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Using the Mole. The Mole 1 mole = 6.02 X 10 23 Particles Particle = atoms, compounds, or molecules Molar ratio: Tells us the number of moles of each chemical.

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Presentation on theme: "Using the Mole. The Mole 1 mole = 6.02 X 10 23 Particles Particle = atoms, compounds, or molecules Molar ratio: Tells us the number of moles of each chemical."— Presentation transcript:

1 Using the Mole

2 The Mole 1 mole = 6.02 X 10 23 Particles Particle = atoms, compounds, or molecules Molar ratio: Tells us the number of moles of each chemical we need to use in order to have a complete reaction (where all the chemicals are used up.)

3 Atomic Molar Mass Atomic Molar Mass: The mass of 1 mole of an element (the mass of 6.02 X 10 23 atoms of that element) Units: Grams/Mole ( g/mol ) Eg.1) What is the molar mass of Ca? = Eg. 2) What is the molar mass of S? =

4 Atomic Molar Mass Atomic Molar Mass: The mass of 1 mole of an element (the mass of 6.02 X 10 23 atoms of that element) Units: Grams/Mole ( g/mol ) Eg.1) What is the molar mass of Ca?= 40.08g/mol Eg. 2) What is the molar mass of S? = 32.06g/mol

5 How do we find the molar mass of a compound Calculate the molar mass of 1)NaCl = Find out the number of each element is in the compound 2) NH 4 Cl =

6 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = Find out the mass of each element Remember: 2 oxygens weight twice as much as one = multiply each mass by the number of atoms in the compound 2) NH 4 Cl =

7 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = Add up the mass of all the atoms 2) NH 4 Cl

8 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = 58.44g/mol 2) NH 4 Cl =

9 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = 58.44g/mol 2) NH 4 Cl = 1N + 4H + 1Cl =

10 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = 58.44g/mol 2) NH 4 Cl = 1N + 4H + 1Cl =1x14.01g/mol + 4x1.01g/mol + 35.45g/mol =

11 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = 58.44g/mol 2) NH 4 Cl = 1N + 4H + 1Cl =1x14.01g/mol + 4x1.01g/mol + 35.45g/mol = 14.01g/mol + 4.04g/mol + 35.45g/mol

12 How do we find the molar mass of a compound Calculate the molar mass of 1) NaCl = 1Na + 1Cl = 1x 22.99g/mol + 1x 35.45g/mol = 58.44g/mol 2) NH 4 Cl = 1N + 4H + 1Cl =1x14.01g/mol + 4x1.01g/mol + 35.45g/mol = 14.01g/mol + 4.04g/mol + 35.45g/mol = 53.50g/mol

13 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 4) 2CH 3 COOH =

14 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 4) 2CH 3 COOH

15 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 1(24.31g/mol) + 2(14.01g/mol) + 6(16.00g/mol) = 4) 2CH 3 COOH

16 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 1(24.31g/mol) + 2(14.01g/mol) + 6(16.00g/mol) = 24.31g/mol + 28.02g/mol + 96.00g/mol 4) 2CH 3 COOH =

17 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 1(24.31g/mol) + 2(14.01g/mol) + 6(16.00g/mol) = 24.31g/mol + 28.02g/mol + 96.00g/mol = 148.33 4) 2CH 3 COOH = 2 (2C + 4H + 2O) =

18 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 1(24.31g/mol) + 2(14.01g/mol) + 6(16.00g/mol) = 24.31g/mol + 28.02g/mol + 96.00g/mol 4) 2CH 3 COOH = 2 (2C + 4H + 2O) = 2 (2(12.01g/mol) + 4(1.01g/mol) + 2(16.00g/mol)) =

19 How do we find the molar mass of a compound Calculate the molar mass of 3) Mg(NO 3 ) 2 = 1Mg + 2N + 6O = 1(24.31g/mol) + 2(14.01g/mol) + 6(16.00g/mol) = 24.31g/mol + 28.02g/mol + 96.00g/mol 4) 2CH 3 COOH = 2 (2C + 4H + 2O) =2 (2(12.01g/mol) + 4(1.01g/mol) + 2(16.00g/mol)) = 2 (24.02g/mol + 4.04g/mol + 32.00g/mol) = 2(60.06g/mol) = 120.12g/mol

20 Assignment Worksheet on conversions Next Class: Lab on Moles of Iron page 55 in Heath Chemistry Laboratory Experiments


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