1. Medical devices, based on the principles of wave optics
The Nature of Light
Chapter Five
Medical devices, based on the principles of wave optics

2. Plan Nature of light Thermal radiation Black body radiation
Stefan-Boltzman law
Wien’s law
Absorbtion
Polarization

3. Speed of Light
In 1850 Fizeau and Foucalt also experimented with light by bouncing it off a rotating mirror and measuring time
The light returned to its source at a slightly different position because the mirror has moved during the time light was traveling
The deflection angle depends on the speed of light and the dimensions of the apparatus.

4. Light: spectrum and color
Newton found that the white light from the Sun is composed of light of different color, or spectrum (1670).

5. Light has wavelike property
Young’s Double-Slit Experiment indicated light behaved as a wave (1801)
The alternating black and bright bands appearing on the screen is analogous to the water waves that pass through a barrier with two openings

6. Light is Electromagnetic Radiation
The nature of light is electromagnetic radiation
In the 1860s, James Clerk Maxwell succeeded in describing all the basic properties of electricity and magnetism in four equations: the Maxwell equations of electromagnetism.

7. Light: Wavelength and Frequency
Example
FM radio, e.g., MHz (WTOP station) => λ = 2.90 m
Visible light, e.g., red 700 nm => ν = 4.29 X 1014 Hz
The speed of light in the vacuum
C = 299, km/s, or
C = 3.00 X 105 km/s = 3.00·108 m/s

8. Electromagnetic Spectrum
Visible light falls in the 400 to 700 nm range
In the order of decreasing wavelength
Radio waves: 1 m
Microwave: 1 mm
Infrared radiation: 1 μm
Visible light: 500 nm
Ultraviolet radiation: 100 nm
X-rays: 1 nm
Gamma rays: 10-3 nm

9. Radiation depending on Temperature
A general rule:
The higher an object’s temperature, the more intensely the object emits electromagnetic radiation and the shorter the wavelength at which emits most strongly
The example of heated iron bar. As the temperature increases
The bar glows more brightly
The color of the bar also changes

10. Thermal radiation is electromagnetic radiation emitted from the surface of an object which is due to the object's temperature. An example of thermal radiation is the infrared radiation emitted by hot objects. A person near a fire will feel the radiated heat of the fire, even if the surrounding air is very cold. You cannot see the thermal radiation but you can see other energies.

11. ? How does the sun warm you on a hot day? infrared radiation
Earth is warmed by heat energy from the Sun.
How does this heat energy travel from the Sun to the Earth? ?
infrared
radiation
There are no particles between the Sun and the Earth so the heat cannot travel by conduction or by convection.
The heat travels to Earth by infrared waves. They are similar to light waves and are able to travel through empty space.

12. INFRARED WAVES Heat can move by travelling as infrared waves.
These are electromagnetic waves, like light waves, but with a longer wavelength.
This means that infrared waves act like light waves:
They can travel through a vacuum.
They travel at the same speed as light – 300,000,000 m/s.
They can be reflected and absorbed.
Infrared waves heat objects that absorb them and so can be called thermal radiation.

13. Radiation in Equilibrium with Matter
Typically, radiation emitted by a hot body, or from a laser is not in equilibrium: energy is flowing outwards and must be replenished from some source. The first step towards understanding of radiation being in equilibrium with matter was made by Kirchhoff, who considered a cavity filled with radiation, the walls can be regarded as a heat bath for radiation.
The walls emit and absorb e.-m. waves. In equilibrium, the walls and radiation must have the same temperature T. The energy of radiation is spread over a range of frequencies, and we define uS (,T) d as the energy density (per unit volume) of the radiation with frequencies between  and +d. uS(,T) is the spectral energy density. The internal energy of the photon gas:

14. In equilibrium, uS (,T) is the same everywhere in the cavity, and is a function of frequency and temperature only. If the cavity volume increases at T=const, the internal energy U = u (T) V also increases. The essential difference between the photon gas and the ideal gas of molecules: for an ideal gas, an isothermal expansion would conserve the gas energy, whereas for the photon gas, it is the energy density which is unchanged, the number of photons is not conserved, but proportional to volume in an isothermal change.
A real surface absorbs only a fraction of the radiation falling on it. The absorptivity  is a function of  and T; a surface for which ( ) =1 for all frequencies is called a black body.

