1. Introduction to Mixture Applications Example 1: A jar contains 20 ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution? First, determine what 10% is as a fraction. Recall than percent means per hundred:

2. 20 ounces total water & acid

3. 10% acid

4. 10% The acid is 10% of the total: of the total 20

5. 2 oz. There are two ounces of acid in the solution.

6. 10% Review the expression that gave us the amount of acid: of the total 20 In decimal form … = (percent acid)× (total amount) 10% 20

7. Introduction to Mixture Applications Example 2: A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 10% of the total solution, how much acid is in the solution?

8. x ounces total water & acid

9. 10% acid

10. 10% The acid is 10% of the total: of the total x = (percent acid)× (total amount)

11. 0.10x oz. There are 0.10x ounces of acid in the solution. = (percent acid)× (total amount)

12. Introduction to Mixture Applications Example 3: A jar contains x ounces of a solution that is part water and part acid. If the amount of acid is 65% of the total solution, how much acid is in the solution? = (percent acid)× (total amount)Amount acid