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Published byNathan Cobb Modified over 9 years ago
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Announcements No class next Monday (MLK day)
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Equations of Motion Tractable cases §2.5–2.6
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Find Position from Velocity Generally: velocity is slope of a position- time graph. Conversely, position is the area under a velocity-time graph. What is this when v is constant?
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Area under a v-t graph speed (m/s) time (s) area = (a m/s) (b s) = ab m a b distance units
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Constant-Velocity Motion v = x/ t = constant throughout process x = v t x f = x i + x = x i + v t Can also use this with average v
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Find Velocity from Acceleration General case: acceleration is slope of a velocity-time graph. Conversely, velocity is the area under an acceleration-time graph. What is this when a is constant?
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Constant-Acceleration Motion Instantaneous accel = average accel a = v/ t v = velocity change over time t v = a t v = v 0 + v = v 0 + a t
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Acceleration on an x-t Graph Velocity is the slope of a position-time graph Acceleration means a changing slope –A constant slope means a straight x-t line –A varying slope means a curved x-t line Positive acceleration = concave up Negative acceleration = concave down
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Visualize Acceleration Young and Freedman, Fig. 2.8 Board Work: 2.Signs of v 3.Signs of a
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Acceleration Starting from a traffic light that turns green d t v t a t area = velocity area = distance slope = velocity slope = acceleration
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Equations of Motion What are velocity and position under conditions of constant acceleration?
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Formulas from Constant x-Acceleration Velocity change v = a t Velocity v t = v 0 + v = v 0 + a t Position change x = v 0 t + 1/2 a ( t) 2 Position x t = x 0 + v 0 t + 1/2 a ( t) 2
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Another Form (constant a) If you don’t know t and want v: x = x 0 + v 0 t + 1/2 a ( t) 2 t = v/a x – x 0 = v 0 v/a + 1/2 a ( v/a) 2 2a (x–x 0 ) = 2v 0 (v–v 0 ) + (v–v 0 ) 2 2a (x–x 0 ) = 2vv 0 – 2v 0 2 + v 2 – 2vv 0 + v 0 2 2a (x–x 0 ) = 2vv 0 – 2vv 0 + v 2 + v 0 2 – 2v 0 2 2a (x–x 0 ) = v 2 – v 0 2 v 2 = v 0 2 + 2a (x–x 0 ) Do units work?
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Another Form (constant a) If you don’t know a but know v, v 0, and t: x = x 0 + v 0 t + 1/2 a ( t) 2 a = v/ t = (v–v 0 )/ t x = x 0 + v 0 t + 1/2 ( (v–v 0 )/ t ) ( t) 2 x – x 0 = v 0 t + 1/2 v t – 1/2 v 0 t x – x 0 = v 0 t – 1/2 v 0 t + 1/2 v t x – x 0 = 1/2 (v 0 + v) t Do units work?
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Example Problem A car 3.5 m in length traveling at 20 m/s approaches an intersection. The width of the intersection is 20 m. The light turns yellow when the front of the car is 50 m from the beginning of the intersection. If the driver steps on the brake, the car will slow at –3.8 m/s 2 and if the car steps on the gas the car will accelerate at 2.3 m/s 2. The light will be yellow for 3 s. To avoid being in the intersection when the light turns red, should the driver use the brake or the gas?
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