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Published byRodger Watkins Modified over 9 years ago
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Pre-Algebra Unit 1 Review
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Unit 1 Review 1)Name the property demonstrated. a) a + b = b + a b) a(b + c) = ab + ac
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Unit 1 Review 1)Name the property demonstrated. a) a + b = b + a Commutative property of addition b) a(b + c) = ab + ac distributive property Answer
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Unit 1 Review 2)Name the property demonstrated. a) ab = ba b) a + (b + c) = (a + b) + c
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Unit 1 Review 2)Name the property demonstrated. a) ab = ba commutative property of multiplication b) a + (b + c) = (a + b) + c associative property of addition Answer
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Unit 1 Review 3)Simplify. a) 5x + 3y + 3x + 2y
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Unit 1 Review 3)Simplify. a) 5x + 3y + 3x + 2y = 8x + 5y Answer
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Unit 1 Review 4)Simplify. a) 4 + 6(a + 2) + 3a
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Unit 1 Review 4)Simplify. a) 4 + 6(a + 2) + 3a = 9a + 16 Answer
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Unit 1 Review 5)Solve for x. a) x + 19 = 30 b) 38 + x -18 = 500
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Unit 1 Review 5)Solve for x. a) x + 19 = 30 x = 11 b) 38 + x -18 = 500 x = 480 Answer
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Unit 1 Review 6)Solve for y. a) 8y = 96 b) y / 12 = -24
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Unit 1 Review 6)Solve for y. a) 8y = 96 y = 12 b) y / 12 = -24 y = -288 Answer
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Unit 1 Review 7)Write an equation for the problem and solve. a) Twice a number increased by 28 is 54.
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Unit 1 Review 7)Write an equation for the problem and solve. a) Twice a number increased by 28 is 54. 2n + 28 = 54 n = 13 Answer
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Unit 1 Review 8)Write an equation for the problem and solve. a) Terry’s age is half Bobby’s age. The sum of their ages is 36. How old are they?
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Unit 1 Review 8)Write an equation for the problem and solve. a) Terry’s age is half Bobby’s age. The sum of their ages is 36. How old are they? Terry’s age is a. Bobby’s age is 2a a + 2a = 36 a = 12 So, Terry is 12 and Bobby is 24. Answer
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Unit 1 Review 9)Solve for n. 2│n│ = 10
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Unit 1 Review 9)Solve for n. 2│n│ = 10 n = ±5 Answer
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