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7. Relativity Wave Equations and Field Theories 7.1. The Klein-Gordon Equation 7.2. Scalar Field Theory for Free Particles 7.3. The Dirac Equation and spin-1/2 Particles 7.4. Spinor Field Theory 7.5. Weyl and Marjorana Spinors 7.6. Particles of Spin 1 and 2 7.7. Wave Equations in Curved Spacetime
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Natural Units c = 1→[ L ] = [ T ] = 1→[ E ] = [ T ] 1 Choosing [ E ] = MeV, we have [ M ] = [ P ] = [ E ] = MeV [ L ] = [ T ] = [ E ] 1 = (MeV) 1 c = 2.997 10 8 m/s h = 6.582 10 22 MeV s 1 MeV = 1.602 10 13 J → T( s ) = 6.582 10 22 T( MeV 1 ) L( m ) = 1.937 10 13 L( MeV 1 ) M( kg ) = 1.783 10 30 M( MeV )
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7.1. The Klein-Gordon Equation → Klein-Gordon equation D’Alembertian μ μ is a Lorentz scalar → must be a Lorentz tensor Only case = scalar considered.
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Conserved Current Density Statistical interpretation of quantum mechanics requires existence of a conserved probability density . 4-current density: Equation of continuity: → is conserved. However, j μ cannot be the 4-current probability density because is not positive definite.
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Plane Wave Solutions Plane wave with 4-wavevector k = (k 0, k ): → ϕ is a solution to the K-G eq only if → energy of the particle is E < 0 solutions are unphysical since the vaccuum is at E = 0. If E < 0 solutions are allowed, ground state is E → . However, E < 0 solutions are needed to form a complete set of basis functions. These problems are resolved through the concept of anti-particles.
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Precursor to a Quantum Field Problems of the K-G eq can be fully resolved only by switching to QFT. Consistent 1-particle relativistic quantum theory does not exist ( particle- antiparticle pairs always emerge spontaneously at sufficiently high E ) Action for the K-G eq: Conjugate momenta : General solution:
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where
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The following aims to find a and c : (a) (b) Add: Subtract:
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7.2. Scalar Field Theory for Free Particles Scalar field → particles are bosons. Quantization is expressed by equal-time commutators : c kills anti-particle of E > 0.
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Covariant Normalization changes the normalization of the 1-P eigenstates. Factor (2π) 3 2ω k in where For a system with exactly one “particle”, the states { | k } are complete : | k is a free particle state →
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→→ transforms like k 0 is a Lorentz covariant normalization.
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Hamiltonian Ignoring the possible ambiguity that may arise from we write
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→ Vacuum energy:
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Normal Ordering Determination of structure of spacetime by matter distribution requires E 0 = 0. This is accomplished by writing H in normal ordering : … :, which means all creation operators are to the left of all annihilation operators. The technique should be applied to all “total” operators. Total number operator: j 0 is the net probability density so that net number of “particles” is conserved Some neutral particles are identical to their anti-particles, e.g., γ, π 0 … → Number of γ is not conserved ( necessary if they’re the quanta of EM fields )
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Summary
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7.3. The Dirac Equation and spin-1/2 Particles K-G eq. is 2 nd order in t partials → E < 0 solutions. Remedy: find eq. that’s 1 st order in t partials. Dirac’s choice: Correct 4-momentum → must satisfy the K-G eq. → → Set of all linear combinations of is called a Dirac algebra. It is a special case C(V 4 (1) ) of the Clifford algebra C(V n (s) ) [see Choquet]. E.g., C(V 1 (0) ) = C, C(V 2 (0) ) = quarternions, C(V 3 (3) ) = Pauli algebra
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Standard representation: Pauli matrices: For j = ½, Angular momenta commutator Pauli algebra Spin ½ Dirac eq.:
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Lorentz Covariance and Spin Transformation of the Matrices : Dirac eq. is Lorentz covariant if is a scalar. are 4 4 matrices → must be a 4 1 matrix → covariance not automatic. Components of γ matrices: ( γ μ ) αβ with μ = 0,1,2,3 and α, β = 1,2,3,4. Lorentz transformation: Covariance → → →→ spinor
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The Matrix S Infinitesimal transformation: ( No need to distinguish primed and unprimed indices in since such information does not appear explicitly in S. ) → ( μ → λ )
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→ → → Simplest ansatz: →
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Generators Scalar : Infinitesimal (inverse) Lorentz transformation:
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Spinor : → ½ (4 2 4) = 6 independent components Divided into 2 groups :
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Spin ω 0 j ~ boost → K j = generator of boost along j-axis. ω i j ~ rotation→ J i = rotation generator in the j-k plane ( i j k cyclic ) →
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→ J = total angular momentum, L = orbital angular momentum → = spin ( ½)
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Pauli-Lubanski 4-Vector A simple 4-vector description of the spin is the Pauli-Lubanski 4-vector since W μ is a pseudovector since ε μνλσ is a tensor density of weight +1.
