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Hydrogen Peroxide. Hydrogen peroxide 2. From Barium peroxide Barium sulphate is filtered off leaving behind H 2 O 2. Methods of preparation.

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Presentation on theme: "Hydrogen Peroxide. Hydrogen peroxide 2. From Barium peroxide Barium sulphate is filtered off leaving behind H 2 O 2. Methods of preparation."— Presentation transcript:

1 Hydrogen Peroxide

2 Hydrogen peroxide 2. From Barium peroxide Barium sulphate is filtered off leaving behind H 2 O 2. Methods of preparation

3 3. By electrolysis of 50% H 2 SO 4 H 2 SO 4 At cathode At Anode H 2 O 2 distills first leaving behind the H 2 SO 4 which is recycled.

4 4. By auto oxidation of 2- ethylanthraquinol The H 2 O 2 obtained by this method is further concentrated by distillation under reduced pressure.

5 Physical Properties  In the pure state H 2 O 2 is an almost colourless (very pale blue) liquid.  H 2 O 2 is miscible with water in all proportions and forms a hydrate H 2 O 2.H 2 O  A 30% solution of H 2 O 2 is marketed as ‘100 volume’ hydrogen peroxide.

6 Structure of hydrogen peroxide

7 Oxidising properties Chemical Properties

8 Oxidising properties

9 Reducing properties

10

11 Acidic properties It reacts with alkalies and decomposes carbonates.

12  For bleaching silk, wool, hair and leather  As rocket fuel  Dilute solution is sold in name ‘perhydrol’  It is used in the synthesis of hydroquinone, tartaric acid and certain food products and pharmaceuticals (cephalosporin) etc. Uses of hydrogen peroxide

13 H 2 O 2 is stored in the bottles lined with wax because the rough glass surface causes the decomposition of hydrogen peroxide. Storage H 2 O 2 decomposes slowly on exposure to light.

14 Volume strength of hydrogen peroxide Calculate the percentage strength of a 10 volume H 2 O 2 solution. 10 volume hydrogen peroxide means that 1 ml of such a solution of hydrogen peroxide on heating will produce 10 ml of oxygen at N.T.P. 2(2 + 32) gm 22.4L at N.T.P. = 68 gm or 22400 cm 3 at N.T.P.

15 Solution But 10 ml of O 2 at N.T.P. are produced from 1 ml of 10 volume H 2 O 2 solution. = 0.03035 gm

16 Illustrative example Calculate the normality of 30 volume of H 2 O solution: Solution: 2(2 + 32) gm 22.4 L = 68 gm 22.4 L of O 2 is produced from = 68 gm of H 2 O 2 = 91.07 gm/mL

17 Solution 68 parts by weight32 parts by weight 32 parts by weight of oxygen is obtained from = 68 parts by weight of H 2 O 2 parts by weight of oxygen is obtained from =


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