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Label the points where the graph crosses the x-axis. x y Problem 1.

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Presentation on theme: "Label the points where the graph crosses the x-axis. x y Problem 1."— Presentation transcript:

1 Label the points where the graph crosses the x-axis. x y Problem 1

2 Label the points where the graph crosses the x-axis. x-2012 y3210 Problem 1 Solution

3 Find the area of the green shaded region. Problem 2 10 12

4 Find the area of the green shaded region. Problem 2 10 12 A - A = Area of shaded region Solution

5 Find the area of the green shaded region. Problem 2 10 12 A - A = Area of shaded region 12(10) – 12(10) = Area of green region 2 Solution

6 Find the area of the green shaded region. Problem 2 10 12 A - A = Area of shaded region 12(10) – 12(10) = Area of green region 2 120 – 60 = Area of green region 60 = Area of green region Solution

7 Solve the diamond problem. Problem 3 1 3 3 5

8 Solve the diamond problem. Problem 3 1 3 3 5 Solution To get the top number Multiply 1/3 and 3/5 together.

9 Solve the diamond problem. Problem 3 1 3 3 5 Solution 1 3 3 5 = 3 15 or 1515

10 Solve the diamond problem. Problem 3 1 3 3 5 Solution 1*5 3*5 + = 3535 Multiply top and bottom by 5. 1515

11 Solve the diamond problem. Problem 3 1 3 3 5 Solution 1*5 5 3*5 15 + = 3535 1515 Multiply top and bottom by 5.

12 Solve the diamond problem. Problem 3 1 3 3 5 Solution 1*5 5 3*5 15 + = 3*3 5*3 Multiply top and bottom by 3. = 9 15 1515

13 Solve the diamond problem. Problem 3 1 3 3 5 Solution 1*5 5 3*5 15 + = 3*3 5*3 Lastly add the two fractions. = 9 15 14 15 1515

14 Solve the diamond problem. Problem 3 1 3 3 5 Solution 14 15 1515

15 Solve the diamond problem. Problem 4 20 -2

16 Solve the diamond problem. Problem 4 20 -2 Think, -2 * what number = 20

17 Solve the diamond problem. Problem 4 20 -2 -2 * -10 = + 20

18 Solve the diamond problem. Problem 4 20 -2 - 10 -2 * -10 = + 20

19 Solve the diamond problem. Problem 4 20 -2 - 10 -2 + (-10) = - 12

20 Solve the diamond problem. Problem 4 20 -2 - 10 -12 Solution

21 Use the graph to answer each of the questions. Name the y-coordinate of the point whose x-coordinate is -1. Problem 5

22 Use the graph to answer each of the questions. Name the y-coordinate of the point whose x-coordinate is -1. The y-coordinate = + 2 Problem 5 2 Solution

23 Use the graph to answer each of the questions. Name the x-coordinate of the point whose y-coordinate is -4. Problem 6

24 Use the graph to answer each of the questions. Name the x-coordinate of the point whose y-coordinate is -4. Problem 6 The x-coordinate = + 1 Solution

25 Use the graph to answer each of the questions. Label the point where the graph crosses the x-axis. Problem 7 The graph crosses at -.4 Solution

26 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1 lap? Problem 8

27 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1 lap? Problem 8 4 laps 1 lap 6 min. x min =

28 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1 lap? Problem 8 4 laps 1 lap 6 min. x min = One lap takes George 6/4 or 3/2 minutes. Solution

29 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1/2 lap? Problem 9

30 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1/2 lap? Problem 9 4 laps.5 lap 6 min. x min =

31 If George runs 4 laps in 6 minutes. At that pace how long did it take him to run 1/2 lap? Problem 9 4 laps.5 lap 6 min. x min = It will take ¾ min to run a ½ lap. Solution

32 If George runs 4 laps in 6 minutes. How many laps would George run if he ran 30 minutes? Problem 10

33 If George runs 4 laps in 6 minutes. How many laps would George run if he ran 30 minutes? Problem 10 4 laps x lap 6 min. 30 min =

34 If George runs 4 laps in 6 minutes. How many laps would George run if he ran 30 minutes? Problem 10 4 laps x lap 6 min. 30 min = After 30 minutes of running, George will have run 20 laps! Solution

35 Calculate the using the order of operations. Problem 11 (-4)(-2) – 6(2) - 5

36 Calculate the using the order of operations. Problem 11 (-4)(-2) – 6(2) - 5 +8 - 12 - 5

37 Calculate the using the order of operations. Problem 11 (-4)(-2) – 6(2) - 5 +8 - 12 - 5 -4 - 5 - 9 Solution

38 Calculate the using the order of operations. Problem 12 30 – (17 – 5 2)²

39 Calculate the using the order of operations. Problem 12 30 – (17 – 5 2)² 30 – (17 – 10) ² 1 st Multiply negative 5 and positive Solution

