1. Critique 3 Adam Boney, Fraser Cassels, Marc Breslin and Nick Burns

2. Our Design 1 st Floor

3. Building Fabric West FacadeSouthern Facade Thermal Envelope around building : Excludes garage and front porch as these spaces will be rarely occupied so don’t require to be heated. This will also minimize draughts and help reduce thermal bridging

4. Building Fabric Section similar to the design of our wall consists of: Timber cladding, k – 0.18 W/m K, 14mm Battens 40 x 40 Isolair L sarking board, 0.047 W/m K, 22mm Double timber stud work 288 mm with cellulose insulation, 0.035 W/m K, 280 mm Racking board, 12mm Service void 30 mm Plasterboard, 0.16 W/m K, 12mm OuterInner Calculations for U value : R = thickness/ thermal conductivity U Value = 1 / ∑ R Ro = 0.014/ 0.18 = 0.077 Ri = 0.012/ 0.16 = 0.075 R1 = 0.022/ 0.047 = 0.49 R2 = 0.280/ 0.035 = 8 R3 = (0.030 + 0.040)/ 0.025 = 2.8 Rtot = 11.442 U value = 1 / 11.442 = 0.09 W / m 2 K Typical Wall :

5. Building fabric Roof Design : Similar floor: Section is constructed from : Slates, 2 W/m K, 5mm Battens 40 x 40 Isolair L sarking board, 0.047 W/ m K, 60 mm Pavatherm insulation board, 0.038 W/ m K, 80 mm Osb 12mm 175 mm Rafters with sheep’s wool insulation, 0.038 W/m K OSB 12 mm Service void 30 mm Platerboard, 0.016 W/ m K, 12mm U Value of 0.10 W / m 2 K Section constructed from : Flooring finish Fermacell 2 x 12mm Pavatherm, 0.038 W/ m K, 50mm Vapour barrier 220mm Floor joists with 200mm sheep’s wool insulation 0.038 W/ m K Vapour barrier 200 mm air barrier U value of 0.07 W / m 2 K

6. Building fabric Windows: Ecopassiv windows are triple glazed Whole window U value – 0.75 W / m 2 K Warm edge spacers Polyurethane frame insulation Argon fill 44mm Doors: Frostkorken doors which are triple glazed Door whole U value of 0.72 W / m 2 K Incorporates cork frame insulation to reduce thermal bridging High performance seals and extruders fitted to prevent draughts

7. Demand - Heating Fabric heat loss = Area x U-value x Temperature Difference = 8751 kWh/yr Ventilation heat loss = mass flow rate x C p x Temperature Difference =3759.5 kWh/yr

8. Demand - Heating Gains: Passive: = 5840 kWh/yr Total Gains = 8761.25 Solar : = 2921.25 kWh/yr Difference = Gains – Loss = -366.06kWh/yr

9. Demands – Hot water Outside Air Temperature 10 ̊C Temperature of hot water 45 ̊C Hot water demand = 163 litres/day Assume usage = 5 hours m = 0.009 kg/s C p = 4187 Q = m * C p * ∆t * ŋ ∆t = 35 °C Q =3229.146 kWh/yr ŋ = 0.75

10. Demand – Weekday Energy

11. Demand – Weekend Energy

12. Demand – Appliances

13. Total Energy Demand Total Energy Needed = Appliances + Hot water + Heating = 4646.7983 + 3229.146 + 366.06 = 8242.004 kWh/yr required

14. Power calculation formula: Worked example- P=ρAV³xCp http://www.raeng.org.uk

15. Turbine options:

16. Total demand data: Total demand= Appliance demand + hot water demand +Heating demand = 8242.004 kWh/yr

17. Turbine selection: Having calculated the potential total annual demand for building we can select a suitable size of turbine to meet this demand. We have opted for : - 10kW Westwind Turbine. - Producing ~12500kwh/yr. - 6.2m diameter blade. (taken from http://www.westwindturbines.co.uk)

18. Turbine selection: The selected turbine satisfies the annual demand however there is the possibility that it may not meet a particular monthly demand. We have opted for a turbine with a higher output than required. Should this occur we will look to recover the power loss via a - PV system. - Power storage system.

19. Power storage from turbine: There is a potential to store power generated from the chosen turbine. Variety of ways to store power- 1. Battery storage 2. Compressed air storage 3. Hydrogen Storage These three types will be investigated and the most suitable selected.

20. Water – from last time Above ground storage tank Rainwater harvesting systems

21. Water Using correct numbers for water usage from Code for Sustainable Homes, taking: Water required = 60L/day/person = 109,500 L/year Water yield = 152.29m 2 x 1,220mm x 0.75 x 85% = 118,444 L/year So rainwater should yield enough to meet water demands

22. Water – grey water recycling Waste water from bathtub, shower and wash-basin will be filtered and put back into use This will require a secondary filtering process for grey water

23. Water – black water disposal Sewage will be disposed of using a reed bed system Water passing through the reed bed is cleaned by micro-organisms

24. Whats nexts MVHR completion Storage systems Savings Cost