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5-5 Solving Proportions Warm Up Problem of the Day Lesson Presentation
Course 2 Warm Up Problem of the Day Lesson Presentation
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions Warm Up Find the unit rate. 1. 18 miles in 3 hours 2. 6 apples for $3.30 3. 3 cans for $0.87 4. 5 CD’s for $43 6 mi/h $0.55 per apple $0.29 per can $8.60 per CD
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Vocabulary 5-4 Identifying and Writing Proportions equivalent ratios
Course 2 5-4 Identifying and Writing Proportions Vocabulary equivalent ratios proportion
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Quick activity In your group measure the length and width of each others heads. Length= Width=
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions Students in Mr. Howell’s math class are measuring the width w and the length l of their heads. The ratio of l to w is 10 inches to 6 inches for Jean and 25 centimeters to 15 centimeters for Pat.
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions 10 6 25 15 These ratios can be written as the fractions and . Since both simplify to , they are equivalent. Equivalent ratios are ratios that name the same comparison. 5 3
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions An equation stating that two ratios are equivalent is called a proportion. The equation, or proportion, below states that the ratios and are equivalent. 10 6 25 15 10 6 25 15 = Read the proportion by saying “ten is to six as twenty-five is to fifteen.” Reading Math 10 6 = 25 15
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Additional Example 1A: Comparing Ratios in Simplest Forms
Course 2 5-4 Identifying and Writing Proportions Additional Example 1A: Comparing Ratios in Simplest Forms Determine whether the ratios are proportional. 24 51 , 72 128 Simplify . 24 51 24 ÷ 3 51 ÷ 3 = 8 17 72 ÷ 8 128 ÷ 8 = 9 16 Simplify 72 128 8 17 Since = , the ratios are not proportional. 9 16
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions Check It Out: Example 1A Determine whether the ratios are proportional. 54 63 , 72 144 Simplify . 54 63 54 ÷ 9 63 ÷ 9 = 6 7 72 ÷ 72 144 ÷ 72 = 1 2 Simplify 72 144 6 7 Since = , the ratios are not proportional. 1 2
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Identifying and Writing Proportions
Course 2 5-4 Identifying and Writing Proportions Check It Out: Example 1B Determine whether the ratios are proportional. 135 75 , 9 4 135 ÷ 15 75 ÷ 15 = 9 5 Simplify 135 75 9 4 is already in simplest form. 9 4 9 5 Since = , the ratios are not proportional. 4
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Identifying and Writing Proportions Insert Lesson Title Here
Course 2 5-4 Identifying and Writing Proportions Insert Lesson Title Here Lesson Quiz: In pre-school, there are 5 children for every one teacher. In another preschool there are 20 children for every 4 teachers. Determine whether the ratios of children to teachers are proportional in both preschools. 20 4 5 1 =
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5-5 Solving Proportions Quick check
Course 2 5-5 Solving Proportions Quick check Determine whether the ratios are proportional. 5 8 15 24 1. , yes 12 15 16 25 2. , no 15 10 , 20 16 3. no 14 18 , 42 54 4. yes
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Course 2 5-5 Solving Proportions Learn to solve proportions by using cross products.
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Insert Lesson Title Here
Course 2 5-5 Solving Proportions Insert Lesson Title Here Vocabulary cross product
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5 · 6 = 30 6 2 = 15 5 2 · 15 = 30 5-5 Solving Proportions
Course 2 5-5 Solving Proportions For two ratios, the product of the numerator in one ratio and the denominator in the other is a cross product. If the cross products of the ratios are equal, then the ratios form a proportion. 5 · 6 = 30 = 2 5 6 15 2 · 15 = 30
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5-5 Solving Proportions a c In the proportion = , the cross products,
Course 2 5-5 Solving Proportions CROSS PRODUCT RULE In the proportion = , the cross products, a · d and b · c are equal. a b c d You can use the cross product rule to solve proportions with variables.
