1. Chapter 7
Circular Motion

2. Chapter 7 Outline Objectives Relate radians to degrees
Calculate angular quantities such as displacement, velocity, & acceleration
Differentiate between centripetal, centrifugal, & tangential acceleration.
Identify the force responsible for circular motion.
Apply Newton’s universal law of gravitation to find the gravitational force between two masses.

3. Converting Between Radians and Degrees
To convert from degrees to radians, simply multiply
Θ(degrees) x π/180
Remember that radians involve π, so we want the degrees to disappear and leave the π.
To convert from radians to degrees, do the inverse of above
Θ(radians) x 180/ π
We now want the radians to go away, so that means π must be divided out.

4. Measuring Rotational Motion
Section 7.1
Measuring Rotational Motion

5. Angular Displacement Δs ΔΘ = r
Angular displacement is the distance an object travels along the circumference of a circle. This is used to measure the speed of a orbiting satellite or a rock tied to the end of a string. Δs
change in arc length
ΔΘ = r
Angular displacement (radians)
radius

6. Angular Velocity ΔΘ ω = Δt
Angular speed is defined much like linear speed in which the displacement of the object is measured for a specific time interval. ΔΘ
omega
ω = Δt
angular displacement
angular speed (radians/second)
or revolutions per time
time

7. Angular Acceleration Δω α = Δt
While we are on the same path as linear motion, we can use linear acceleration to formulate an equation for angular acceleration. Δω
α = Δt
angular velocity (rad/s)
angular acceleration (rad/s2)
Time (s)

8. Rotational Kinematics
One Dimensional
Rotational
vf = vi + a Δt
ωf = ωi + αΔt
Δx = 1/2(vf + vi) Δt
ΔΘ = ½(ωf + ωi)Δt
vf2 = vi2 + 2aΔx
ωf2 = ωi2 + 2αΔΘ
Δx = viΔt + 1/2aΔt2
ΔΘ = ωiΔt + ½αΔt2

9. Tangential and Centripetal Acceleration
Section 7.2
Tangential and Centripetal Acceleration

10. Tangential v Centripetal
Tangential follows the guidelines of linear quantities.
So tangential speed is the instantaneous linear speed of an object traveling in a circle.
Tangential acceleration is the instantaneous linear acceleration of an object traveling in a circle.
Centripetal is a term associated with circular motion.
Centripetal means center-seeking.
Centrifugal means center-fleeing.

11. Tangential Speed vt = r ω Linear Δs ΔΘ = r Δt ω
Tangential speed is the thought that as an object is traveling in a circle, with what speed is it traveling linearly.
Or a more practical use would be if the object were to break its circular motion, what path would it travel?
Linear
So what would the initial velocity be of the object as it breaks from the circle?
arc length ΔΘ = Δs r
velocity Δt
Now solve for velocity by multiplying both sides by r. ω
vt = r ω
radius
This equation only works when ω is in radians per unit time.

12. Tangential Acceleration
Tangential acceleration is again that instant where the circular motion breaks and linear motion takes over.
So basically we are converting from circular to linear motion.
And remember that acceleration is just the rate of change of velocity.
vt = r ω
angular acceleration Δt
tangential acceleration
at = r α
Rate of change means divide by time.

13. Causes of Circular Motion
Section 7.3
Causes of Circular Motion

14. Centripetal v Centrifugal
Remember that centripetal means center seeking.
And centrifugal means center fleeing.

15. Acceleration in a Circle?
Recall that acceleration can occur in two ways
The magnitude of the velocity changes.
The direction of the velocity changes.
Now will we call it centripetal or centrifugal acceleration based on its direction?
Imagine a rock being swung on a string in a circular path.
And since the instantaneous velocity at those two points run tangential to the circle, we can draw vectors to represent the two different velocities and two different times.
Since acceleration is found by the change of velocity, we must have two different velocities and two different times.

16. Zoom In a Little vf vi Δv Δt a = vf - vi = Δt
We have found two different velocities at two different times so we can find the acceleration.
But we want to know the acceleration the instant the string would break, that way we can use our tangential velocity concept.
So we have found two velocities of the rock at the two times as close together as possible.
And now recall the formula for acceleration is finding the difference of the velocities over the time it took to change the velocity. vf vi Δv Δt
a =
vf - vi = Δt

17. Subtracting Vectors Graphically
Remember to place them head-to-head. vf
And the order is important to find the resultant, so draw the resultant from the final to the initial. vi Δv
And notice the change in velocity points toward the center. So the acceleration is seeking the center. So we call this
Centripetal Acceleration

18. Formula for Centripetal Acceleration
vt2
Use if you are given a tangential velocity. Usually identified by a unit of distance over time.
ac = r
Use if you are given angular velocity. That angular velocity must be in radians per time.
ac =
rω2

19. Total Acceleration aT = √(at2 + ac2)
The total acceleration takes the tangential acceleration and the centripetal acceleration into account at the same time.
That is because the tangential acceleration takes into account the changing speed and the centripetal acceleration takes into account the changing direction.
So,
aT = √(at2 + ac2)

20. Centripetal Force
Since acceleration is centripetal, the force must also be centripetal because it follows the direction of the acceleration.
So centripetal force is the force responsible for maintaining circular motion.
The reason you feel a force pulling out is because inertia is resisting the centripetal force of circular motion.

21. Formula for Centripetal Force
We derived our universal formula for force from Newton’s 2nd Law.
F = ma
Using a little substitution of the formulas for centripetal acceleration.
vt2
vt2
ac =
F = m r r
ac =
rω2
F = m
rω2

22. Newton’s Universal Law of Gravitation
Isaac Newton observed that planets are held in their orbits by a gravitational pull to the Sun and the other planets in the Solar System.
He went on to conclude that there is a mutual gravitational force between all particles of matter.
From that he saw that the attractive force was universal to all objects based on their mass and the distance they are apart from each other.
Because of its universal nature, there is a constant of universal gravitation for all objects.
G = x Nm2/kg2

23. Formula for Newton’s Universal Law of Gravitation
m1m2 G
Fg = r2
Force due to gravity. Same concept that we have seen before.
Constant of Universal Gravitation
Masses of the two objects.
Distance between the centers of mass of the two objects.