1. In the Name Of Allah DSS Lab 04 Solving Problems 1Tahani ALdweesh

2. Objectives Using Excel’s Solver to solve LP problems. Exercise. 2Tahani ALdweesh

3. Steps to solve (LP) Step 1: formulate the LP on paper Step 2: set up the problem in Excel Step 3: Add the solver add-in Step 4: Set up the Solver 3Tahani ALdweesh

4. Problem 1 The Blendex Oil Company blends a regular and premium product from two ingredients, heptane and octane. Each liter of regular is composed of exactly 50% heptane and 50% octane. Each liter of premium is composed of exactly 40% heptane and 60% octane. During this planning period there are exactly 200,000 liters of heptane and 310,000 liters of octane available. The profit contributions per liter of the regular and premium product are $0.03 and $0.04 per liter respectively. 4Tahani ALdweesh

5. Cont -The Blendex Oil Company blends a regular and premium product from two ingredients, heptane and octane. - Each liter of regular is composed of exactly : 50% heptane and 50% octane. - Each liter of premium is composed of exactly: 40% heptane and 60% octane. - there are exactly: 200,000 liters of heptane and 310,000 liters of octane available. - The profit contributions per liter of the regular and premium product are: $0.03 and $0.04 per liter respectively. 5Tahani ALdweesh

6. Step 1: formulate the LP on paper In this step we need to determine : 1-Decision Variables: HR = liters of heptane used to produce regular gasoline. OR = liters of octane used to produce regular gasoline HP = liters of heptane used to produce premium gasoline. OP = liters of octane used to produce premium gasoline 6Tahani ALdweesh

7. 2-Objective function: to maximize the total contribution from selling both types of gasoline: Max = 0.03 * (HR + OR) + 0.04 * (HP + OP) 7Tahani ALdweesh RegularPremium

8. 3-Constraints : A) - Each liter of regular must have exactly : 50% heptane and 50% octane: (50/100 )HR - (50/100 )OR 0.5 HR – 0.5 OR = 0 B)- Each liter of premium must have exactly: 40% heptane and 60% octane: (40/100 )HP - (60/100 )OP 0.6 HP – 0.4 OP = 0 8Tahani ALdweesh

9. C)- There is exactly 200,000 liters of heptane: HR + HP <= 200,000 D)- There is exactly 310,000 liters of octane: OR + OP <= 310,000 9Tahani ALdweesh

10. Step 2: set up the problem in Excel 10Tahani ALdweesh

11. Decision Variable 11Tahani ALdweesh Decision Variable

12. Constraints 12Tahani ALdweesh HR + HP <= 200,000 OR + OP <= 310,000

13. Constraints : Cont 13Tahani ALdweesh 0.5 HR – 0.5 OR = 0 0.6 HP – 0.4 OP = 0 0.5HR 0.6HP 0.4OP 0.5 OR 0.5HR – 0.5 OR0.6 HP – 0.4 OP

14. Max = 0.03 * (HR + OR) + 0.04 * (HP + OP) 14Tahani ALdweesh HR+OR 0.04*(HP+OP)0.03*(HR+OR) أ HP+OP Max

15. Step 3 : Add Solver Tahani ALdweesh15

16. Solution Tahani ALdweesh16

17. Problem 2 ( Exercise ) Tahani ALdweesh17 How many pounds of oat and corn should be fed to each cattle per day to minimize feed cost ?

18. Any Question Tahani ALdweesh18

19. Tahani ALdweesh19