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Pg. 606 Homework Pg. 631#1 – 3, 5 – 10, 13 – 19 odd #1135#12126 #1370#14220 #151365#161716 #1756x 5 y 3 #1856x 3 y 5 #19240x 4 #20-2268x 6 #34expand to.

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Presentation on theme: "Pg. 606 Homework Pg. 631#1 – 3, 5 – 10, 13 – 19 odd #1135#12126 #1370#14220 #151365#161716 #1756x 5 y 3 #1856x 3 y 5 #19240x 4 #20-2268x 6 #34expand to."— Presentation transcript:

1 Pg. 606 Homework Pg. 631#1 – 3, 5 – 10, 13 – 19 odd #1135#12126 #1370#14220 #151365#161716 #1756x 5 y 3 #1856x 3 y 5 #19240x 4 #20-2268x 6 #34expand to prove

2 11.3 Counting, Permutations, and Combinations Problem A: How many two letter “words” can be formed from the letters {a, b, c}? Problem B: A construction crew has three members. A team of two must be chosen. In how many ways can the team be chosen from {a, b, c}? How are these two examples the same? How are these two examples different? Problem A is a _____________ Problem B is a _____________

3 11.3 Counting, Permutations, and Combinations A permutation of n objects taken r at a time, denoted P(n, r) is an arrangement of r of the n objects in a specific order. P(n, r) = n∙(n – 1)∙(n – 2)∙ … ∙ (n – (r – 1)) P(5, 2) P(4, 2) P(3, 2) P(6, 4) P(100, 2)

4 11.3 Counting, Permutations, and Combinations A combination of n objects taken r at a time, denoted C(n, r) is a selection of r objects from among the n, with order disregarded. C(n, r) = P(n, r) r! C(5, 2) C(4, 2) C(3, 2) C(6, 4) C(100, 2)

5 11.3 Counting, Permutations, and Combinations When dealing with word problems, you must think: “Is there a specific order or is order disregarded?” This will tell you whether or not it is a permutation or combination. The Board of Directors of a company has 10 members. In how many ways can they choose a committee of three?

6 11.3 Counting, Permutations, and Combinations Nine horses are entered into the Kentucky Derby. Assuming no ties, how many different outcomes of 1 st, 2 nd, and 3 rd are there? A student is require to work exactly five of the eight problems on an exam. In how many different ways can the problems be chosen?

7 11.3 Counting, Permutations, and Combinations How many different outcomes of “winner” and “runner-up” are possible if there are six contestants in a pie-eating contest?


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