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Published byMarcus Summers Modified over 9 years ago
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Lesson 6-3B Objective: Solve inequalities using more than one step…continued
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5x + 10 – 3x -9 > 8 ( ) -9 (-9) 5x + 10 – 3x < -72 2x + 10 < -72 -10 2x < -82 x < - 41 2 2
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Example 3-2a -8x -8x 3(2x – 1) + 4x < 8x + 7 6x – 3 + 4x < 8x + 7 10x – 3 < 8x + 7 2x – 3 < 7 +3 +3 2x < 10 2 2 x < 5 Combine like terms
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Example 3-2a +6x +6x -2(3x + 5) > 3(-2x + 4) -6x + -10 > -6x + 12 -10 > 12 This is a false statement……. no solution ( Ø ) variables are gone from both sides!
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Example 3-2a -4x -4x ½ (8x – 10 ) ≤ 2(2x + 3) 4x – 5 ≤ 4x + 6 -5 ≤ 6 This is a true statement……. all real numbers are solutions ( R ) variables are gone from both sides!
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Work with your table partner to complete the challenge problem… 8 – (c + 3) ≤ 6c + 3(2 – c)
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Example 3-4a Answer: or +c +c -6 -6 8 – (c + 3) ≤ 6c + 3(2 – c)
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Lesson 6-3B, p. 335 #26-30, 35-38, 41, 42 Quiz tomorrow (6-1 to 6-3) Assignment:
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