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A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.
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A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.
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A jogger runs 145m in a direction 20
A jogger runs 145m in a direction 20.0 degrees east of north (vector A), and then runs 105m in a direction 35.0 degrees south of east (vector B). Using components, determine the magnitude and direction of the resultant vector C for these two displacements.
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Sin 20 = Ax / 145 Ax = 49.6 m Cos 35 = Bx/105 Bx = 86.0 m Ax + Bx = m
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cos 20 = Ay / 145 Ay = m sin 35 = Bx/105 By = 60.2 m Ay - By = 75.8 m
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= C2 C = 155m tan angle = 75.8/135.6 angle = 29 degrees
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