ete tyre R1= Students ⋈ <course=course#> Courses R2= <address=“Aberdeen”> R1 R3= <Students.name, Course.name> R2 Students.name Courses.name Faton Pharmacy Bujar Computing
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Disa Operacione te tjera
Unioni Intersekcioni Diferenca
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Unioni Takes the set of rows in each table and combines them, eliminating duplicates Participating relations must be compatible, ie have the same number of columns, and the same column names, domains, and data types R S R S A B a2 b2 a3 b3 A B a1 b1 a2 b2 a3 b3 A B a1 b1 a2 b2
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Intersection Takes the set of rows that are common to each relation
Participating relations must be compatible R S R S A B a1 b1 a2 b2 A B a2 b2 a3 b3 A B a2 b2
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Difference Takes the set of rows in the first relation but not the second Participating relations must be compatible R S R - S A B a1 b1 a2 b2 A B a2 b2 a3 b3 A B a1 b1
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Ushtrimi - Employee WorkLoad Project
empid name empid* projid* duration projid name E100 Faton E100 P P001 DB E200 Agim E200 P P002 Access E300 Bujar E300 P P003 SQL E400 Petrit Përcaktoni rezultatin e operacioneve për: Natural join ndermjet Employee dhe WorkLoad Left outer join ndermjet Employee dhe WorkLoad Right outer join ndermjet WorkLoad dhe Project
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Algjebra Relacionale Te shkruarit e oeracioneve ne SQL
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Unary Operations Selection Projection course = ‘Computing’ Students
In SQL: Select * From Students Where course = ‘Computing’; Projection stud#, name Students In SQL: Select stud#, name From Students; Selection & Projection stud#, name ( course = ‘Computing’ Students) In SQL: Select stud#, name From students Where course = ‘Computing’;
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Binary Operations/Joins
Cartesian Product: Students X Courses In SQL: Select * From Students, Courses; Theta Join: Students ⋈ <stud# =200> Courses In SQL: Select * From Students, Courses Where stud# = 200;
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Binary Operations/Joins
Inner Join (Equijoin): Students ⋈ <course=course#> Courses In SQL: Select * From Students, Courses Where course=course#; Natural Join: R1= Students ⋈ <course = course#> Courses R2= < stud#, Students.name, course, Courses.name > R1 In SQL: Select stud#, Students.name, course, Courses.name From Students, Courses Where course=course#;
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Outer Joins Left Outer Join Students <course = course#> Courses
In SQL: Select * From Students, Courses Where course = course#(+) Right Outer Join Students <course = course#> Courses In SQL: Select * From Students, Courses Where course(+) = course#
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Combination of Unary and Join Operations
R1= Students ⋈ <course=course#> Courses R2= <address=“Aberdeen”> R1 R3= <Students.name, Course.name> R2 In SQL: Select Students.name, Courses.name From Students, Courses Where course=course# AND address=“Aberdeen”;
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Set Operations Union: R S Intersection: R S In SQL: In SQL:
Select * From R Union Select * From S; Intersection: R S In SQL: Select * From R Intersect Select * From S; Difference: R - S In SQL: Select * From R Minus Select * From S;
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SQL Operators Between, In, Like, Not
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SQL Operators SELECT * FROM Book WHERE catno BETWEEN 200 AND 400;
FROM Product WHERE prod_desc BETWEEN ‘C’ AND ‘S’; WHERE catno NOT BETWEEN 200 AND 400;
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SQL Operators SELECT Catno FROM Loan WHERE Date-Returned IS NULL;
WHERE Date-Returned IS NOT NULL;
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SQL Operators SELECT Name FROM Member
WHERE memno IN (100, 200, 300, 400); WHERE memno NOT IN (100, 200, 300, 400);
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SQL Operators SELECT Name FROM Member
WHERE address NOT LIKE ‘%Aberdeen%’; WHERE Name LIKE ‘_ES%’; Note: In MS Access, use * and # instead of % and _
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Selecting Distinct Values
Student stud# name address 100 Faton Aberdeen 200 Agim Dundee 300 Bujar Aberdeen SELECT Distinct address FROM Student; address Aberdeen Dundee
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Exercise Employee(empid, name) Project(projid, name)
WorkLoad(empid*, projid*, duration) List the names of employees working on project name ‘Databases’.
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