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There are 3 red, 2 green, 5 yellow, and 1 blue marker pens in a box. Suppose you choose one at random. Find these probabilities. Probability COURSE 3 LESSON.

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Presentation on theme: "There are 3 red, 2 green, 5 yellow, and 1 blue marker pens in a box. Suppose you choose one at random. Find these probabilities. Probability COURSE 3 LESSON."— Presentation transcript:

1 There are 3 red, 2 green, 5 yellow, and 1 blue marker pens in a box. Suppose you choose one at random. Find these probabilities. Probability COURSE 3 LESSON 6-9 P (yellow) = 5 11 5 favorable outcomes 11 possible outcomes P (brown) = 0 11 0 favorable outcomes 11 possible outcomes The probability of choosing a yellow marker pen is. 5 11 = 0 Write the fraction in simplest form. The probability of choosing a brown marker pen is 0. b.P (brown) a.P (yellow) 6-9

2 The probability of a certain person making a basket from the center line of a basketball court is 1 out of 1,200. Express this probability as a percent. Round to the nearest thousandth of a percent. Probability COURSE 3 LESSON 6-9 The probability of the person making the basket is about 0.083%. 1 out of 1,200 = 1 1,200 Write the probability as a fraction. 11,2000.00083333 Use a calculator to change the fraction to a decimal. = 0.00083333Write the decimal as a percent. 0.083% Round to the nearest thousandth of a percent. 6-9

3 In a survey of the class, 13% of the students prefer vanilla, 27% prefer chocolate, 10% prefer strawberry, and the rest chose other flavors of ice cream. Find the probability that a student randomly selected from the class chose vanilla or chocolate. Probability COURSE 3 LESSON 6-9 13% of the students chose vanilla, and 27% of the students chose chocolate. P(vanilla or chocolate) = P(vanilla) + P(chocolate) = 13% + 27%Substitute. = 40%Simplify. The probability that the student chose vanilla or chocolate is 40%. 6-9


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