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Surface Area and Volume Review

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Presentation on theme: "Surface Area and Volume Review"— Presentation transcript:

1 Surface Area and Volume Review

2 What is the minimum amount of gift wrap you would need to wrap a box that is 10 inches long, 8 inches wide, and 6 inches in height? SA= 2lw+ 2lh+2wh SA= 2(10)(8)+2(10)(6)+2(8)(6) SA= SA= 376 in.2 of gift wrap

3 How much paint will this paint can hold if it is 8 inches in diameter and 12 inches in height?
V= πr2h V= 3.14(4)(4)(12) V= in.3 of paint

4 Approximately how much aluminum is needed to cover this soda can that has a radius of 2 inches and a height of 5 inches? SA=2πrh+2πr2 SA= 2(3.14)(2)(5)+2(3.14)(2)(2) SA= SA= in.2 of aluminum

5 V= lwh V= 4(3)(1) V= 12 ft.3 of sand
Approximately how much sand is needed to fill a sandbox that is 4 feet in length, 3 feet in width and 1 foot in height? V= lwh V= 4(3)(1) V= 12 ft.3 of sand

6 Approximately how much material would you need to recover a suitcase that is 20 inches in length, 6 inches in width, and 15 inches in height? SA= 2lw+ 2lh+2wh SA= 2(20)(6)+2(20)(15)+2(6)(15) SA= SA=1,020in.2 of material

7 V= lwh V= 22(14)(10) V= 3,080 ft.3 of water
How much water is needed to fill a rectangular pool with a length of 22 feet, width of 14 feet and height of 10 feet? V= lwh V= 22(14)(10) V= 3,080 ft.3 of water

8 How much liquid will this glass hold if it is 3 inches in diameter and 6 inches in height? Round to the nearest tenth. V= πr2h V= 3.14(1.5)(1.5)(6) V= 42.4 in.3 of liquid

9 Approximately how much paint is needed to cover this trash can that has a radius of 8 inches and a height of 20 inches? SA=2πrh+2πr2 SA= 2(3.14)(8)(20)+2(3.14)(8)(8) SA= SA= 1, in.2 of paint


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