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Warm-up over Lesson 5-1.

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Presentation on theme: "Warm-up over Lesson 5-1."— Presentation transcript:

1 Warm-up over Lesson 5-1

2 Simplify b2 ● b5 ● b3. A. b5 B. b8 C. b10 D. b30 5-Minute Check 1

3 A. B. C. D. 5-Minute Check 2

4 Simplify (10a2 – 6ab + b2) – (5a2 – 2b2).
A. 15a2 + 8ab + 3b2 B. 10a2 – 6ab – b2 C. 5a2 + 6ab – 3b2 D. 5a2 – 6ab + 3b2 5-Minute Check 3

5 Simplify 7w(2w2 + 8w – 5). A. 14w3 + 56w2 – 35w B. 14w2 + 15w – 35
C. 9w2 + 15w – 12 D. 2w2 + 15w – 5 5-Minute Check 4

6 Find the product of 3y(2y2 – 1)(y + 4).
A. 18y5 + 72y4 – 9y3 – 36y2 B. 6y4 + 24y3 – 3y2 – 12y C. –18y3 – 3y2 + 12y D. 6y3 – 2y + 4 5-Minute Check 6

7 Chapter 5 Lesson 2 (Part A)
Dividing Polynomials Long Division

8 Mathematical Practices 6 Attend to precision.
Content Standards A.APR.6 Rewrite simple rational expressions in different forms; write a(x)/b(x) in the form q(x) + r(x)/b(x), where a(x), b(x), q(x), and r(x) are polynomials with the degree of r(x) less than the degree of b(x), using inspection, long division, or, for the more complicated examples, a computer algebra system. Mathematical Practices 6 Attend to precision. CCSS

9 Divide polynomials using long division.
You divided monomials. Divide polynomials using long division. Then/Now

10 Example # 1 = a – 3b2 + 2a2b3 a1 – 1 = a0 or 1 and b1 – 1 = b0 or 1
Divide a Polynomial by a Monomial Sum of quotients Divide. = a – 3b2 + 2a2b3 a1 – 1 = a0 or 1 and b1 – 1 = b0 or 1 Answer: a – 3b2 + 2a2b3 Example 1

11 Example #2 Simplify

12 Example #3 Simplify

13 A. 2x3y – 3x5y2 B. 1 + 2x3y – 3x5y2 C. 6x4y2 + 9x7y3 – 6x9y4
D x7y3 – 3x9y4 Example 1

14 Remembering Long Division……

15 Example # 4 Use long division to find (x2 – 2x – 15) ÷ (x – 5).
Division Algorithm Use long division to find (x2 – 2x – 15) ÷ (x – 5). x(x – 5) = x2 – 5x 3(x – 5) = 3x – 15 –2x – (–5x) = 3x Answer: The quotient is x + 3. The remainder is 0. Example 2

16 Example # 5 Use long division to find the quotient.

17 Example # 6 Use long division to find the quotient.

18 Example # 7 Use long division to find the quotient.

19 Use long division to find (x2 + 5x + 6) ÷ (x + 3).
A. x + 2 B. x + 3 C. x + 2x D. x + 8 Example 2

20 Example # 8 Which expression is equal to (a2 – 5a + 3)(2 – a)–1?
Divide Polynomials Which expression is equal to (a2 – 5a + 3)(2 – a)–1? A a + 3 B C D Example 3

21 Divide Polynomials Read the Test Item Since the second factor has an exponent of –1, this is a division problem. Solve the Test Item 3(–a + 2) = –3a + 6 –a(–a + 2) = a2 – 2a Rewrite 2 – a as –a + 2. –5a – (–2a) = –3a Subtract. 3 – 6 = –3 Example 3

22 The quotient is –a + 3 and the remainder is –3.
Divide Polynomials The quotient is –a + 3 and the remainder is –3. Therefore, . Answer: The answer is D. Example 3

23 Which expression is equal to (x2 – x – 7)(x – 3)–1?
B. C. D. Example 3

24 Pg . 315: 1-7 and all

25 Reflection…… If a polynomial is divided by a binomial and the remainder is 0, what does this tell you about the relationship between the binomial and the polynomial? End of the Lesson


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