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Caution: T iμ a μ is the ith component of a 4-vector, but T i j a j is not. → has no tensorial meaning in Minkowski space. → Let a μ be a 4-vector with spatial part Then W 2 = W μ W μ is invariant → it can be evaluated in any convenient coordinate system. Consider W 2 acting on the rest frame of a plane wave with k μ = ( m, 0 ). → → is the spin operator in the rest frame of the particle with eigenvalue s(s + 1).
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Some Properties of the γ Matrices → → → → →
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for Define( not a Lorentz invariant since γ is not a 4-vector ) Dirac equation: Pauli-Lubanski 4-vector: where Ex 7.6
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Conjugate Wavefunction and the Dirac Action → → Conjugate wavefunction Conjugate eq. Dirac action
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Probability Current →→ γ μ is not a 4-vector → need to show j μ is.
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→ 4-vector. ~ probability density
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Bilinear Covariants ( Tensors ) Tensor TypeBilinearsTransformation Scalar Pseudoscalar Vector Pseudovector Tensor Dirac algebra is spanned by 16 basis “numbers”, e.g., I, γ 5, γ μ, γ μ γ 5, σ μν.
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Covariant Spin Polarization Spin 1/2 particle in its rest frame: n = unit vector along axis of spin polarization. → In a frame in which the particle is moving with momentum p = k, Since we have →
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By symmetry, n can involve only n and k → Square: →→ b = +1 since n = n when k = 0. → Rest frame: →
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Plane Wave Solutions Free particle (plane wave) solution:spinor → → → → → → →
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Dirac equation :
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Interpretation Rest frame: Choose u ks and v ks to be the eigenstates of the spin Σ n : → where Frame p μ = k μ : →
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Charge Conjugation Charge conjugation : particle ↔ antiparticle Principle of minimal coupling : Charge conjugation: → C Conjugate equation → Set→ Standard representations → Exercise:
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Massless Spin 1/2 Particles Dirac equation for massless particle: No rest frame → spin polarization specified by helicity Massless particle: → Plane wave is eigenfunction of W if it is an eigenfunction of γ 5. →
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If is a plane wave with wavevector k μ, then R and L are eigenfunctions of W with eigenvalue ½ k μ and ½ k μ, resp. m = 0 → → chiral projections γ 5 = chirality operator Only for massless particles do the chiral projections have definite helicities.
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7.4. Spinor Field Theory Dirac eq: ρ 0 but k 0 = ω k → 2 nd quantization needed for proper interpretation. Dirac action: Momentum conjugate to i : Hamiltonian density : Hamiltonian :
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2nd Quantization Normalization: → → → → Ex 7.4
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Non-negativeness of H requires anticommutation relations: Using commutation relations leads to causality violation (operators with space-like separation would not commute) removed by normal ordering.with
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Field Operator Version Spatial parts of the Dirac wavefunctions should be anticommutating. ( Not positive-definite )
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7.5. Weyl and Marjorana Spinors Weyl (Chiral) Representation ( for Massless Particles ) : →
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Chiral Solutions Weyl representation: m = 0 → ( u and v are linearly dependent ) → E.g., k = ( 0,0,k )
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General k → Writing we have Simplest solution: → → c = normalization constant.
