1. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success

2. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female

3. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female b. Components of fitness:

4. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female b. Components of fitness - probability of female surviving to reproductive age

5. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female b. Components of fitness - probability of female surviving to reproductive age - number of offspring the female produces

6. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female b. Components of fitness - probability of female surviving to reproductive age - number of offspring the female produces - probability that offspring survive to reproductive age

7. II. Deviations from HWE A. Mutation B. Migration C. Non-Random Mating D. Genetic Drift - Sampling Error E. Selection 1. Measuring “fitness” – differential reproductive success a. The mean number of reproducing offspring (or females)/female b. Components of fitness - probability of female surviving to reproductive age - number of offspring the female produces - probability that offspring survive to reproductive age c. With a limited energy budget, selection cannot maximize all three components… there will necessarily be TRADE-OFFS.

8. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets

9. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets GROWTH METABOLISM REPRODUCTION

10. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets GROWTH METABOLISM REPRODUCTION Maximize probability of survival GROWTH METABOLISM REPRODUCTION Maximize reproduction

11. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets METABOLISM REPRODUCTION METABOLISM REPRODUCTION Trade-offs within reproduction Lots of small, low prob of survival A few large, high prob of survival

12. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets 3. Modeling Selection

13. Selection for a Dominant Allele p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00

14. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 3. Modeling Selection Selection for a Dominant Allele

15. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 3. Modeling Selection Selection for a Dominant Allele

16. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 3. Modeling Selection Selection for a Dominant Allele

17. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 = 0.73 3. Modeling Selection Selection for a Dominant Allele

18. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 = 0.73 Geno. Freq., breeders0.220.660.12 = 1.00 3. Modeling Selection Selection for a Dominant Allele

19. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 = 0.73 Geno. Freq., breeders0.220.660.12 = 1.00 Gene Freq's, gene poolp = 0.55q = 0.45 3. Modeling Selection Selection for a Dominant Allele

20. p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.8 0.2 Relative Fitness110.25 Survival to Reproduction0.160.480.09 = 0.73 Geno. Freq., breeders0.220.660.12 = 1.00 Gene Freq's, gene poolp = 0.55q = 0.45 Genotypes, F10.30250.4950.2025 = 100 3. Modeling Selection Selection for a Dominant Allele

21. 3. Modeling Selection Selection for a Dominant Allele Δp declines with each generation.

22. 3. Modeling Selection Selection for a Dominant Allele Δp declines with each generation. BECAUSE: as q declines, a greater proportion of q alleles are present in heterozygotes (and invisible to selection). As q declines, q 2 declines more rapidly...

23. 3. Modeling Selection Selection for a Dominant Allele Δp declines with each generation. So, in large populations, it is hard for selection to completely eliminate a deleterious allele....

24. 3. Modeling Selection Selection for a Dominant Allele Δp declines with each generation. Rate of change depends on the strength of selection; the difference in reproductive success among genotypes. In this case, a new adaptive mutant allele has been produced in the population. The “selection differential”, s, is selection AGAINST the existing allele that had become ‘fixed’ in the population (f = 1.0) So, the “better” the new allele is (represented by the greater selective differential against the old allele), the faster the new mutant accumulates in the population.

25. 3. Modeling Selection Selection for a Dominant Allele Selection for an allele where there is not complete dominance: - Consider incomplete dominance, codominance, or heterosis. In these situations, the heterozygote has a phenotype that differs from either of the homozygotes, and selection can favor one genotype over another: - Selection might favor one homozygote over the heterozygote and other homozygote (first example), or might favor the heterozygote over the homozygotes (second example), or might favor both homozygotes over the heterozygote (not considered here).

26. Selection for the homozygote of a ‘non-dominant’ allele (incomplete dominance, codominance, overdominance) p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.80.40.2 Relative Fitness10.50.25 Survival to Reproduction0.160.240.09 = 0.49 Geno. Freq., breeders0.330..500.17 = 1.00 Gene Freq's, gene poolp = 0.58q = 0.42 Genotypes, F10.340.480.18 = 100

27. Selection for the homozygote of a non-dominant allele - deleterious alleles can no longer hide in the heterozygote; its presence always causes a reduction in fitness, and so it can be eliminated from a population (if the heterozygote is less ‘fit’ than the AA).

28. Selection for the heterozygote p = 0.4, q = 0.6AAAaaa Parental "zygotes"0.160.480.36 = 1.00 prob. of survival (fitness)0.40.80.2 Relative Fitness0.5 (1-s)10.25 (1-t) Survival to Reproduction0.080.480.09 = 0.65 Geno. Freq., breeders0.120.740.14 = 1.00 Gene Freq's, gene poolp = 0.49q = 0.51 Genotypes, F10.240.500.26 = 100 AAAaaa Maintains both genes in the gene pool p eq = t/s+t = 0.75/1.25 = 0.6

29. Maintains both genes in the gene pool p eq = t/s+t = 0.75/1.25 = 0.6

30. Selection for the Heterozygote Sickle cell caused by a SNP of valine for glutamic acid at the 6 th position in the beta globin protein in hemoglobin (147 amino acids long). The malarial parasite (Plasmodium falciparum) cannot complete development in red blood cells with this hemoglobin, because O 2 levels are too low in these cells. NNNSSS

31. E. Selection 1. Measuring “fitness” – differential reproductive success 2. Relationships with Energy Budgets 3. Modeling Selection 4. Types of Selection - Selection acts on phenotypes, which may be single gene traits, polygenic quantitative traits, and/or effected by epistatic interactions. - The different effects are measured by changes in the mean phenotype over time.

32. E. Selection 4. Types of Selection - Directional

33. E. Selection 4. Types of Selection - Directional

34. E. Selection 4. Types of Selection - Stabilizing

35. E. Selection 4. Types of Selection - Disruptive Lab experiment – “bidirectional selection” – create two lines by directionally selecting for extremes. Populations are ‘isolated’ and don’t reproduce.

36. E. Selection 4. Types of Selection - Disruptive African Fire-Bellied Seed Crackers