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Good mornin’ Lot’s of things to pick up today: Quiz Scantron Quiz version that you took Lab Sheet Final Study Guide Dry Erase Board Marker 10 minutes to look over missed quiz questions & answer the Catalyst
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pH Test Tube[H+] (mol/L)pH 10.01<4 20.001<4 30.00014 40.000015 50.0000016 How does the molarity of H+ change? How does the pH change? Why are the pH’s for test tubes 1 and 2 indicated as “<4”? What is an Arrhenius acid? What is an Arrhenius base? What is a Bronsted-Loewry acid? What is a Bronsted-Loewry base?
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Example Brønsted Acids and Bases: Here, H 2 O acts as a Brønsted acid by donating a proton to NH 3 which acts as a Brønsted base. Conjugate base and conjugate acid? NH 3 + HOH NH 4 + + OH -
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pH pH is a scale used to reflect the concentration of H+ ions! Acids and bases are aqueous solutions Water can act as an acid and a base: HOH H + + OH - Why is water neutral? Acids dissociate and increase the number of protons (H+) in solution Bases dissociate and increase the number of hydroxide (OH-) in solution either directly (Arrhenius) or indirectly (Bronsted-Loewry)
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Neutralization Reaction Remember that this is just an acid base reaction What would a product of a neutralization reaction be? Just like the stoichiometry you’ve been doing, in lab we can use this fact to calculate the molarity of solution whose concentration is unknown
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Titration Definition ◦ Analytical method in which a standard solution is used to determine the concentration of an unknown solution. standard solution unknown solution Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
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Buret stopcock Erlenmeyer flask
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Titration Vocabulary Titrant ◦ The substance added to the analyte in a titration (a standard solution) Analyte ◦ The substance being analyzed Equivalence point ◦ The point in a titration at which the quantity of titrant is exactly sufficient for stoichiometric reaction with the analyte.
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Acid-Base Titration Titrant Analyte If the concentration of the titrant is known, then the unknown concentration of the analyte can be determined.
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Buret Reading
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Why do chemists use titrations?? Quantitative analysis — used to determine the amounts or concentrations of substances present in a sample by using a combination of chemical reactions and stoichiometric calculations
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Acidic, basic, or neutral??
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The “perfect pink” for a titration with phenolphthalein
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Indicator - changes color to indicate pH change Volume base added Example… phenolphthalein is colorless in acid and pink in basic solution pH Endpoint = 7 pink point at which exactly enough reactant has been added for the solution to be neutralized and no more
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Equivalence point (endpoint) Point at which equal amounts of H 3 O + and OH - are present in solution. Determined by… indicator color change dramatic change in pH Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
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Titration moles H 3 O + = moles OH - Courtesy Christy Johannesson www.nisd.net/communicationsarts/pages/chem
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White Board Review! Solubility Molarity Dilutions Solutions Stoichiometry Acid and Base
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Problem #1 What mass of (NH 4 ) 2 SO 4 is required to make 1.25 L of a 0.250 M solution of NH 4 + ? Answer: 20.6 g (mm=132.14g/mol)
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Problem #2 If 25 g of KCl is added to 50 g of water at 40°C, the solution would be: 1) Unsaturated 2) Saturated 3) Supersaturated
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Problem #3 Calculate the molarity of a solution prepared by dissolving 4.1 g of solid KBr in enough water to make 1.10 L of solution Answer: 0.031 M (mm=119.02 g/mol)
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Problem #4 One way to determine the amount of chloride ion in a a water sample is to titrate the sample of standard AgNO 3 solution to produce solid AgCl. Ag + (aq) + Cl - (aq) AgCl(s) If a 25.0 mL water sample requires 27.2 mL of 0.104 M AgNO 3 in such a titration, what is the concentration of Cl - in the sample? Answer: 0.113 M
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Problem #5 What volume of of a a 5.00M Ca(NO 3 ) 2 solution is needed to prepare 465 mL of a 0.250 M Ca(NO 3 ) 2 solution? Answer: 23.3 mL
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Problem #6 Calculate the mass of sodium iodide that must be added to 425.0 mL of a 0.100 M lead (II) nitrate solution to precipitate all of the lead (II) ions as lead (II) iodide. Answer: 12.7 g NaI
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