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Roots of Complex Numbers Sec. 6.6c HW: p. 558 39-59 odd
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From last class: The complex number is a third root of –8 The complex number is an eighth root of 1
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Definition A complex number v = a + bi is an nth root of z if v = z n If z = 1, then v is an nth root of unity.
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Finding nth Roots of a Complex Number If, then the n distinct complex numbers where k = 0, 1, 2,…, n – 1, are the nth roots of the complex number z.
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Let’s now do an example… Find the fourth roots of Use the new formula, with r = 5, n = 4, k = 0 – 3, k = 0:
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fourth root continued… Find the fourth roots of Use the new formula, with r = 5, n = 4, k = 0 – 3, k = 1:
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fourth root continued… Find the fourth roots of Use the new formula, with r = 5, n = 4, k = 0 – 3, k = 2:
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fourth root done! Find the fourth roots of Use the new formula, with r = 5, n = 4, k = 0 – 3, k = 3: How would we verify these algebraically???
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A new example… Find the cube roots of –1 and plot them. First, rewrite the complex number in trig. form: Use the new formula, with r = 1, n = 3, k = 0 – 2,
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third root continued… Find the cube roots of –1 and plot them. First, rewrite the complex number in trig. form: Use the new formula, with r = 1, n = 3, k = 0 – 2,
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third root continued… Find the cube roots of –1 and plot them. First, rewrite the complex number in trig. form: Use the new formula, with r = 1, n = 3, k = 0 – 2,
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third root done! Find the cube roots of –1 and plot them. Now, how do we sketch the graph??? First, rewrite the complex number in trig. form: Use the new formula, with r = 1, n = 3, k = 0 – 2, The cube roots of –1
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