15. Blackbody Radiation
A blackbody is a hypothetical object that is a perfect absorber of electromagnetic radiation at all wavelengths
The radiation of a blackbody is entirely the result of its temperature
A blackbody does not reflect any light at all
Blackbody curve: the intensities of radiation emitted at various wavelengths by a blackbody at a given temperature
The higher the temperature, the shorter the peak wavelength
The higher the temperature, the higher the intensity
Blackbody curve

16. Blackbody Radiation Hot and dense objects act like a blackbody
Stars, which are opaque gas ball, closely approximate the behavior of blackbodies
The Sun’s radiation is remarkably close to that from a blackbody at a temperature of 5800 K
A human body at room temperature emits most strongly at infrared light
The Sun as a Blackbody

17. Three Temperature Scales
Temperature in unit of Kelvin is often used in physics
TK = TC +273
TF = 1.8 (TC+32)

18. Blackbody Radiation
Blackbody – a perfect emitter & absorber of radiation; it absorbs all incident radiation, and no surface can emit more for a given temperature and wavelength
Emits radiation uniformly in all directions – no directional distribution – it’s diffuse
Example of a blackbody: large cavity with a small hole Joseph Stefan (1879)– total radiation emission per unit time & area over all wavelengths and in all directions:
s=Stefan-Boltzmann constant =5.67 x10-8 W/m2K4

19. Blackbody radiation: Stefan-Boltzmann Law
The Stefan-Boltzmann law states that a blackbody radiates electromagnetic waves with a total energy flux F directly proportional to the fourth power of the Kelvin temperature T of the object:
F = T4
F = energy flux, in joules per square meter of surface per second
 = Stefan-Boltzmann constant = 5.67 X 10-8 W m-2 K-4
T = object’s temperature, in kelvins

20. Planck’s Distribution Law
Sometimes we care about the radiation in a certain wavelength interval
For a surface in a vacuum or gas
Integrating this function over all l gives us

21. Blackbody Radiation: Wien’s Law
Wien’s law states that the dominant wavelength at which a blackbody emits electromagnetic radiation is inversely proportional to the Kelvin temperature of the object
For example
The Sun, λmax = 500 nm  T = 5800 K
Human body at 37 degrees Celcius, or 310 Kelvin  λmax = 9.35 μm = 9350 nm

22. Dual properties of Light: (1) waves and (2) particles
Light is an electromagnetic radiation wave, e.g, Young’s double slit experiment
Light is also a particle-like packet of energy - photon
Light particle is called photon
The energy of phone is related to the wavelength of light
Light has a dual personality; it behaves as a stream of particle like photons, but each photon has wavelike properties

23. Dual properties of Light: Planck’s Law
Planck’s law relates the energy of a photon to its wavelength or frequency
E = energy of a photon
h = Planck’s constant
= x 10–34 J s
c = speed of light
λ= wavelength of light
Energy of photon is inversely proportional to the wavelength of light
Example: 633-nm red-light photon
E = 3.14 x 10–19 J
or E = 1.96 eV
eV: electron volt, a small energy unit = x 10–19 J

24. Kirchhoff’s Laws on Spectrum
Three different spectrum: continuous spectrum, emission-line spectrum, and absorption line spectrum

25. Kirchhoff’s Laws on Spectrum
Law 1- Continuous spectrum: a hot opaque body, such as a perfect blackbody, produce a continuous spectrum – a complete rainbow of colors without any spectral line
Law 2 – emission line spectrum: a hot, transparent gas produces an emission line spectrum – a series of bright spectral lines against a dark background
Law 3 – absorption line spectrum: a relatively cool, transparent gas in front of a source of a continuous spectrum produces an absorption line spectrum – a series of dark spectral lines amongst the colors of the continuous spectrum. Further, the dark lines of a particular gas occur at exactly the same wavelength as the bright lines of that same gas.

