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Physics Chp 2. Displacement – is the difference between the intitial position and the final position. It does not matter how far you really went. ex.

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Presentation on theme: "Physics Chp 2. Displacement – is the difference between the intitial position and the final position. It does not matter how far you really went. ex."— Presentation transcript:

1 Physics Chp 2

2 Displacement – is the difference between the intitial position and the final position. It does not matter how far you really went. ex. Flying to Boston via Sea or Salt Lake or Houston. All 3 you have the same displacement and it is symbolized as Δx. Needs a value and direction with units

3 Velocity is the change in x divided by time v = Δx/ Δt Avg. velocity is just comparing any two points of data. Instantaneous velocity is at one instant in time and is the tangent to the graph of Δx vs Δt

4

5 Slope of tangent to the graph gives the velocity at that instant in time.

6 Acceleration a = Δv/ Δt graphical const vs variable

7 Equations when a = constant v f = v o +aΔt Δx = 1/2(v o + v f )Δt Δx = v o Δt + 1/2a(Δt) 2 v f 2 = v o 2 + 2aΔx

8 Ex Find the final velocity if you toss a ball from your car traveling North at 200 m/s and your arm accelerates it 50 m/s 2 N for 0.3 s.

9 V o = 200 m/s N a = 50 m/s 2 N t = 0.3 s v f = v o +aΔt v f = 200 m/s + 50 m/s 2 (0.3s) V f =

10 Free Fall is just when a = -9.81 m/s2 Ex If it takes 13 s for a rock dropped off a cliff to hit the bottom, how high is the cliff? Ignore the echo issue.

11 v o = 0 m/s a = -9.81 m/s 2 t = 13s Δx = v o Δt + 1/2a(Δt) 2 Δx = 0m/s(13s) + ½(-9.81m/s 2 )(13s) 2 Δx = -830m cliff is really 830m Why

12 Ex How fast did the rock hit the bottom of the cliff?

13 v o = 0 a = -9.81 m/s 2 t = 13s ∆x = -830m v f 2 = v o 2 + 2aΔx v f 2 = 0 2 + 2(-9.81 m/s 2 )(-830m) v f 2 = v f = ?????


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