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1 12.5 Molarity and Dilution Chapter 12 Solutions Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings
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2 Molarity (M) Molarity (M) is A concentration term for solutions. The moles of solute in 1 L solution. moles of solute liter of solution
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3 Preparing a 1.0 Molar Solution A 1.00 M NaCl solution is prepared By weighing out 58.5 g NaCl (1.00 mol) and Adding water to make 1.00 liter of solution. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings
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4 Add GPS Guide to Calculating Molarity Basic 2e p 394
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5 What is the molarity of 0.500 L NaOH solution if it contains 6.00 g NaOH? STEP 1 Given 6.00 g NaOH in 0.500 L solution Need molarity (mol/L) STEP 2 Plan g NaOH mol NaOH molarity STEP 3 Conversion factors 1 mol NaOH = 40.00 g 1 mol NaOH and 40.00 g NaOH 40.00 g NaOH 1 mol NaOH Calculation of Molarity
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6 STEP 4 Calculate molarity. 6.00 g NaOH x 1 mol NaOH = 0.150 mol 40.00 g NaOH 0.150 mol = 0.300 mol = 0.300 M NaOH 0.500 L 1 L Calculation of Molarity (cont.)
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7 What is the molarity of 325 mL of a solution containing 46.8 g of NaHCO 3 ? 1) 0.557 M 2) 1.44 M 3) 1.71 M Learning Check
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8 3) 1.71 M 46.8 g NaHCO 3 x 1 mol NaHCO 3 = 0.557 mol NaHCO 3 84.01 g NaHCO 3 0.557 mol NaHCO 3 = 1.71 M NaHCO 3 0.325 L Solution
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9 What is the molarity of a solution if 225 mL contains 34.8 g KNO 3 ? 1)0.0775 M 2)1.53 M 3)15.5 M Learning Check
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10 2) 1.53 M 34.8 g KNO 3 x 1 mol KNO 3 = 0.344 mol KNO 3 101.11g KNO 3 M = mol = 0.344 mol KNO 3 = 1.53 M L 0.225 L In one setup 34.8 g KNO 3 x 1 mol KNO 3 x 1 = 1.53 M 101.11g KNO 3 0.225 L Solution
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11 Molarity Conversion Factors The units of molarity are used as conversion factors in calculations with solutions. Table 2.6 Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings
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12 Molarity in Calculations How many grams of KCl are needed to prepare 125 mL of a 0.720 M KCl solution? STEP 1 Given 125 mL (0.125 L) of 0.720 M KCl Need Grams of KCl STEP 2 Plan L KCl mol KCl g KCl
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13 Molarity in Calculations (cont.) STEP 3 Conversion factors 1 mol KCl = 74.55 g 1 mol KCl and 74.55 g KCl 74.55 g KCl 1 mol KCl 1 L KCl = 0.720 mol KCl 1 L and 0.720 mol KCl 0.720 mol KCl 1 L STEP 4 Calculate grams. 0.125 L x 0.720 mol KCl x 74.55 g KCl = 6.71 g KCl 1 L 1 mol KCl
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14 How many grams of AlCl 3 are needed to prepare 125 mL of a 0.150 M solution? 1) 20.0 g AlCl 3 2) 16.7g AlCl 3 3) 2.50 g AlCl 3 Learning Check
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15 Solution 3) 2.50 g AlCl 3 0.125 L x 0.150 mol x 133.3 g = 2.50 g AlCl 3 1 L 1 mol
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16 How many milliliters of 2.00 M HNO 3 contain 24.0 g HNO 3 ? 1) 12.0 mL 2) 83.3 mL 3) 190. mL Learning Check
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17 3) 190. mL 24.0 g HNO 3 x 1 mol HNO 3 x 1000 mL 63.02 g HNO 3 2.00 mol HNO 3 Molarity factor inverted = 190. mL HNO 3 Solution
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18 Dilution In a dilution Water is added. Volume increases. Concentration decreases. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings
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19 Comparing Initial and Diluted Solutions In the initial and diluted solution The moles of solute are the same. The concentrations and volumes are related by the equation M 1 V 1 = M 2 V 2 initial diluted
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20 Add GPS Guide to Calculating Dilution Quantities Basic 2e p 398
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21 Dilution Calculations What is the molarity if 0.180 L of 0.600 M KOH is diluted to a final volume of 0.540 L? STEP 1 Prepare a table: M 1 = 0.600 MV 1 = 0.180 L M 2 = ?V 2 = 0.540 L STEP 2 Solve dilution equation for unknown. M 1 V 1 = M 2 V 2 M 1 V 1 / V 2 = M 2 STEP 3 Set up and enter values: M 2 = M 1 V 1 = (0.600 M)(0.180 L) = 0.200 M V 2 0.540 L
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22 Learning Check What is the final volume if 15.0 mL of a 1.80 M KOH is diluted to give a 0.300 M solution? 1) 27.0 mL 2) 60.0 mL 3) 90.0 mL
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23 Solution STEP 1 Prepare a table: M 1 = 1.80 MV 1 = 15.0 mL M 2 = 0.300MV 2 = ? STEP 2 Solve dilution equation for unknown. M 1 V 1 = M 2 V 2 V 2 = M 1 V 1 / M 2 STEP 3 Set up and enter values: V 2 = M 1 V 1 = (1.80 M)(15.0 mL) = 90.0 mL M 2 0.300 M
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