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Chapter 2 – kinematics of particles
Tuesday, September 1, 2015: Lecture 4 Today’s Objective: Curvilinear motion Normal and Tangential Components
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Coordinate Systems
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Plane Curvilinear Motion: Velocity
Note the direction of acceleration. It’s not predictable!
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Acceleration Note: The curve isn’t the path of the particle, it’s a plot of the velocity!
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Rectangular Vector Coordinates
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Normal and Tangential Coordinates
Used when Motion is along a curve n-t coordinates are most effective ds = ρ dβ, ds/dt = ρ dβ/dt = ρ v
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Normal and Tangential Coordinates
From Fig 2, as dv approaches 0, the direction of dv becomes perpendicular to the tangent a = v det/dt + dv/dt et The second term on the r.h.s. represents acceleration component in the tangential direction In the 1st term on RHS, et has a magnitude of 1, but the direction is changing with the motion, so this is not a constant vector and det/dt ≠0 Fig 1 Fig 2
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Normal and Tangential Coordinates
Let us find what is det/dt det = dß (et = 1) en det/dt= dß/dt en The direction of et is along the tangent to the curve, where as, det points toward the center of the curve. det/dt = angular velocity (dß/dt) x en = (w 𝜌)en =𝑣/𝜌 en dß/dt = angular velocity of the particle = w = v/ρ
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Normal and Tangential Coordinates
Circular Motion a = v det/dt + dv/dt et = (v) (v/ρ) en + dv/dt et = v2/ρ en + at et a = an en +at et For a circular motion, v = r 𝑑𝜃 𝑑𝑡 Or d𝜃/𝑑𝑡 = v/r 𝜃 𝑎𝑛𝑑 𝛽 𝑎𝑟𝑒 𝑢𝑠𝑒𝑑 𝑖𝑛𝑡𝑒𝑟𝑐ℎ𝑎𝑛𝑔𝑒𝑎𝑏𝑙𝑦
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Problem Given: N = 45 rpm. Find v and a of point A.
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Problem 2.122 Given: The particle P starts from rest at point A at time t = 0 and changes its speed thereafter at a constant rate of 2g as it follows the horizontal path as shown. Determine the magnitude and direction of its total acceleration: Just after point B, and At point C
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