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Inflation / Deflation Inflation is an increase over time in the price of a good or service with a constant value A gallon of 87 octane gasoline increases in price (but still only gets Dr. J. 32 miles down the road) Deflation is a decrease over time in the price of a good or service of constant value. A 2 GHz computer has decreased in price (but still does the same number of computations/min.)
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Other Examples: Inflationary Tuition Fees Books Industry Salaries Cars Gas Deflationary CPU Memory Computers Constant Bread Milk
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Average Inflation Rate (f) In most engineering econ problems, different items will have different inflation rates Average Inflation Rate is based on a market basket of goods – CPI or Consumer Price Index Simplifies cash flow in an analysis! 1.Food & Drink 2.Housing 3.Clothing 4.Transportation 5.Medical Care 6.Entertainment 7.Personal Care 8.Other Goods / Services
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Deriving Equation for Inflation P = 50,000 f = 10% increase annually F 1 = 50,000 + 50,000 (.10) = 50,000 (1 +.10) = 55,000 F 2 = 55,000 + 55,000 (.10) = 55,000 (1 +.10) = 50,000 (1 +.10)(1 +.10) = 50,000 (1 +.10) 2 = 60,500 F 3 = 60,500 + 60,500 (.10) = 50,000 (1 +.10) 2 (1 +.10) = 50,000 (1 +.10) 3 = 66,550 Generally:F n = P (1 + f ) n
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Constant Dollars vs. Actual Dollars Constant Dollars – represent constant purchasing power independent of the passage of time. Actual Dollars – an estimate of a future cash flow for Year n that take into account any anticipated changes in amount caused by inflationary or deflationary effects.
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Constant Dollars vs. Actual Dollars f = Average Inflation Rate $785 / QTR Tuition & Fees 19802012 ACTUAL $ $785 / QTR Tuition & Fees $785 (1+ f ) 32 / QTR Tuition & Fees 19802012 CONSTANT $ $A = $C (1+ f ) n $C = $A (1+ f ) – n
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Incorporating Inflation Inflation can be accounted for as an additional component on top of the interest rate: d = i + f + if (d replaces i in tables/equations) where: i is the effective interest rate f is the constant inflation rate
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Incorporating Inflation Example If you desire a real return of 10% on your money, excluding inflation, and inflation is running 3%, what is combined discount rate you should be seeking?
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Ch 15 Inflation 10 Measuring Inflation with CPI Consumer Price Index
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Example using CPI Carol and George are both engineers. In 2001, their combined income was $105,000. How much did their income need to be in 2008 to have the same purchasing power? 2001 CPI = 176.7 2008 CPI = 210
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Ch 15 Inflation 12 Are the Lowest Paid Keeping up with Inflation? Federal minimum wage $1 in 1960 $7.25 in 2009 CPI 29.8 in 1960 215.9 in 2009 Did pay increase in real terms?
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Ch 15 Inflation 13 Average CPI & Minimum Wage Inflation Rates F T + t = F T (1 + f ) t 1960 to 2009 is 49 years CPI 215.9 = 29.8 (1 + f ) 49 f = (215.9/29.8) 1/49 – 1 = 4.124% Federal minimum wage 7.25 = 1 (1 + f MW ) 49 f MW = (7.25/1) 1/49 – 1 = 4.126%
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Class Example A $50,000 Bond which has a bond interest rate of 10% per year payable semiannually is currently for sale. The bond is due in 15 years. If the rate of return required by investors is a nominal 16% per year compounded semiannually and if the inflation rate is 4.5% per semi annual period, how much should be paid for the bond (a) when inflation is not taken into account and (b) when inflation is considered.
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Additional References Eschenbach, Ted G. (2011). Engineering Economy - Applying Theory to Practice (3rd Edition).. Oxford University Press.Online version available at:http://www.knovel.com/web/portal/bro wse/display?_EXT_KNOVEL_DISPLAY_ bookid=4020&VerticalID=0, Chapter 15 Blank and Tarquin. Engineering Economy (3 rd Edition) 1989. Pg 261.
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