1. The circumference of the circle is 50  feet. The area of the shaded region = ________ example 1 :

2. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet. 50

3. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet and the radius is 25 feet. 25 50

4. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet and the radius is 25 feet. 25 The area of the circle =  (25) 2 = 625  square feet 50 the area of the square = 50x50 = 2500 square feet

5. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet and the radius is 25 feet. 25 The area of the circle =  (25) 2 = 625  square feet 50 2500 square feet - 625  square feet

6. The circumference of the circle is 50  feet. The area of the shaded region =(2500 - 625  ) square feet C =  d = 50  therefore the diameter of the circle is 50 feet and the radius is 25 feet. 25 The area of the circle =  (25) 2 = 625  square feet 50 2500 square feet - 625  square feet

7. The circumference of the circle is 50  feet. The area of the shaded region = ________ example 2 :

8. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet.

9. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet. x x Let x = the side of the square 50

10. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet. x x Let x = the side of the square 50 x 2 + x 2 = 50 2 = 2500 x 2 = 1250 = the area of the square area of circle = 625 

11. The circumference of the circle is 50  feet. The area of the shaded region = ________ C =  d = 50  therefore the diameter of the circle is 50 feet. x x Let x = the side of the square 50 x 2 + x 2 = 50 2 = 2500 x 2 = 1250 = the area of the square area of circle = 625  - area of square = 1250

12. The circumference of the circle is 50  feet. The area of the shaded region =(625  - 1250) sq feet C =  d = 50  therefore the diameter of the circle is 50 feet. x x Let x = the side of the square 50 x 2 + x 2 = 50 2 = 2500 x 2 = 1250 = the area of the square area of circle = 625  - area of square = 1250

13. example 3 : A B AB = 30 feet 30 What is the SUM of the areas of the purple squares?_________

14. example 3 : A B AB = 30 feet 30 What is the SUM of the areas of the purple squares?_________ x x y y Let x = the length of the side of the large square and let y = the length of the side of the small square

15. example 3 : A B AB = 30 feet 30 What is the SUM of the areas of the purple squares? x 2 + y 2 x x y y Let x = the length of the side of the large square and let y = the length of the side of the small square Area = x 2 Area = y 2

16. example 3 : A B AB = 30 feet 30 What is the SUM of the areas of the purple squares? x 2 + y 2 = 30 2 = 900 sq ft x x y Let x = the length of the side of the large square and let y = the length of the side of the small square Area = x 2 Area = y 2 y

17. example 4 : 7 feet 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ____________

18. example 4 : 7 feet 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is ____________ The area of a triangle = ½ height x base 14 = ½ height x 7 28 = height x 7 4 = height

19. example 4 : 7 feet 10 feet If the area of the triangle is 14 square feet, then the area of the rectangle is 10 x 4 = 40 sq ft The area of a triangle = ½ height x base 14 = ½ height x 7 28 = height x 7 4 = height 4