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Additional Example 1: Solving Proportions Using Cross Products
Course 2 5-5 Solving Proportions Additional Example 1: Solving Proportions Using Cross Products Use cross products to solve the proportion. = m 5 9 15 15 · m = 9 · 5 The cross products are equal. 15m = 45 Multiply. 15m 15 = 45 15 Divide each side by 15 to isolate the variable. m = 3
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Insert Lesson Title Here
Course 2 5-5 Solving Proportions Insert Lesson Title Here Check It Out: Example 1 Use cross products to solve the proportion. 6 7 = m 14 7 · m = 6 · 14 The cross products are equal. 7m = 84 Multiply. 7m 7 84 7 = Divide each side by 7 to isolate the variable. m = 12
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Understand the Problem
Course 2 5-5 Solving Proportions Additional Example 2: Problem Solving Application If 3 volumes of Jennifer’s encyclopedia takes up 4 inches of space on her shelf, how much space will she need for all 26 volumes? 1 Understand the Problem Rewrite the question as a statement. Find the space needed for 26 volumes of the encyclopedia. List the important information: 3 volumes of the encyclopedia take up 4 inches of space.
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Additional Example 2 Continued
Course 2 5-5 Solving Proportions Additional Example 2 Continued 2 Make a Plan Set up a proportion using the given information. Let x represent the inches of space needed. 3 volumes 4 inches 26 volumes x volumes inches =
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Additional Example 2 Continued
Course 2 5-5 Solving Proportions Additional Example 2 Continued Solve 3 3 4 26 x Write the proportion. = 3 · x = 4 · 26 The cross products are equal. 3x = 104 Multiply. 3x 3 104 3 Divide each side by 3 to isolate the variable. = 2 3 x = 34 2 3 She needs 34 inches for all 26 volumes.
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Additional Example 2 Continued
Course 2 5-5 Solving Proportions Additional Example 2 Continued 4 Look Back 4 · 26 = 104 26 3 4 = 2 3 34 3 · 34 2 3 = 104 The cross products are equal, so 34 2 3 is the answer
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Understand the Problem
Course 2 5-5 Solving Proportions Check It Out: Example 2 John filled his new radiator with 6 pints of coolant, which is the 10 inch mark. How many pints of coolant would be needed to fill the radiator to the 25 inch level? 1 Understand the Problem Rewrite the question as a statement. Find the number of pints of coolant required to raise the level to the 25 inch level. List the important information: 6 pints is the 10 inch mark.
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Check It Out: Example 2 Continued
Course 2 5-5 Solving Proportions Check It Out: Example 2 Continued 2 Make a Plan Set up a proportion using the given information. Let p represent the pints of coolant. 6 pints 10 inches p 25 inches pints inches =
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Check It Out: Example 2 Continued
Course 2 5-5 Solving Proportions Check It Out: Example 2 Continued Solve 3 6 10 p 25 Write the proportion. = 10 · x = 6 · 25 The cross products are equal. 10x = 150 Multiply. 10x 10 150 10 Divide each side by 10 to isolate the variable. = p = 15 15 pints of coolant will fill the radiator to the 25 inch level.
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Check It Out: Example 2 Continued
Course 2 5-5 Solving Proportions Check It Out: Example 2 Continued 4 Look Back 10 · 15 = 150 6 10 15 = 25 6 · 25 = 150 The cross products are equal, so 15 is the answer.
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Insert Lesson Title Here
Course 2 5-5 Solving Proportions Insert Lesson Title Here Lesson Quiz: Part I Use cross products to solve the proportion. 25 20 45 t 1. = t = 36 2. x 9 = 19 57 x = 3 2 3 r 36 3. = r = 24 n 10 28 8 4. = n = 35
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Insert Lesson Title Here
Course 2 5-5 Solving Proportions Insert Lesson Title Here Lesson Quiz: Part II 5. Carmen bought 3 pounds of bananas for $1.08. June paid $ 1.80 for her purchase of bananas. If they paid the same price per pound, how many pounds did June buy? 5 pounds
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