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Normalization For c real,
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→
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→
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Setting → orthonormality
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Charge Conjugation The chiral solution are also related by charge conjugation:
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2 nd Quantization Matrix form:Weyl representation: Dirac equation:
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→
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Weyl Spinors From Ex.7.9: m = 0 → Action: ( R and L decoupled ) → Either R or L alone describes a self-consistent theory. Spinors in this reduced theory are called Weyl spinors. E.g., in a theory involving only L, the operators are → there are only left-handed particles and right-handed antiparticles. For a theory involving only R, the opposite is true. Both theories are entirely equivalent, physically as well as mathematically.
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Majorana Spinors A spin ½ particle which is its own anti-particle can access only 2 of the 4 spinor states allowed by the Dirac equation. The field operator M for such a particle is called a Majorana spinor. By definition If the particle is also massless, we have →→ → A, B R, L Proof ?
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For non-interacting massless particles, Weyl & Majorana spinors are equivalent. E.g. Corresponding action: This equivalence is broken in the presence of interactions.
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7.6. Particles of Spin 1 and 2 Maxwell equations in a source-free region: → Proca equation: → → ( Klein-Gordon eq for A μ ) Consider the gauge transformation: Settinggives In this context, is called the Lorentz condition. A μ is said to be in the Lorentz gauge.
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Spin Lorentz transformation: or Comparing withgives Hence, the “spin” part of the infinitesimal generators M are simply the generators of the Lorentz transformation on x . The spin part of K i ( i ) denotes a boost (rotation):
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Plane wave solution: polarization vector ε μ is a column matrix Lorentz condition → → For a massive particle, k μ = ( m, 0 ) in the rest frame. The Pauli- Lubanski vector becomes → →→
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Secular equations for all three matrices i are the same, i.e., so that The corresponding (orthonormalized) eigenvectors for 3 are ε 0 is not an acceptable solution since ( Lorentz condition violated ) form a basis for the polarization of the spin 1 particle. Wrt this basis, Σ Σ is effectively a unit matrix.
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For massless particles → → The last condition is satisfied by → polarization ε L is longitudinal → corresponding plane wave is pure gauge ( ~ A μ = 0 ) → photon has only 2 polarizations h = 1 → complications in quantization scheme → path integral
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Gravitons Source free regions : Field eq. → To 1 st order in h (x) : Field eq. →
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Gauge Invariance g symmetric → at most 10 independent components in h . 2 different h are equivalent if they lead to the same g in different coordinates. i.e., (gauge) transformations on g that leave all physical properties unchanged. Gauge invariance further reduces number of independent components of h . Infinitesimal coordinate transformation:
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Set To 1 st order terms in both h and , gauge transformation
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Harmonic Gauge Condition Field eq. where → Gauge transformation:
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→harmonic gauge condition → to 1 st order in h in harmonic gauge Field eq. →( massless K-G eq ) → graviton is massless ~ 0
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Spin Field eq. Plane wave solution: is a symmetric polarization tensor (at most 10 independent components) In the harmonic gauge, → Gauge condition → 4 constraints on for transformation between harmonic gauges → E.g. with
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→ → Writing further reduce the number of independent components of to 2. ~ helicity states of h = 2. → Gravition is massless, spin 2. Helicity states of h = 0, 1 correspond to purely gauge degrees of freedom and have no physical significance. Experimental proof of gravitational waves : binary pulsar No graviton has yet been detected.
