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Geometry Honors C ONCURRENT L INES, M EDIANS & A LTITUDES.

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Presentation on theme: "Geometry Honors C ONCURRENT L INES, M EDIANS & A LTITUDES."— Presentation transcript:

1 Geometry Honors C ONCURRENT L INES, M EDIANS & A LTITUDES

2 Vocabulary Concurrent Lines – when three or more lines intersect in one point. Point of concurrency– the point at which 3 or more lines intersect.

3 Geogebra Demonstration of Perpendicular Bisectors

4 Vocabulary Circumcenter of the triangle– the point of concurrency of the perpendicular bisectors. Circumcenter

5 The perpendicular bisectors of the sides of a triangle are concurrent at a point equidistant from the vertices. Theorem

6 Since the vertices of the triangle are equidistant from the circumcenter, we can draw a circle around the triangle or circumscribe the triangle. The center of the circle is the circumcenter of the triangle.

7 Geogebra Demonstration of Angle Bisectors

8 Vocabulary Incenter of the triangle– the point of concurrency of the angle bisectors. Incenter

9 Theorem The bisectors of the angles of a triangle are concurrent at a point equidistant from the sides.

10 We can now inscribe a circle in the triangle since the incenter is equidistant from the sides. The center of the circle is the incenter of the triangle.

11 Geogebra Demonstration of Altitudes of Triangles

12 Vocabulary Altitude of a Triangle– a perpendicular segment from a vertex to the line containing the side opposite to the vertex. Orthocenter

13 FYI An altitude can be the side of the triangle.

14 Theorem The lines that contain the altitudes of a triangle are concurrent.

15 Geogebra Demonstration of Medians of Triangles

16 Vocabulary Median of a Triangle– a segment whose endpoints are a vertex and the midpoint of the opposite side. Centroid

17 FYI The centroid is the center of gravity of the triangle. If you cut out the triangle and paper- fold to determine the centroid, you can balance the triangle on the tip of your pencil point.

18 Theorem The medians of a triangle are concurrent at a point that is two thirds the distance from each vertex to the midpoint of the opposite side.

19 A B C D E F G

20 Cut out your triangles. Yellow Paper - Median Draw an acute triangle. Cut it out. Determine the midpoint of each side by folding corner to corner. Then fold the triangle from the midpoint of each side to the vertex opposite it. Ask Mrs. Slifko to see the model in my notebook if you need to. Label the point of concurrency the centroid. Try to balance your triangle on the tip of your pencil. Put any other theorems on the triangle.

21 Cut out your triangles. Green Paper- Altitude Draw an acute triangle. Cut it out. Fold the triangle so that you create an altitude extending from all three vertices. Ask Mrs. Slifko to see the model in my notebook if you need to. Label the point of concurrency the orthocenter. Write any necessary information on the triangle.

22 We can use coordinate geometry to write equations of the various special segments of the triangles.

23 Example: A(2,9) B(-2,3)C(6,-1) How can we find the slope of altitude AD? D We know that altitudes are at right angles to the opposite sides…therefore, if we can find the slope of BC, we can use opposite reciprocals to find the slope of AD.

24 Example: A(2,9) B(-2,3)C(6,-1) How can we find the equation of altitude AD? D If you know a point on the altitude, namely A(2,9),and the slope of AD, then you can use the point –slope formula to find the equation of altitude AD.

25 Example: A(3,9) B(-2,3)C(6,-1) How can we find the slope of median AD? D Since we know that a median hits the midpoint, we know that D is the midpoint of BC. Once you find the midpoint, you can use the slope formula to calculate the slope of AD.

26 Example: A(3,9) B(-2,3)C(6,-1) How can we find the equation of median AD? D Since you know a point on the median line and a slope, you can use point-slope formula to determine the equation of median AD.

27 Example: A(6,9) B(-2,3) C(12,-1) How can we find the slope of the perpendicular bisector of BC? D Since we know that perpendicular bisectors form right angles, we can determine the slope of BC and then use opposite reciprocals to determine the slope of the perpendicular bisector of BC.


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