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Enthalpy
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Thermodynamics 101 First Law of Thermodynamics o Energy is conserved in a reaction (it cannot be created or destroyed)--- sound familiar??? o Math representation: ΔE total = ΔE sys + ΔE surr = 0 Δ= “change in” ΔΕ= positive (+), energy gained by system ΔΕ= negative (-), energy lost by system Total energy = sum of the energy of each part in a chemical reaction
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Mg+ 2HCl MgCl 2 + H 2
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Exothermic Temperature increase (--isolated system) Heat is released to surroundings (--open/closed system) q = - value Chemical Thermal Energy
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Endothermic Temperature decrease (--isolated system) o All energy going into reaction, not into surroundings Heat absorbed by system, surroundings have to put energy into reaction q = + value Thermal Chemical Energy
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Heat of Reaction Amount of heat exchange happening between the system and its surroundings for a chemical reaction. Temperature remains constant Usually reactions happen at constant volume or constant pressure
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How does work factor into heat of reaction? W = -PΔV If volume is constant (ΔV), PΔV = 0 and no other work sooooo If pressure (P) is constant so volume can change, work is being done soooo
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Enthalpy (H) Measures 2 things in a chemical reaction: 1)Energy change 2)Amount of work done to or by chemical reaction 2 types of chemical reactions: 1) Exothermic —heat released to the surroundings, getting rid of heat, -ΔΗ 2) Endothermic —heat absorbed from surroundings, bringing heat in, +ΔΗ ** Enthalpy of reaction —heat from a chemical reaction which is given off or absorbed, units = kJ/mol Enthalpy of reaction o Heat from a chemical reaction which is given off or absorbed o At constant pressure o Units = kJ/mol
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Enthalpy (H) cont. Most chemical reactions happen at constant pressure (atmospheric pressure)—open container Temperature and pressure are constant o Only work is through pressure/volume Sum of reaction’s internal energy + pressure/volume of system o H = U + PV o ΔH = ΔU + PΔV
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Properties of Enthalpy Extensive Property o Dependent on amount of substance used State Function o Only deals with current condition o Focus on initial and final states Enthalpy changes are unique o Each condition has specific enthalpy value SO enthalpy change (ΔH) also has specific value
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Example 1 CH 4 + 2O 2 CO 2 + 2H 2 O ΔH = -890.3 kJ
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Example 2 2HgO 2Hg + O 2 ΔH = + 181.66 kJ HgO Hg + ½ O 2 ΔH = + 90.83 kJ
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More Enthalpy The reverse of a chemical reaction will have an EQUAL but OPPOSITE enthalpy change HgO Hg + ½ O 2 ΔH = + 90.83 kJ Hg + ½ O 2 HgO ΔH = - 90.83 kJ SOOO-----total ΔH = 0
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Example 1: Based on the following: 2Ag 2 S + 2H 2 O 4Ag + 2H 2 S + O 2 ΔH = +595.5 kJ Find the ΔH for the reaction below: Ag + ½ H 2 S + ¼ O 2 ½ Ag 2 S + ½ H 2 O ΔH = ?
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Example 2: Write a chemical equation for ice melting at 0°C through heat absorption of 334 kJ per gram.
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Stoichiometry Returns
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Example 1: H 2 + Cl 2 2HCl ΔH = -184.6 kJ
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Example 2: Calculate the ΔH for the following reaction when 12.8 grams of hydrogen gas combine with excess chlorine gas to produce hydrochloric acid. H 2 + Cl 2 2HCl ΔH = -184.6 kJ
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Example 3: Pentaborane (B 5 H 9 ) burns to produce B 2 O 3 and water vapor. The ΔH for this reaction is -8686.6 kJ/mol at 298°K. What is the ΔH with the consumption of 0.600 mol B 5 H 9 ? 2B 5 H 9 + 12O 2 5B 2 O 3 + 9H 2 O
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Homework Study for intermolecular quiz-----Tuesday Problems p. 251 #27, 29-31, 33-35 due Wednesday
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