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Comparing Measures of a Triangle There is a relationship between the positions of the longest and shortest sides of a triangle and the positions of its angles. longest side largest angle smallest angle shortest side
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If one angle of a triangle is larger than another angle, then the side opposite the larger angle is longer than the side opposite the smaller angle. 60 ˚ DE F 40 ˚ Theorem 5.11 EF > DF Theorem 5.10 If one side of a triangle is longer than another side, then the angle opposite the longer side is larger than the angle opposite the shorter side. 3 5 A B C m A > m C Comparing Measures of a Triangle There is a relationship between the positions of the longest and shortest sides of a triangle and the positions of its angles. THEOREMS
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Writing Measurements in Order from Least to Greatest Write the measurements of the triangles in order from least to greatest. 100 ˚ H J G 45 ˚ 35 ˚ SOLUTION mGmG< m J JH< GH < m H < JG
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Writing Measurements in Order from Least to Greatest Write the measurements of the triangles in order from least to greatest. 100 ˚ H J G 45 ˚ 35 ˚ SOLUTION mGmG< m J JH< GH < m H < JG 8 5 Q R P 7 QP< QR m Rm R< m P SOLUTION < PR < m Q
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Theorem 5.10 can be proved using the diagram shown below. A C B Given Prove AC > AB Paragraph Proof m ABC > m C Substituting m 2 for m 1 produces m ABC > m 2. Because m 2 = m 3 + m C, m 2 > m C. Finally, because m ABC > m 2 and m 2 > m C, you can conclude that m ABC > m C. In the isosceles triangle ABD, 1 2. Because m ABC = m 1 + m 3, it follows that m ABC > m 1. D 1 2 3 Use the Ruler Postulate to locate a point D on AC such that DA = BA. Then draw the segment BD. Comparing Measurements of a Triangle
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The proof of Theorem 5.10 used an exterior angle and showed that its measure is the sum of the measures of two nonadjacent interior angles. Then the measure of the exterior angle must be greater than the measure of either nonadjacent interior angle. THEOREM Theorem 5.12 Exterior Angle Inequality The measure of an exterior angle of a triangle is greater than the measure of either of the two nonadjacent interior angles. A B C 1 m 1 > m A and m 1 > m B
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Using Theorem 5.10 SOLUTION Therefore, m B = m C. Because BC > AB, m A > m C by Theorem 5.10. By substitution, m A > m B. In addition, you can conclude that m A > 60 ˚, m B < 60 ˚, and m C < 60 ˚. Because AB AC, ABC is isosceles, so B C. DIRECTOR’S CHAIR In the director’s chair shown, AB AC and BC > AB. What can you conclude about the angles in ABC?
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Using the Triangle Inequality Not every group of three segments can be used to form a triangle. The lengths of the segments must fit a certain relationship. Construct a triangle with the given group of side lengths, if possible. 2 cm, 2 cm, 5 cm SOLUTION Try drawing triangles with the given side lengths. Impossible
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Using the Triangle Inequality Not every group of three segments can be used to form a triangle. The lengths of the segments must fit a certain relationship. Construct a triangle with the given group of side lengths, if possible. 2 cm, 2 cm, 5 cm SOLUTION Try drawing triangles with the given side lengths. Impossible 3 cm, 2 cm, 5 cm Impossible
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Using the Triangle Inequality Not every group of three segments can be used to form a triangle. The lengths of the segments must fit a certain relationship. Construct a triangle with the given group of side lengths, if possible. 2 cm, 2 cm, 5 cm SOLUTION Try drawing triangles with the given side lengths. Impossible 3 cm, 2 cm, 5 cm Impossible 4 cm, 2 cm, 5 cm Only the last group is possible. The sum of the first and second lengths must be greater than the third length.
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Using the Triangle Inequality The result of the previous example is summarized as Theorem 5.13. THEOREM Theorem 5.13 Triangle Inequality The sum of the lengths of any two sides of a triangle is greater than the length of the third side. C A B AB + BC > AC AC + BC > AB AB + BC > BC
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Finding Possible Side Lengths A triangle has one side of 10 centimeters and another of 14 centimeters. Describe the possible lengths of the third side. SOLUTION Let x represent the length of the third side. Using the Triangle Inequality, you can write and solve inequalities. x + 10 > 14 x > 4 10 + 14 > x 24 > x So, the length of the third side must be greater than 4 centimeters and less than 24 centimeters.
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