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Section 5-2 Bisectors in Triangles. Vocabulary Distance from a point to a line: the length of the perpendicular segment from the point to the line.

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Presentation on theme: "Section 5-2 Bisectors in Triangles. Vocabulary Distance from a point to a line: the length of the perpendicular segment from the point to the line."— Presentation transcript:

1 Section 5-2 Bisectors in Triangles

2 Vocabulary Distance from a point to a line: the length of the perpendicular segment from the point to the line.

3 Theorems Perpendicular Bisector Theorem- If a point lies on the perpendicular bisector of a line segment, then it is an equal distance away from both endpoints of the line segment. Angle Bisector Theorem- If a point lies on the angle bisector of an angle, then it is an equal distance away from both sides of the angle.

4 Converse of the Theorems Converse of the Perpendicular Bisector Theorem- If a point is an equal distance away from the endpoints of a line segment, then it lies on the perpendicular bisector of the line segment. Converse of the Angle Bisector Theorem- If a point in the interior of an angle is an equal distance away from both sides of the angle, then it lies on the angle bisector of the angle.

5 Perpendicular Bisector Theorem

6 Angle Bisector Theorem

7 Proof of Perpendicular Bisector Theorem StatementReason BD is the ┴ bisector of AC Given ∠ABD and ∠CBD are right angles Definition of perpendicular ∠ABD ≅ ∠CBD All right angles are congruent DB ≅ DB Reflexive Property of Congruency AB ≅ CB Definition of bisector ∆ABD ≅ ∆CBD SAS AD ≅ CD CPCTC

8 Proof of Angle Bisector Theorem StatementReason AD is the angle bisector of ∠CAB Given CD is ┴ to AC By construction DB is ┴ to AB By construction ∠ACB and ∠ABD are right angles Definition of perpendicular ∠ACB ≅ ∠ABD All right angles are congruent ∠CAD ≅ ∠BAD Definition of angle bisector AD ≅ AD Reflexive Property pf Congruency ∆CAD ≅ ∆BAD AAS CD ≅ BD CPCTC

9 Practice Problem Given: BE is the perpendicular bisector of AC, ∠AED ≅ ∠CEF, DE ≅ FE. Prove: ∠DAE ≅ ∠FCE Answer on next slide⫸

10 Solution to Practice Problem StatementReason BE is ┴ bisector of ACGiven AE ≅ CE Perpendicular Bisector Theorem DE ≅ FE Given ∠AED ≅ ∠CEF Given ∆ADE ≅ ∆CFE SAS ∠DAE ≅ ∠FCE CPCTC

11 Practice Problem 2 Find the value of X and Y Answer on next slide⫸

12 Solution to Practice Problem 2 Answer: X = -3, Y = 12

13 Extra Resources http://www.youtube.com/watch?v=oskp0T8aZJw (very weird jumpy guy explaining the perpendicular bisector theorem) http://www.youtube.com/watch?v=oskp0T8aZJw http://www.youtube.com/watch?v=9k8QMHIFwOk&list=PL66 8AB35C6885A036&index=35 (same weird guy explaining the angle bisector theorem) http://www.youtube.com/watch?v=9k8QMHIFwOk&list=PL66 8AB35C6885A036&index=35


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