26. Polarizers and analysers
A polarizer (like polaroid) can be used to polarize light

27. Polarizers and analysers
A polarizer can also be used to determine if light is polarized. It is then called an analyser.

28. Malus’ Law
The intensity of polarised light that passes through a polarizer is proportional to the square of the cosine of the angle between the electric field of the polarized light and the angle of the polarizer!

29. Malus’ law
I = Iocos2θ Io
Iocos2θ

30. Optical activity
Some substances can change the plane of polarized light. We say they are optically active

31. Optical activity
Sugar solution is optically active. The amount of rotation of the plane of polarization depends on the concentration of the solution.

32. Interference and Diffraction

33. Diffraction of Light
Diffraction is the ability of light waves to bend around obstacles placed in their path.
Ocean
Beach
Fuzzy Shadow
Light rays
Water waves easily bend around obstacles, but light waves also bend, as evidenced by the lack of a sharp shadow on the wall.

34. Water Waves
A wave generator sends periodic water waves into a barrier with a small gap, as shown below.
A new set of waves is observed emerging from the gap to the wall.

35. Interference of Water Waves
An interference pattern is set up by water waves leaving two slits at the same instant.

36. Young’s Experiment
In Young’s experiment, light from a monochromatic source falls on two slits, setting up an interference pattern analogous to that with water waves.
Light source S1 S2

37. The Superposition Principle
The resultant displacement of two simul-taneous waves (blue and green) is the algebraic sum of the two displacements.
The composite wave is shown in yellow.
Constructive Interference
Destructive Interference
The superposition of two coherent light waves results in light and dark fringes on a screen.

38. Young’s Interference Pattern
Constructive
Bright fringe
Destructive
Dark fringe
Constructive
Bright fringe

39. Conditions for Bright Fringes
Bright fringes occur when the difference in path Dp is an integral multiple of one wave length l. l l l p1 p2 p3 p4
Path difference
Dp = 0, l , 2l, 3l, …
Bright fringes: Dp = nl, n = 0, 1, 2, . . .

40. Conditions for Dark Fringes
Dark fringes occur when the difference in path Dp is an odd multiple of one-half of a wave length l/2. l l p1
n = odd
n = 1,3,5 … p2 p3 p3
Dark fringes:

41. Analytical Methods for Fringesx y
d sin q s1 s2 d q p1 p2
Dp = p1 – p2
Dp = d sin q
Path difference determines light and dark pattern.
Bright fringes: d sin q = nl, n = 0, 1, 2, 3, . . .
Dark fringes: d sin q = nl/2 , n = 1, 3, 5, . . .

42. Analytical Methods (Cont.)x y
d sin q s1 s2 d q p1 p2
From geometry, we recall that:
So that . . .
Bright fringes:
Dark fringes:

43. Example 1: Two slits are 0. 08 mm apart, and the screen is 2 m away
Example 1: Two slits are 0.08 mm apart, and the screen is 2 m away. How far is the third dark fringe located from the central maximum if light of wavelength 600 nm is used? x y
d sin q s1 s2 q
n = 1, 3, 5
x = 2 m; d = 0.08 mm
l = 600 nm; y = ?
d sin q = 5(l/2)
The third dark fringe occurs when n = 5
Dark fringes:

44. Example 1 (Cont. ): Two slits are 0
Example 1 (Cont.): Two slits are 0.08 mm apart, and the screen is 2 m away. How far is the third dark fringe located from the central maximum if l = 600 nm?
x = 2 m; d = 0.08 mm
l = 600 nm; y = ? x y
d sin q s1 s2 q
n = 1, 3, 5
y = 3.75 cm

