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Pascal’s Triangle and the Binomial Theorem, then Exam!
20.0 Students know the binomial theorem and use it to expand binomial expressions that are raised to positive integer powers.
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Pascal’s Triangle and the Binomial Theorem
Objectives Key Words Relate Pascal’s Triangle to the terms of a Binomial Expansion The Binomial Theorem Pascal’s triangle The arrangement of 𝑛 𝐶 𝑟 in a triangular pattern in which each row corresponds to a value of n. (pg 553, you have to see it to believe it!)
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Pascal’s Triangle If you arrange the values of 𝑛 𝐶 𝑟 in a triangular pattern in which each row corresponds to a value of n, you get a pattern called Pascal’s triangle. Turn to page 553.
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For any positive integer n, the expansion of 𝑎+𝑏 𝑛 is:
The Binomial Theorem For any positive integer n, the expansion of 𝑎+𝑏 𝑛 is: 𝑎+𝑏 𝑛 = 𝑛 𝐶 0 𝑎 𝑛 𝑏 𝑛 𝐶 1 𝑎 𝑛−1 𝑏 1 + 𝑛 𝐶 2 𝑎 𝑛−2 𝑏 2 +⋯+ 𝑛 𝐶 𝑛 𝑎 0 𝑏 𝑛 Note that each term has the form 𝑛 𝐶 𝑟 𝑎 𝑛−𝑟 𝑏 𝑟 where r is an integer from 0 to n. Examples: 𝑎+𝑏 1 𝑎+𝑏 2 𝑎+𝑏 3
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Example 1 Expand ( )4. b a + SOLUTION
Expand a Power of a Simple Binomial Sum Expand ( )4. b a + SOLUTION In , the power is n So, the coefficients of the terms are the numbers in the 4th row of Pascal’s Triangle. = ( )4 b a + Coefficients: 1, 4, 6, 4, 1 Powers of a: a 4, a 3, a 2, a 1, a 0 Powers of b: b0, b1, b2, b3, b4 = 1a 4b 0 + ( )4 b a 4a 3b 1 6a 2b 2 1a 0b 4 4a 1b 3 = a 4 + 4a 3b 6a 2b 2 4ab 3 b 4 5
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Use the binomial theorem with a x and b 5. =
Example 2 Expand a Power of a Binomial Sum Expand ( )3. 5 x + SOLUTION Use the binomial theorem with a x and b = 5 x ( + 3 = 3C0x 350 3C1x 251 3C2x 152 3C3x 053 = + ( ) x 3 1 x 2 3 5 x 1 25 x 0 125 = + x 3 15x 2 75x 125 6
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First rewrite the difference as a sum: SOLUTION
Example 3 Expand a Power of a Binomial Difference Expand y 2x ( – )4 . First rewrite the difference as a sum: SOLUTION = 2x [ + 4 ( – y ] y – ) 4 = Then use the binomial theorem with a 2x and b –y. 4C3 4C2 4C4 = + 2x [ 4 ( – y ] 4C0 4C1 3 1 2 7
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Example 3 = + ( ) 16x 4 1 8x 3 4 y – 4x 2 6 y 2 2x – y 3 y 4 = 16x 4 +
Expand a Power of a Binomial Difference = + ( ) 16x 4 1 8x 3 4 y – 4x 2 6 y 2 2x – y 3 y 4 = 16x 4 + – 32x 3y 24x 2y 2 8xy 3 y 4 8
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Expand the power of the binomial sum or difference.
Checkpoint Expand a Power of a Binomial Sum or Difference Expand the power of the binomial sum or difference. 1. b a ( + )5 ANSWER a 5 + 5a 4b 10a 3b 2 10a 2b 3 5ab 4 b 5 2. 2 x ( + )4 ANSWER x 4 + 8x 3 24x 2 32x 16 3. 5 3x ( + )3 ANSWER 27x 3 + 135x 2 225x 125
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Expand the power of the binomial sum or difference.
Checkpoint Expand a Power of a Binomial Sum or Difference Expand the power of the binomial sum or difference. 4. 4 p ( )3 – p 3 ANSWER + – 12p 2 48p 64 5. – n m ( )4 m 4 ANSWER + – 4m 3n 6m 2n 2 4mn 3 n 4 6. t 3s ( – )3 27s 3 + – 27s 2t 9st 2 t 3 ANSWER
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Conclusions Summary Assignment Exit Slip:
How can you calculate the coefficients of the terms of 𝑎+𝑏 𝑛 ? Each term in the expansion of 𝑎+𝑏 𝑛 has the form 𝑛 𝐶 𝑟 𝑎 𝑛−𝑟 𝑏 𝑟 , where r is an integer from 0 to n. Pg 555 #(2,6-13) Write the assignment down, you will work on it after the you finish the exam, early. Get ready for the exam.
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45 Minutes No talking – Read Rubric – Read Directions – Good Luck!
Exam on the Fundamental Counting Principle 45 Minutes No talking – Read Rubric – Read Directions – Good Luck!
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