40 Calculate the using the order of operations. Problem 12 30 – (17 – 5 2)² 30 – (17 – 10) ² 30 – (7) ² 1 st Multiply negative 5 and positive 2 nd Subtract 17 and 10 Solution

41 Calculate the using the order of operations. Problem 12 30 – (17 – 5 2)² 30 – (17 – 10) ² 30 – (7) ² 30 – 49 1 st Multiply negative 5 and positive 2 nd Subtract 17 and 10 3 rd Square 7 Solution

42 Calculate the using the order of operations. Problem 12 30 – (17 – 5 2)² 30 – (17 – 10) ² 30 – (7) ² 30 – 49 - 19 1 st Multiply negative 5 and positive 2 nd Subtract 17 and 10 3 rd Square 7 4 th Subtract Solution

43 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² )

44 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² ) 4(2 + 5 – 6) ÷ ( 9 – 4 ) Solution Do the operations in blue 1st

45 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² ) 4(2 + 5 – 6) ÷ ( 9 – 4 ) 4(7 – 6 ) ÷ (5) Solution Follow each step by doing the operations in blue.

46 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² ) 4(2 + 5 – 6) ÷ ( 9 – 4 ) 4(7 – 6 ) ÷ (5) 4(1) ÷ 5 Solution Follow each step by doing the operations in blue.

47 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² ) 4(2 + 5 – 6) ÷ ( 9 – 4 ) 4(7 – 6 ) ÷ (5) 4(1) ÷ 5 Solution Follow each step by doing the operations in blue.

48 Calculate the using the order of operations. Problem 13 4(2 + 5 – 3 2) ÷ (3² – 2² ) 4(2 + 5 – 6) ÷ ( 9 – 4 ) 4(7 – 6 ) ÷ (5) 4(1) ÷ 5 4 ÷ 5 0.80 Solution Follow each step by doing the operations in blue.

49 Solve for x. Combine the same color terms on each side of the equal sign Problem 14 3x + 5 + x = 15 + 2x – 9

50 Solve for x. Combine the same color terms on each side of the equal sign Problem 14 3x + 5 + x = 15 + 2x – 9 4x + 5 = 2x + 6 Solution

51 Solve for x. Subtract the 2x from each side and subtract 5 from each side. Problem 14 3x + 5 + x = 15 + 2x – 9 4x + 5 = 2x + 6 -2x – 5 = -2x - 5 Solution

52 Solve for x. Problem 14 3x + 5 + x = 15 + 2x – 9 4x + 5 = 2x + 6 -2x – 5 = -2x – 5 2x = 1 Solution

53 Solve for x. Divide remaining terms by 2. And the answer is.... One Half!! Problem 14 3x + 5 + x = 15 + 2x – 9 4x + 5 = 2x + 6 -2x – 5 = -2x – 5 2x = 1 2 x = 1/2 Solution

54 Solve for x. Problem 15 17 + 2 – 3x = -19

55 Solve for x. Problem 15 17 + 2 – 3x = -19 19 - 3x = - 19 Solution Combine 17 and 2 on the left side of the equal sign.

56 Solve for x. Problem 15 17 + 2 – 3x = -19 19 - 3x = - 19 - 19 = -19 Solution Subtract 19 from both sides.

57 Solve for x. Problem 15 17 + 2 – 3x = -19 19 - 3x = - 19 - 19 = - 19 - 3x = - 38 Solution Remember -19 -19 = - 38!

58 Solve for x. Problem 15 17 + 2 – 3x = -19 19 - 3x = - 19 - 19 = - 19 - 3x = - 38 Solution Divide both sides by -3. -3 - 3

59 Solve for x. Problem 15 17 + 2 – 3x = -19 19 - 3x = - 19 - 19 = - 19 - 3x = - 38 Solution Divide both sides by -3. -3 - 3 x = + 12.67

60 Solve for x. Problem 16 5x – 7 = - (6x – 15)

61 Solve for x. Problem 16 5x – 7 = - 1(6x – 15) Write the negative 1 before the parenthesis!!!! Solution

62 Solve for x. Problem 16 5x – 7 = - 1(6x – 15) 5x – 7 = - 6x + 15 Multiply 6x and negative 15 by negative 1. That changes the signs. Solution

63 Solve for x. Problem 16 5x – 7 = - (6x – 15) 5x – 7 = - 6x + 15 +6x + 7 = +6x + 7 Add 6x to both sides and add 7 to both sides of the equal sign. Solution

64 Solve for x. Problem 16 5x – 7 = - (6x – 15) 5x – 7 = - 6x + 15 +6x + 7 = +6x + 7 Lastly divide both sides by 11. 11x = 22 Solution

65 Solve for x. Problem 16 5x – 7 = - (6x – 15) 5x – 7 = - 6x + 15 +6x + 7 = +6x + 7 Lastly divide both sides by 11. 11x = 22 11 x = 2 Solution

