2. AREA Remember: The perimeter of a shape is a measure of distance around the outside. The area of a shape is a measure of the surface/space contained within its perimeter. Area is measured in units 2 Units of distance mm cm m km inches feet yards miles 1 cm 1 cm 2 1 cm Metric Imperial Units of area mm 2 cm 2 m 2 km 2 inches 2 feet 2 yards 2 miles 2 Metric Imperial

3. AREA Remember: The perimeter of a shape is a measure of distance around the outside. The area of a shape is a measure of the surface/space contained within its perimeter. Area is measured in units 2 Units of distance mm cm m km inches feet yards miles Units of area mm 2 cm 2 m 2 km 2 inches 2 feet 2 yards 2 miles 2 1 cm 1 cm 2 1 cm 18 cm 2 6 cm 3 cm Area = 6 cm x 3 cm = 18 cm 2 Metric Imperial Metric Imperial

4. 4 m 2 m 5 m 3 m 7 m 4 m Area 8 m 2 15 m 2 28 m 2 2 rows of 4 or 4 columns of 2 2 x 4 or 4 x 2 3 rows of 5 or 5 columns of 3 3 x 5 or 5 x 3 4 rows of 7 or 7 columns of 4 4 x 7 or 7 x 4 To Find the area of a rectangle simply multiply the 2 dimensions together. Area = l x w (or w x l)

5. Area of a Triangle rectangle area = 2 + 2 triangle area = ½ rectangle area base height Area of a triangle = ½ base x height The area of a triangle = ½ the area of the surrounding rectangle/parallelogram

6. Area = ½ x 8 x 9 = 36 cm 2 Area = ½ x 10 x 12 = 60 cm 2 Area = ½ x 14 x 16 = 112 cm 2 Area = ½ x 3.2 x 4.5 = 7.2 m 2 Find the area of the following triangles. 8 cm 10 cm 14 cm 12 cm 9 cm 16 cm Area = ½ b x h 3.2 m 4.5 m 7 mm 5 mm Area = ½ x 7 x 5 = 17.5 mm 2

7. base height base height  Area of a Parallelogram The area of a parallelogram = the area of a rectangle on the same base. Area = base x height

8. 8 cm 14 mm 1.5 m 12 cm5 mm 2.1 m Find the area of each parallelogram below. 1 2 3 Area = 8 x 12 = 96 cm 2 Area = 14 x 5 = 70 mm 2 Area = 1.5 x 2.1 = 3.15 m 2

9. The Area of a Trapezium  a b h  b ½h a Area of trapezium = area of parallelogram A = ½(a + b)h

10. The Area of a Trapezium Area = ½ the sum of the parallel sides x the perpendicular height A = ½(a + b)h a b h ½ah ½bh Area = ½ah + ½bh = ½h(a + b) = ½(a + b)h Area = ½ (8 + 12) x 9 = ½ x 20 x 9 = 90 cm 2 Area = ½(7 + 5) x 6 = ½ x 12 x 6 = 36 cm 2 Find the area of each trapezium 1 8 cm 12 cm 9 cm 2 5 cm 7 cm 6 cm 3 5 cm 3.9 cm 7.1 cm Area = ½(3.9 + 7.1) x 5 = ½ x 11 x 5 = 27.5 cm 2

11. The Area of a Kite The area of a kite is ½ the product of its diagonals. base height Area of rectangle = 4 + 4 Area of kite = ½ area of rectangle. Area of kite = ½ base x height = ½ the product of the diagonals.

12. The Area of a Kite Find the area of the kites below. 8 cm 7 cm 11 cm 12 cm 14 cm 11 cm 1 2 Area = ½ x 16 x 18 = 144 cm 2 Area = ½ x 24 x 25 = 300 cm 2