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7.7. Wave Equations in Curved Spacetime Scalar Field = dimensionless coupling constant, R(x) = Ricci curvature scalar, Λ = 0. L field is the only choice that allows a dimensionless coupling constant. Note: but
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Euler-Lagrange equations For the degrees of freedom: Covariant Gauss’ theorem [see eq(A.23), appendix A.4] → Hence, the covariant Euler-Lagrange equations are → δ = 0 on S
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→ → There is no known physical principle that can be used to determine . Effects of spacetime curvature are too small for measurement of . The arbitrary case ξ = 0 is called minimal coupling. Conformal transformation : (x) = arbitrary real function Conformal coupling: For ξ= 1/6 and m = 0, is invariant under a conformal transformation if
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Vierbeins Let y a be local coordinates at point X with large-scale coordinates x μ = X μ. Spacetime is locally flat → g(y) = η. Transformation matrices : Orthogonality: Local inertial frames should vary smoothly from point to point. → For a fixed, e μ a (x) is a vector field specifying the y a axis at every point x. is called a vierbein, a tetrad, or a frame field. Likewise
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Verbein e is a 2 nd rank tensor whose and a indices are associated with g (x) & ab. The 16 components of e carry 2 kinds of information. 10 components specifying g . 6 components specifying boost & rotation relating each local frame to a fixed reference Minkowkian frame. coordinate vector Lorentz vector
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Spin Connection Parallel transport of a Lorentz vector such as = spin connection →
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→ → → → (a) →
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Vierbein, like g, is invariant under parallel transport Reminder: e serves the role of g that converts between a and types of indices. → is the compatibility condition between ω & η. → magnitudes and angles be invariant under parallel transport: L.H.S. =→ To 1 st order in dx: →→ This can be shown to implyi.e., Γ = metric connection.
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Spinors Parallel transport of a spinor : → Ω = 4 4 spin matrix Scalar field: To 1 st order in dx : S is invariant →
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Lorentz vector : → →
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Consider ansatzfor → → → →
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→is automatically satisfied since ω is real →
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Dirac Equation μ are defined only for inertial frames → must be mediated by e. Covariant Dirac equation is Set→ ( Covariant Clifford / Dirac algebra ) Covariant action : There’s no field term because the coupling constant cannot be dimensionless. E.g., a term like requires to have the dimension of length.
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Vacuum State Problem Concept of the vacuum is problematic even in Minkowkian spacetime: The vacuum state, which by definition contains no particle to an inertial observer, will appear to an accelerating observer as a thermal bath of particles with temperature proportional to the acceleration. We’ll demonstrate it for the special case of a massless 2-D Hermitian scalar field. A complete proof of this statement is rather involved.
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Rindler Coordinates Massless spin 0 particles in a 2-D Minkowskian spacetime. Inertial frame: (t, x)Rindler coordinates: (η,ξ) α > 0 →→for x > 0Rindler wedge Inverse: →
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→ → For an observer at fixed . The eq of his worldline in an inertial frame is → His velocity in the inertial frame is His acceleration: →→
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Let inertial frame S be moving with velocity v with respect to S. Then If S coincides instantaneously with the rest frame of the particle, then v = u, ( see Ex.2.2 ) → a p is the proper acceleration of the observer. Proper time of the observer is obtained by setting dξ= 0. →→ With a proper choice of coordinate origins, we have
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2 D Massless Hermitian Scalar Field (x, t) Klein-Gordon equation inside the Rindler wedge : Plane wave solution : →
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Expanding in terms of k (ξ,η), → Caution: b k and b k + are confined in the Rindler wedge but not a q and a q +. In general, transformation that relates different sets of solutions to a wave equation is called a Bogoliubov transformation.
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Average Particle Numbers | 0 = vacumm state in Minkowskian spacetime → = number of particles with momentum between k and k+dk as seen by a Rindler observer. Problem: If volume → , then N(k,k) → even if the density of particles is finite. Remedy: Use N(k,k) then take limit k → k. Involved manipulation →
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= Bose-Einstein occupation number with Consider the observer at fixed = ξ 0. His proper time is A positive energy plane wave is which represents a particle with energy → → QED
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