45. The Diffraction Grating
A diffraction grating consists of thousands of parallel slits etched on glass so that brighter and sharper patterns can be observed than with Young’s experiment. Equation is similar.
d sin q q d
d sin q = nl
n = 1, 2, 3, …

46. The Grating Equation 6l 4l 2l 3l The grating equation: 2l l 1st order
d = slit width (spacing)
l = wavelength of light
q = angular deviation
n = order of fringe
2nd order 2l 4l 6l

47. Example 2: Light (600 nm) strikes a grating ruled with 300 lines/mm
Example 2: Light (600 nm) strikes a grating ruled with 300 lines/mm. What is the angular deviation of the 2nd order bright fringe?
To find slit separation, we take reciprocal of 300 lines/mm:
300 lines/mm
n = 2
Lines/mm  mm/line

48. Example (Cont. ) 2: A grating is ruled with 300 lines/mm
Example (Cont.) 2: A grating is ruled with 300 lines/mm. What is the angular deviation of the 2nd order bright fringe?
300 lines/mm
n = 2
l = 600 nm
Angular deviation of second order fringe is:
q2 = 21.10

49. A compact disk acts as a diffraction grating
A compact disk acts as a diffraction grating. The colors and intensity of the reflected light depend on the orientation of the disc relative to the eye.

50. Interference From Single Slit
When monochromatic light strikes a single slit, diffraction from the edges produces an interference pattern as illustrated.
Pattern Exaggerated
Relative intensity
The interference results from the fact that not all paths of light travel the same distance some arrive out of phase.

51. Single Slit Interference Pattern
Each point inside slit acts as a source.
a/2 a 1 2 4 3 5
For rays 1 and 3 and for 2 and 4:
First dark fringe:
For every ray there is another ray that differs by this path and therefore interferes destructively.

52. Single Slit Interference Pattern1 2 4 3 5
First dark fringe:
Other dark fringes occur for integral multiples of this fraction l/a.

53. Example 3: Monochromatic light shines on a single slit of width 0
Example 3: Monochromatic light shines on a single slit of width 0.45 mm. On a screen 1.5 m away, the first dark fringe is displaced 2 mm from the central maximum. What is the wavelength of the light? q
x = 1.5 m y
a = 0.35 mm
l = ?
l = 600 nm

54. Diffraction for a Circular Opening
Circular diffraction D
The diffraction of light passing through a circular opening produces circular interference fringes that often blur images. For optical instruments, the problem increases with larger diameters D.

55. Resolution of Images
Consider light through a pinhole. As two objects get closer the interference fringes overlap, making it difficult to distinguish separate images. d1
Clear image of each object d2
Separate images barely seen

56. Resolution Limit Separate images Resolution Limit
Images are just resolved when central maximum of one pattern coincides with first dark fringe of the other pattern. d2
Resolution limit
Separate images
Resolution Limit

57. Resolving Power of Instruments
The resolving power of an instrument is a measure of its ability to produce well-defined separate images.
Limiting angle D q
For small angles, sin q  q, and the limiting angle of resolution for a circular opening is:
Limiting angle of resolution:

58. Resolution and Distanceq so p D
Limiting angle qo
Limiting Angle of Resolution:

59. Example 4: The tail lights (l = 632 nm) of an auto are 1
Example 4: The tail lights (l = 632 nm) of an auto are 1.2 m apart and the pupil of the eye is around 2 mm in diameter. How far away can the tail lights be resolved as separate images? q so p
Eye D
Tail lights
p = km

60. Summary d sin q q Young’s Experiment:
Monochromatic light falls on two slits, producing interference fringes on a screen. x y
d sin q s1 s2 d q p1 p2
Bright fringes:
Dark fringes:

61. Summary (Cont.) The grating equation: d = slit width (spacing)
l = wavelength of light
q = angular deviation
n = order of fringe

62. Summary (Cont.) Interference from a single slit of width a:
Pattern Exaggerated
Relative Intensity

63. Summary (cont.) The resolving power of instruments. q p D so
Limiting angle qo
Limiting Angle of Resolution: