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Conversion Factor Analysis practice Write down and answer these questions: 1)Molar Mass of C 6 H 12 O 6 = ____________ 2)How many C atoms in 1.74 mol of.

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Presentation on theme: "Conversion Factor Analysis practice Write down and answer these questions: 1)Molar Mass of C 6 H 12 O 6 = ____________ 2)How many C atoms in 1.74 mol of."— Presentation transcript:

1 Conversion Factor Analysis practice Write down and answer these questions: 1)Molar Mass of C 6 H 12 O 6 = ____________ 2)How many C atoms in 1.74 mol of C 6 H 12 O 6 ? 3)2.34 mol H 2 SO 4 are needed as a reactant. a) How many grams of H 2 SO 4 are needed? b) How many kilograms (kg) would that be?

2 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol

3 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom

4 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol

5 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol

6 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol M O = 16.00 g/mol

7 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol M O = 16.00 g/mol 6(12.01 g/mol)

8 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol M O = 16.00 g/mol 6(12.01 g/mol) + 12(1.008 g/mol)

9 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol M O = 16.00 g/mol 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00g/mol) =

10 Conversion Factor Analysis practice 1)Molar Mass of C 6 H 12 O 6 = ____________ M=g/mol see Periodic Table for molar mass of each atom M C = 12.01 g/mol M H = 1.008 g/mol M O = 16.00 g/mol 6(12.01 g/mol) + 12(1.008 g/mol) + 6(16.00g/mol) = 180.156 g/mol

11 Conversion Factor Analysis practice 2) How many C atoms in 1.74 mol of C 6 H 12 O 6 1.74 mol x 6.02x10 23 atoms x 6 C atoms = 2.625x10 23 1 mol 24 atoms

12 3) 2.34 mol H 2 SO 4 are needed as a reactant. a) How many grams of H 2 SO 4 are needed? b) How many kilograms (kg) would that be? First, setup the calculation to convert from what you have to what you need: 2.34 mol x ________g H 2 SO 4 = mol

13 3) 2.34 mol H 2 SO 4 are needed as a reactant. a) How many grams of H 2 SO 4 are needed? b) How many kilograms (kg) would that be? Second, find the quantities needed to plug into your calculation: Find molar mass of H 2 SO 4: 2(1.008g/mol) + 1(32.06g/mol) + 4(16.00g/mol) = 98.076g/mol

14 3) 2.34 mol H 2 SO 4 are needed as a reactant. a) How many grams of H 2 SO 4 are needed? b) How many kilograms (kg) would that be? Third, plug the quantities into the equation to convert to the needed units: 2.34 mol x 98.076g H 2 SO 4 = 229.50 g H 2 SO 4 mol

15 3) 2.34 mol H 2 SO 4 are needed as a reactant. a) How many grams of H 2 SO 4 are needed? b) How many kilograms (kg) would that be? Fourth, convert from grams to kilograms: 229.50g x 1 kg. = 0.2295 kg this is the answer to (b) 1,000g

16 4) Find the mass of 1 mole of MgCl 2. 5) What is the mass of 3.7 moles of MgCl 2 ? 6) How many Cl atoms in 3.7 mol MgCl 2 ?

17 4) Find the mass of 1 mole of MgCl 2. Look at periodic table. Mg 24.31g Cl 2

18 4) Find the mass of 1 mole of MgCl 2. Look at periodic table. Mg 24.31g Cl 2 70.90g

19 4) Find the mass of 1 mole of MgCl 2. Look at periodic table. Mg 24.31g Cl 2 70.90g 95.21g

20 5) What is the mass of 3.7 moles of MgCl 2 ? 95.21g x 3.7 mol = 352.3g 1 mol

21 6) How many Cl atoms in 3.7 mol MgCl 2 ? Step 1: Find total # of molecules 3.7mol x 6.02x10 23 MgCl 2 = 2.23x10 24 MgCl 2 1 mol

22 6) How many Cl atoms in 3.7 mol MgCl 2 ? Step 1: Find total # of molecules 3.7mol x 6.02x10 23 MgCl 2 = 2.23x10 24 MgCl 2 1 mol Step 2: since there are 2 Cl atoms in each MgCl 2 molecule, multiply by 2 2.23x10 24 MgCl 2 x 2 Cl = 4.46x10 24 Cl atoms 1 MgCl 2

23 Conversion Factor Analysis practice How many moles in your name? Chalk = Calcium Carbonate, CaCO 3 Initial mass:________g Final mass:_________g Mass of CaCO 3 in your name:__________g Molar mass of CaCO 3 :________g/mol How many moles CaCO 3 in your name? How many molecules of CaCO 3 in your name?

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