66 Solve for x. Problem 17 12 – 4x + 2 = 10 – 5x + 6 Combine the black non-x terms.

67 Solve for x. Problem 17 12 – 4x + 2 = 10 – 5x + 6 14 – 4x = 16 – 5x Now get all teal colored x terms on the left and black numbers on the right. Solution

68 Solve for x. Problem 17 12 – 4x + 2 = 10 – 5x + 6 14 – 4x = 16 – 5x -14 + 5x = -14 + 5x Add 5x to both sides and Subtract 14 from both sides. Solution

69 Solve for x. Problem 17 12 – 4x + 2 = 10 – 5x + 6 14 – 4x = 16 – 5x -14 + 5x = -14 + 5x Solution x = 2

70 Simplify. Problem 19 5x + 7 – (2x + 2)

71 Simplify. Problem 18 5x + 7 –1(2x + 2) Write the negative 1 before the parenthesis!!!! Solution

72 Simplify. Problem 18 5x + 7 –1(2x + 2) 5x + 7 – 2x – 2 Change the signs in front of the 2x and 2!! Solution

73 Simplify. Problem 18 5x + 7 –1(2x + 2) 5x + 7 – 2x – 2 3x + 5 Since there is NO equal sign, simply combine like terms. Solution

74 Solve for x. Subtract 7 from sides Problem 20 3/2 x + 7 = 27

75 Solve for x. Problem 20 3/2 x + 7 = 27 - 7 = - 7 Solution Subtract 7 from sides

76 Solve for x. Stop! There is a fraction in front of the x. We solve it by multiplying both sides by 2/3. Problem 20 3/2 x + 7 = 27 - 7 = - 7 Solution 3 2 x = 20

77 Solve for x. Stop! There is a fraction in front of the x. We solve it by multiplying both sides by 2/3. Problem 20 3/2 x + 7 = 27 - 7 = - 7 Solution 3 2 x = 20 2 2 3 3

78 Solve for x. Remember that 2/3 * 3/2 = 1. Problem 20 3/2 x + 7 = 27 - 7 = - 7 Solution 3 2 x = 20 2 2 3 3 1x = 40/3

79 Complete the table. Then find the rule. Problem 21 x-20123 y-5315

80 Evaluate the expression when x = - 4. Problem 23 4x – 8 + 2x + 10 Replace x with -4

81 Evaluate the expression when x = - 4. Problem 23 Multiply 4 and negative 4 Multiply Positive 2 and negative 4 4x – 8 + 2x + 10 4(-4) – 8 + 2(-4) + 10 Solution

82 Evaluate the expression when x = - 4. Problem 23 4x – 8 + 2x + 10 4(-4) – 8 + 2(-4) + 10 - 16 – 8 – 8 + 10 Solution Multiply 4 and negative 4 Multiply Positive 2 and negative 4

83 Evaluate the expression when x = - 4. Problem 23 Combine left to right 4x – 8 + 2x + 10 4(-4) – 8 + 2(-4) + 10 -16 – 8 – 8 + 10 - 24 - 8 + 10 Solution

84 Evaluate the expression when x = - 4. Problem 23 Combine left to right 4x – 8 + 2x + 10 4(-4) – 8 + 2(-4) + 10 -16 – 8 – 8 + 10 - 24 - 8 + 10 - 32 + 10 Solution

85 Evaluate the expression when x = - 4. Problem 23 Combine left to right 4x – 8 + 2x + 10 4(-4) – 8 + 2(-4) + 10 -16 – 8 – 8 + 10 - 24 - 8 + 10 - 32 + 10 - 22 Solution

86 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y

87 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y4 Solution y = -2(-2) y = + 4

88 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y42 Solution y = -2(-1) y = + 2

89 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y420 Solution y = -2(0) y = 0

90 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y420-2 Solution y = -2(1) y = -2

91 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y420-2-4 Solution y = -2(2) y = -4

92 Fill the table for the rule y = -2x. Then graph the line. Problem 24 x-2012 y420-2-4 Solution Now, plot the points and graph the line.

93 Study the tiles. Draw the 1 st, and 5 th figures. Problem 25 Fig. 2 Fig. 3 Fig. 4

94 Study the tiles. Draw the 1 st, and 5 th figures. Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution

95 Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution Complete the table. x012345 y

96 Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution Complete the table. x012345 y23456

97 Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution x012345 y23456 Write the rule for the table. Rule: y = x + 1 or in words Add 1 to x to get y.

98 Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution x012345 y23456 How many tiles will the 50 th figure have?

99 Problem 25 Fig. 1 Fig. 2 Fig. 3 Fig. 4 Fig. 5 Solution x012345 y23456 How many tiles will the 50 th figure have? y = 50 + 1 The 50 th figure will have 51 tiles.


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