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Summer Assignment Review
Graphing Compound Inequalities And Absolute Value Inequalities
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Compound Inequalities
AND compound inequalities should create a range of values. β2β€π₯β€3 π₯β₯β2 π΄ππ· π₯β€3 Donβt assume that the given inequality creates this range. β2β₯π₯β₯3 π₯β€β2 π΄ππ· π₯β₯3 π₯ falls between -2 and 3 on the number line. π₯ can not be both to the left of -2 and to the right of 3 on the number line . There is no solution.
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Compound Inequalities
OR compound inequalities should create two ranges of values. π₯β€β2 ππ
π₯β₯3 AND compound inequalities should create a range of values. π₯β₯β2 ππ
π₯β€3 π₯ is either to the left of -2 or to the right of 3 on the number line. π₯ can be anywhere on the number line. The solution is All Real Numbers.
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Practice Graph each compound inequality. 1) β3<π₯<4 2) 3)
4) 5) β3<π₯<4 All Real Numbers π₯ β₯β3 ππ π₯<3 π₯<β4 ππ π₯ β₯2 π₯β€0 πππ π₯β₯3 No Solutions π₯>β1 πππ π₯ β€5
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Absolute Value Inequalities
When we say that π₯ =3, we are saying that the distance between x and 0 is 3. When we say that π₯ <3, we are saying that the distance between x and 0 is less than 3. When we say that π₯ >3, we are saying that the distance between x and 0 is greater than 3. The inequalities < and β€ lead to βandβ relationships β3<π₯<3 The inequalities > and β₯ lead to βorβ relationships π₯<β3 ππ
π₯>3
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Solving Absolute Value Inequalities
Case 2 - modified method: Drop the absolute value bars, flip the inequality symbol and change the sign of the term on the right. 2π₯β1<β7 2π₯<β6 π₯<β3
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Solve and Graph an Abs. Val. Ineq.
Example : Solve π₯β5 β₯7 . Graph your solution. Step 1: Is it and or or? For the second, flip the inequality and change the sign of the 7 Step 2: Solve both Step 3: Graph This is β₯ so it is βorβ. Set up two inequalities. π₯β5 β₯7 π₯β5β₯7 π₯β5β€β7 π₯β₯12 π₯β€β2 π₯β₯ or π₯β€β2 Β· Β· Β·
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Solve and Graph an Abs. Val. Ineq.
Example : Solve Graph your solution. Step 1: Is it and or or? Step 2: Solve Step 3: Graph β4π₯β5 +3<9 We donβt know yet, get the abs. val. alone. Now : It is < , so it is an βandβ inequality. Drop the abs. val. Bars and put -6 < on the left. β4π₯β5 +3<9 β4π₯β5 <6 β6<β4π₯β5<6 β1<β4π₯<11 0.25>π₯>β2.75 β2.75<π₯<0.25
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Practice β5<π€<6 β0.2β€πβ€2.6 π₯>5 ππ π₯<β11
π₯>5 ππ π₯<β11 β5<π€<6 β0.2β€πβ€2.6 Β· Β· Β· Β· Β· Β·
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